Learn on PengiBig Ideas Math, Algebra 1Chapter 5: Solving Systems of Linear Equations

Lesson 6: Graphing Linear Inequalities in Two Variables

Property A linear inequality is an inequality that can be written in one of the following forms: $$Ax + By C \quad Ax + By \geq C \quad Ax + By < C \quad Ax + By \leq C$$ Where $A$ and $B$ are not both zero.

Section 1

Linear Inequality

Property

A linear inequality is an inequality that can be written in one of the following forms:

Ax+By>CAx+ByCAx+By<CAx+ByCAx + By > C \quad Ax + By \geq C \quad Ax + By < C \quad Ax + By \leq C

Where AA and BB are not both zero.

Examples

  • An ordered pair (x,y)(x, y) is a solution if it makes the inequality true. For y>x+4y > x + 4, the point (1,6)(1, 6) is a solution because 6>1+46 > 1 + 4 is true.
  • For the same inequality y>x+4y > x + 4, the point (2,6)(2, 6) is not a solution because 6>2+46 > 2 + 4 simplifies to 6>66 > 6, which is false.

Section 2

Solution of a Linear Inequality

Property

An ordered pair (x,y)(x, y) is a solution of a linear inequality if the inequality is true when we substitute the values of xx and yy.

Examples

  • To check if (1,4)(1, 4) is a solution to y>3x1y > 3x - 1, substitute: 4>3(1)14 > 3(1) - 1 becomes 4>24 > 2. This is true, so (1,4)(1, 4) is a solution.
  • To check if (2,1)(2, -1) is a solution to 2x+y32x + y \leq 3, substitute: 2(2)+(1)32(2) + (-1) \leq 3 becomes 333 \leq 3. This is true, so (2,1)(2, -1) is a solution.
  • To check if (0,0)(0, 0) is a solution to x5y>1x - 5y > 1, substitute: 05(0)>10 - 5(0) > 1 becomes 0>10 > 1. This is false, so (0,0)(0, 0) is not a solution.

Explanation

A solution is any point (x,y)(x, y) that makes the inequality true. Unlike equations that have solutions on a line, inequalities have solutions in a whole shaded region. Any point in that region works!

Section 3

Graphing a Linear Inequality

Property

To graph a linear inequality, follow these steps:

  1. Identify and graph the boundary line. Use a solid line for \leq or \geq, and a dashed line for << or >>.
  2. Test a point that is not on the boundary line to see if it is a solution.
  3. If the test point is a solution, shade the side of the line that includes it. If not, shade the opposite side.

Examples

  • To graph y>2x1y > 2x - 1: Draw a dashed line for y=2x1y = 2x - 1. Test (0,0)(0,0): 0>10 > -1 is true. Shade the side containing (0,0)(0,0).
  • To graph x+3y6x + 3y \leq 6: Draw a solid line for x+3y=6x + 3y = 6. Test (0,0)(0,0): 060 \leq 6 is true. Shade the side containing (0,0)(0,0).
  • To graph x<2x < -2: Draw a dashed vertical line at x=2x = -2. Test (0,0)(0,0): 0<20 < -2 is false. Shade the side that does not contain (0,0)(0,0), which is the left side.

Explanation

Graphing an inequality is a three-step process: draw the boundary line (solid or dashed), pick a test point (like (0,0)(0,0)) to see which side is true, and then shade that entire region to show all possible solutions.

Book overview

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Chapter 5: Solving Systems of Linear Equations

  1. Lesson 1

    Lesson 1: Solving Systems of Linear Equations by Graphing

  2. Lesson 2

    Lesson 2: Solving Systems of Linear Equations by Substitution

  3. Lesson 3

    Lesson 3: Solving Systems of Linear Equations by Elimination

  4. Lesson 4

    Lesson 4: Solving Special Systems of Linear Equations

  5. Lesson 5

    Lesson 5: Solving Equations by Graphing

  6. Lesson 6Current

    Lesson 6: Graphing Linear Inequalities in Two Variables

  7. Lesson 7

    Lesson 7: Systems of Linear Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Linear Inequality

Property

A linear inequality is an inequality that can be written in one of the following forms:

Ax+By>CAx+ByCAx+By<CAx+ByCAx + By > C \quad Ax + By \geq C \quad Ax + By < C \quad Ax + By \leq C

Where AA and BB are not both zero.

Examples

  • An ordered pair (x,y)(x, y) is a solution if it makes the inequality true. For y>x+4y > x + 4, the point (1,6)(1, 6) is a solution because 6>1+46 > 1 + 4 is true.
  • For the same inequality y>x+4y > x + 4, the point (2,6)(2, 6) is not a solution because 6>2+46 > 2 + 4 simplifies to 6>66 > 6, which is false.

Section 2

Solution of a Linear Inequality

Property

An ordered pair (x,y)(x, y) is a solution of a linear inequality if the inequality is true when we substitute the values of xx and yy.

Examples

  • To check if (1,4)(1, 4) is a solution to y>3x1y > 3x - 1, substitute: 4>3(1)14 > 3(1) - 1 becomes 4>24 > 2. This is true, so (1,4)(1, 4) is a solution.
  • To check if (2,1)(2, -1) is a solution to 2x+y32x + y \leq 3, substitute: 2(2)+(1)32(2) + (-1) \leq 3 becomes 333 \leq 3. This is true, so (2,1)(2, -1) is a solution.
  • To check if (0,0)(0, 0) is a solution to x5y>1x - 5y > 1, substitute: 05(0)>10 - 5(0) > 1 becomes 0>10 > 1. This is false, so (0,0)(0, 0) is not a solution.

Explanation

A solution is any point (x,y)(x, y) that makes the inequality true. Unlike equations that have solutions on a line, inequalities have solutions in a whole shaded region. Any point in that region works!

Section 3

Graphing a Linear Inequality

Property

To graph a linear inequality, follow these steps:

  1. Identify and graph the boundary line. Use a solid line for \leq or \geq, and a dashed line for << or >>.
  2. Test a point that is not on the boundary line to see if it is a solution.
  3. If the test point is a solution, shade the side of the line that includes it. If not, shade the opposite side.

Examples

  • To graph y>2x1y > 2x - 1: Draw a dashed line for y=2x1y = 2x - 1. Test (0,0)(0,0): 0>10 > -1 is true. Shade the side containing (0,0)(0,0).
  • To graph x+3y6x + 3y \leq 6: Draw a solid line for x+3y=6x + 3y = 6. Test (0,0)(0,0): 060 \leq 6 is true. Shade the side containing (0,0)(0,0).
  • To graph x<2x < -2: Draw a dashed vertical line at x=2x = -2. Test (0,0)(0,0): 0<20 < -2 is false. Shade the side that does not contain (0,0)(0,0), which is the left side.

Explanation

Graphing an inequality is a three-step process: draw the boundary line (solid or dashed), pick a test point (like (0,0)(0,0)) to see which side is true, and then shade that entire region to show all possible solutions.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Solving Systems of Linear Equations

  1. Lesson 1

    Lesson 1: Solving Systems of Linear Equations by Graphing

  2. Lesson 2

    Lesson 2: Solving Systems of Linear Equations by Substitution

  3. Lesson 3

    Lesson 3: Solving Systems of Linear Equations by Elimination

  4. Lesson 4

    Lesson 4: Solving Special Systems of Linear Equations

  5. Lesson 5

    Lesson 5: Solving Equations by Graphing

  6. Lesson 6Current

    Lesson 6: Graphing Linear Inequalities in Two Variables

  7. Lesson 7

    Lesson 7: Systems of Linear Inequalities