Learn on PengiYoshiwara Intermediate AlgebraChapter 2: Applications of Linear Models

Lesson 6: Chapter Summary and Review

In this Grade 7 chapter summary from Yoshiwara Intermediate Algebra, students review the core concepts of Chapter 2, including regression lines, interpolation and extrapolation, and methods for solving 2×2 and 3×3 linear systems using substitution, elimination, and Gaussian reduction. Students also consolidate their understanding of graphing linear inequalities using test points and half-planes, as well as solving systems of inequalities by identifying the intersection of shaded regions. The review problems apply these skills to real-world scenarios involving scatterplots, equilibrium price, and constraint-based optimization.

Section 1

📘 Applications of Linear Models

New Concept

This chapter unites your skills with linear models. You will apply systems of linear equations and inequalities to analyze data, make predictions, and solve complex real-world problems involving multiple variables and constraints.

What’s next

You'll now work through a set of review problems and interactive examples, challenging you to apply every method from this chapter.

Section 2

Regression line and predictions

Property

We can approximate a linear pattern in a scatterplot using a regression line.

We can use interpolation or extrapolation to make estimates and predictions.

If we extrapolate too far beyond the known data, we may get unreasonable results.

Section 3

Solutions of 2x2 linear systems

Property

A solution to a 2×22 \times 2 linear system is an ordered pair that satisfies both equations.

A solution to a 2×22 \times 2 linear system is a point where the two graphs intersect.

The substitution method is easier if one of the variables in one of the equations has a coefficient of 1 or -1.

Section 4

Inconsistent and dependent systems

Property

The graphs of the equations in an inconsistent system are parallel lines and hence do not intersect.

The graphs of the two equations in a dependent system are the same line.

If a linear combination of the equations in a system results in an equation of the form

0x+0y=k(k0)0x + 0y = k \quad (k \neq 0)

then the system is inconsistent. If an equation of the form

0x+0y=00x + 0y = 0

results, then the system is dependent.

Section 5

Graphing linear inequalities

Property

The solutions of the linear inequality

ax+by+c0orax+by+c0ax + by + c \leq 0 \quad \text{or} \quad ax + by + c \geq 0

consists of the line ax+by+c=0ax + by + c = 0 and a half-plane on one side of that line.

To Graph an Inequality Using a Test Point.

  1. Graph the corresponding equation to obtain the boundary line.
  2. Choose a test point that does not lie on the boundary line.
  3. Substitute the coordinates of the test point into the inequality.

a. If the resulting statement is true, shade the half-plane that includes the test point.
b. If the resulting statement is false, shade the half-plane that does not include the test point.

  1. If the inequality is strict, make the boundary line a dashed line.

Examples

  • To graph 3x4y<123x - 4y < 12, first draw the boundary line 3x4y=123x - 4y = 12 as a dashed line. Test the point (0,0)(0,0): 3(0)4(0)<123(0) - 4(0) < 12 is true, so shade the half-plane that contains the origin.

Section 6

Solving 3x3 linear systems

Property

A solution to an equation in three variables is an ordered triple of numbers that satisfies the equation.

To solve a 3×33 \times 3 linear system, we use linear combinations to reduce the system to triangular form, and then use back-substitution to find the solutions.

Examples

  • For the system x+z=5x+z=5, yz=8y-z=-8, and 2x+z=72x+z=7, first subtract the top equation from the bottom one to get x=2x=2. Substitute x=2x=2 into x+z=5x+z=5 to find z=3z=3. Finally, use z=3z=3 in yz=8y-z=-8 to find y=5y=-5. The solution is (2,5,3)(2, -5, 3).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Applications of Linear Models

  1. Lesson 1

    Lesson 1: Linear Regression

  2. Lesson 2

    Lesson 2: Linear Systems

  3. Lesson 3

    Lesson 3: Algebraic Solution of Systems

  4. Lesson 4

    Lesson 4: Gaussian Reduction

  5. Lesson 5

    Lesson 5: Linear Inequalities in Two Variables

  6. Lesson 6Current

    Lesson 6: Chapter Summary and Review

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Applications of Linear Models

New Concept

This chapter unites your skills with linear models. You will apply systems of linear equations and inequalities to analyze data, make predictions, and solve complex real-world problems involving multiple variables and constraints.

What’s next

You'll now work through a set of review problems and interactive examples, challenging you to apply every method from this chapter.

Section 2

Regression line and predictions

Property

We can approximate a linear pattern in a scatterplot using a regression line.

We can use interpolation or extrapolation to make estimates and predictions.

If we extrapolate too far beyond the known data, we may get unreasonable results.

Section 3

Solutions of 2x2 linear systems

Property

A solution to a 2×22 \times 2 linear system is an ordered pair that satisfies both equations.

A solution to a 2×22 \times 2 linear system is a point where the two graphs intersect.

The substitution method is easier if one of the variables in one of the equations has a coefficient of 1 or -1.

Section 4

Inconsistent and dependent systems

Property

The graphs of the equations in an inconsistent system are parallel lines and hence do not intersect.

The graphs of the two equations in a dependent system are the same line.

If a linear combination of the equations in a system results in an equation of the form

0x+0y=k(k0)0x + 0y = k \quad (k \neq 0)

then the system is inconsistent. If an equation of the form

0x+0y=00x + 0y = 0

results, then the system is dependent.

Section 5

Graphing linear inequalities

Property

The solutions of the linear inequality

ax+by+c0orax+by+c0ax + by + c \leq 0 \quad \text{or} \quad ax + by + c \geq 0

consists of the line ax+by+c=0ax + by + c = 0 and a half-plane on one side of that line.

To Graph an Inequality Using a Test Point.

  1. Graph the corresponding equation to obtain the boundary line.
  2. Choose a test point that does not lie on the boundary line.
  3. Substitute the coordinates of the test point into the inequality.

a. If the resulting statement is true, shade the half-plane that includes the test point.
b. If the resulting statement is false, shade the half-plane that does not include the test point.

  1. If the inequality is strict, make the boundary line a dashed line.

Examples

  • To graph 3x4y<123x - 4y < 12, first draw the boundary line 3x4y=123x - 4y = 12 as a dashed line. Test the point (0,0)(0,0): 3(0)4(0)<123(0) - 4(0) < 12 is true, so shade the half-plane that contains the origin.

Section 6

Solving 3x3 linear systems

Property

A solution to an equation in three variables is an ordered triple of numbers that satisfies the equation.

To solve a 3×33 \times 3 linear system, we use linear combinations to reduce the system to triangular form, and then use back-substitution to find the solutions.

Examples

  • For the system x+z=5x+z=5, yz=8y-z=-8, and 2x+z=72x+z=7, first subtract the top equation from the bottom one to get x=2x=2. Substitute x=2x=2 into x+z=5x+z=5 to find z=3z=3. Finally, use z=3z=3 in yz=8y-z=-8 to find y=5y=-5. The solution is (2,5,3)(2, -5, 3).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Applications of Linear Models

  1. Lesson 1

    Lesson 1: Linear Regression

  2. Lesson 2

    Lesson 2: Linear Systems

  3. Lesson 3

    Lesson 3: Algebraic Solution of Systems

  4. Lesson 4

    Lesson 4: Gaussian Reduction

  5. Lesson 5

    Lesson 5: Linear Inequalities in Two Variables

  6. Lesson 6Current

    Lesson 6: Chapter Summary and Review