Learn on PengienVision, Algebra 2Chapter 3: Polynomial Functions

Lesson 5: Zeros of Polynomial Functions

In this Grade 11 enVision Algebra 2 lesson, students learn how to find and use the zeros of polynomial functions to sketch graphs, applying the Zero-Product Property and the Factor Theorem. The lesson covers multiplicity of a zero and how odd or even multiplicity determines whether a graph crosses or turns at the x-axis. Students also practice finding real and complex zeros using synthetic division and the Quadratic Formula.

Section 1

Solve Polynomial Equations by Factoring

Property

Polynomial Equation

An equation of the form P(x)=0P(x) = 0 where P(x)P(x) is a polynomial function is called a polynomial equation.

Section 2

Multiplicity of Zeros and Graph Behavior

Property

The multiplicity of a zero is the number of times the corresponding factor appears in the polynomial's factorization. If cc is a zero of multiplicity mm in polynomial P(x)=(xc)mQ(x)P(x) = (x - c)^m \cdot Q(x), then:

  • Odd multiplicity: graph crosses the x-axis at x=cx = c
  • Even multiplicity: graph touches but does not cross the x-axis at x=cx = c

Examples

Section 3

Synthetic Division to Find Additional Zeros

Property

When one zero cc of a polynomial P(x)P(x) is known, synthetic division can be used to divide P(x)P(x) by (xc)(x - c) to obtain P(x)=(xc)Q(x)P(x) = (x - c) \cdot Q(x), where Q(x)Q(x) is a polynomial of lower degree whose zeros are the remaining zeros of P(x)P(x).

Examples

Section 4

The Discriminant

Property

The discriminant of a quadratic equation is

D=b24acD = b^2 - 4ac
  1. If D>0D > 0, there are two unequal real solutions.
  2. If D=0D = 0, there is one solution of multiplicity two.
  3. If D<0D < 0, there are two complex conjugate solutions.

Examples

  • For y=x2x3y = x^2 - x - 3, the discriminant is D=(1)24(1)(3)=13D = (-1)^2 - 4(1)(-3) = 13. Since D>0D > 0, the equation has two distinct real solutions and the graph has two x-intercepts.
  • For y=2x2+x+1y = 2x^2 + x + 1, the discriminant is D=124(2)(1)=7D = 1^2 - 4(2)(1) = -7. Since D<0D < 0, the equation has two complex solutions and the graph has no x-intercepts.

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Chapter 3: Polynomial Functions

  1. Lesson 1

    Lesson 1: Graphing Polynomial Functions

  2. Lesson 2

    Lesson 2: Adding, Subtracting, and Multiplying Polynomials

  3. Lesson 3

    Lesson 3: Polynomial Identities

  4. Lesson 4

    Lesson 4: Dividing Polynomials

  5. Lesson 5Current

    Lesson 5: Zeros of Polynomial Functions

  6. Lesson 6

    Lesson 6: Theorems About Roots of Polynomial Equations

  7. Lesson 7

    Lesson 7: Transformations of Polynomial Functions

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Solve Polynomial Equations by Factoring

Property

Polynomial Equation

An equation of the form P(x)=0P(x) = 0 where P(x)P(x) is a polynomial function is called a polynomial equation.

Section 2

Multiplicity of Zeros and Graph Behavior

Property

The multiplicity of a zero is the number of times the corresponding factor appears in the polynomial's factorization. If cc is a zero of multiplicity mm in polynomial P(x)=(xc)mQ(x)P(x) = (x - c)^m \cdot Q(x), then:

  • Odd multiplicity: graph crosses the x-axis at x=cx = c
  • Even multiplicity: graph touches but does not cross the x-axis at x=cx = c

Examples

Section 3

Synthetic Division to Find Additional Zeros

Property

When one zero cc of a polynomial P(x)P(x) is known, synthetic division can be used to divide P(x)P(x) by (xc)(x - c) to obtain P(x)=(xc)Q(x)P(x) = (x - c) \cdot Q(x), where Q(x)Q(x) is a polynomial of lower degree whose zeros are the remaining zeros of P(x)P(x).

Examples

Section 4

The Discriminant

Property

The discriminant of a quadratic equation is

D=b24acD = b^2 - 4ac
  1. If D>0D > 0, there are two unequal real solutions.
  2. If D=0D = 0, there is one solution of multiplicity two.
  3. If D<0D < 0, there are two complex conjugate solutions.

Examples

  • For y=x2x3y = x^2 - x - 3, the discriminant is D=(1)24(1)(3)=13D = (-1)^2 - 4(1)(-3) = 13. Since D>0D > 0, the equation has two distinct real solutions and the graph has two x-intercepts.
  • For y=2x2+x+1y = 2x^2 + x + 1, the discriminant is D=124(2)(1)=7D = 1^2 - 4(2)(1) = -7. Since D<0D < 0, the equation has two complex solutions and the graph has no x-intercepts.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Polynomial Functions

  1. Lesson 1

    Lesson 1: Graphing Polynomial Functions

  2. Lesson 2

    Lesson 2: Adding, Subtracting, and Multiplying Polynomials

  3. Lesson 3

    Lesson 3: Polynomial Identities

  4. Lesson 4

    Lesson 4: Dividing Polynomials

  5. Lesson 5Current

    Lesson 5: Zeros of Polynomial Functions

  6. Lesson 6

    Lesson 6: Theorems About Roots of Polynomial Equations

  7. Lesson 7

    Lesson 7: Transformations of Polynomial Functions