Learn on PengiYoshiwara Core MathChapter 6: Core Concepts

Lesson 5: More About Similarity

In this Grade 8 lesson from Yoshiwara Core Math (Chapter 6), students explore how scale factors affect the areas of similar figures, discovering that multiplying each dimension of a figure by k increases its area by a factor of k². The lesson applies the Area Principle to real-world problems, such as comparing pizza sizes and scaling architectural floor plans. Students also extend these concepts to examine the volumes of proportional solids.

Section 1

📘 More About Similarity

New Concept

When we scale a figure's dimensions by a factor of kk, its area and volume change more dramatically. This lesson introduces the Area and Volume Principles, showing how area scales by k2k^2 and volume by k3k^3.

What’s next

Now, you'll see this principle in action through interactive examples. We'll explore how scaling dimensions affects the area and volume of various shapes.

Section 2

Similar Figures

Property

Two figures are similar if, and only if:

  1. Their corresponding angles are equal, and
  2. Their corresponding sides are proportional.

Examples

  • A rectangle with sides 4 cm and 6 cm is similar to a rectangle with sides 8 cm and 12 cm. The scale factor is 2.
  • A photograph measuring 4 inches by 6 inches is enlarged to 8 inches by 12 inches. The enlarged photo is similar to the original.

Section 3

Areas of Similar Figures

Property

If we multiply each dimension of a figure by kk, then:

  1. The new figure is similar to the original figure, and
  2. The area of the new figure is k2k^2 times the area of the original figure.

Examples

  • A square with a side length of 5 cm has an area of 25 cm2^2. If you scale its dimensions by a factor of k=3k=3, the new side is 15 cm and the new area is 152=22515^2 = 225 cm2^2, which is 32×25=9×253^2 \times 25 = 9 \times 25.
  • A circular rug has a radius of 2 feet. A larger, similar rug has a radius of 6 feet. The scale factor is 3, so the area of the larger rug is 32=93^2=9 times the area of the smaller one.

Section 4

Properties of Similar Solids

Property

  • The ratios of all corresponding dimensions in similar objects are equal.
  • The corresponding angles in similar objects are equal.
  • If we scale all the dimensions of a particular object by the same number, the new object will be similar to the old one.

Examples

  • A cube with 2-inch sides is similar to a cube with 6-inch sides. The ratio of their sides is 1:31:3.
  • Two spheres are always similar to each other. A sphere with a 5 cm radius is similar to one with a 10 cm radius.

Section 5

Volume Principle for Similar Objects

Property

If we multiply each dimension of a three-dimensional object by kk, then:

  1. The new object is similar to the original object, and
  2. The volume of the new object is k3k^3 times the volume of the original object.

Examples

  • A cube with a side length of 2 cm has a volume of 8 cm3^3. If you scale it by a factor of k=4k=4, the new side is 8 cm and the new volume is 83=5128^3 = 512 cm3^3, which is 43×8=64×84^3 \times 8 = 64 \times 8.
  • A model car is built at a 1:201:20 scale. The volume of the model is (120)3=18000(\frac{1}{20})^3 = \frac{1}{8000} times the volume of the actual car.

Book overview

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Chapter 6: Core Concepts

  1. Lesson 1

    Lesson 1: Ratios

  2. Lesson 2

    Lesson 2: Proportion

  3. Lesson 3

    Lesson 3: Slope

  4. Lesson 4

    Lesson 4: Similarity

  5. Lesson 5Current

    Lesson 5: More About Similarity

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 More About Similarity

New Concept

When we scale a figure's dimensions by a factor of kk, its area and volume change more dramatically. This lesson introduces the Area and Volume Principles, showing how area scales by k2k^2 and volume by k3k^3.

What’s next

Now, you'll see this principle in action through interactive examples. We'll explore how scaling dimensions affects the area and volume of various shapes.

Section 2

Similar Figures

Property

Two figures are similar if, and only if:

  1. Their corresponding angles are equal, and
  2. Their corresponding sides are proportional.

Examples

  • A rectangle with sides 4 cm and 6 cm is similar to a rectangle with sides 8 cm and 12 cm. The scale factor is 2.
  • A photograph measuring 4 inches by 6 inches is enlarged to 8 inches by 12 inches. The enlarged photo is similar to the original.

Section 3

Areas of Similar Figures

Property

If we multiply each dimension of a figure by kk, then:

  1. The new figure is similar to the original figure, and
  2. The area of the new figure is k2k^2 times the area of the original figure.

Examples

  • A square with a side length of 5 cm has an area of 25 cm2^2. If you scale its dimensions by a factor of k=3k=3, the new side is 15 cm and the new area is 152=22515^2 = 225 cm2^2, which is 32×25=9×253^2 \times 25 = 9 \times 25.
  • A circular rug has a radius of 2 feet. A larger, similar rug has a radius of 6 feet. The scale factor is 3, so the area of the larger rug is 32=93^2=9 times the area of the smaller one.

Section 4

Properties of Similar Solids

Property

  • The ratios of all corresponding dimensions in similar objects are equal.
  • The corresponding angles in similar objects are equal.
  • If we scale all the dimensions of a particular object by the same number, the new object will be similar to the old one.

Examples

  • A cube with 2-inch sides is similar to a cube with 6-inch sides. The ratio of their sides is 1:31:3.
  • Two spheres are always similar to each other. A sphere with a 5 cm radius is similar to one with a 10 cm radius.

Section 5

Volume Principle for Similar Objects

Property

If we multiply each dimension of a three-dimensional object by kk, then:

  1. The new object is similar to the original object, and
  2. The volume of the new object is k3k^3 times the volume of the original object.

Examples

  • A cube with a side length of 2 cm has a volume of 8 cm3^3. If you scale it by a factor of k=4k=4, the new side is 8 cm and the new volume is 83=5128^3 = 512 cm3^3, which is 43×8=64×84^3 \times 8 = 64 \times 8.
  • A model car is built at a 1:201:20 scale. The volume of the model is (120)3=18000(\frac{1}{20})^3 = \frac{1}{8000} times the volume of the actual car.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Core Concepts

  1. Lesson 1

    Lesson 1: Ratios

  2. Lesson 2

    Lesson 2: Proportion

  3. Lesson 3

    Lesson 3: Slope

  4. Lesson 4

    Lesson 4: Similarity

  5. Lesson 5Current

    Lesson 5: More About Similarity