Learn on PengiPengi Math (Grade 8)Chapter 3: Solving Linear Equations

Lesson 5: Literal Equations and Real-World Applications

In this Grade 8 lesson from Pengi Math Chapter 3, students learn to define and solve literal equations by isolating a specific variable in multi-variable formulas, such as rewriting P = 2l + 2w to solve for l. They apply algebraic rearrangement to real-world formulas including Simple Interest (I = Prt) and temperature conversion, then practice setting up and solving linear equations to model practical situations. The lesson also uses the mean formula as a linear equation to find missing data points.

Section 1

Setting up a Linear Equation

Property

To set up or model a linear equation to fit a real-world application, we must first determine the known quantities and define the unknown quantity as a variable.
Then, we begin to interpret the words as mathematical expressions using mathematical symbols.
For example, a variable cost can be written as 0.10x0.10x, while a fixed cost is a constant added or subtracted, such as in C=0.10x+50C = 0.10x + 50.

To model a linear equation:

  1. Identify known quantities.
  2. Assign a variable to represent the unknown quantity.
  3. If there is more than one unknown quantity, find a way to write the second unknown in terms of the first.
  4. Write an equation interpreting the words as mathematical operations.
  5. Solve the equation. Be sure the solution can be explained in words, including the units of measure.

Examples

  • One number is 10 more than another, and their sum is 52. Let the first number be xx. The second is x+10x+10. The equation is x+(x+10)=52x + (x+10) = 52, so 2x=422x=42, and x=21x=21. The numbers are 21 and 31.
  • A taxi charges 3 dollars plus 2 dollars per mile. The total cost CC for a ride of xx miles is modeled by the equation C=2x+3C = 2x + 3. A 5-mile ride costs C=2(5)+3=13C = 2(5) + 3 = 13 dollars.
  • Two streaming services have different plans. Plan A is 15 dollars a month. Plan B is 5 dollars a month plus 2 dollars per movie. To find when they cost the same for mm movies, set 15=5+2m15 = 5 + 2m. Solving gives 10=2m10 = 2m, so m=5m=5 movies.

Section 2

Isolating a Variable in a Formula

Property

Literal equations are formulas that use letters to represent quantities and relationships. These equations can be rewritten to express one variable in terms of others. Using inverse operations, a chosen variable can be isolated on one side of the equation, revealing how it depends on the remaining quantities. The process is the same as solving a regular linear equation, but you will be working with variables instead of just numbers.

Examples

  • The formula d=rtd = rt represents the relationship between distance, rate, and time. If the distance is 120 miles and the time is 3 hours, substituting these values into the rewritten formula
r=dt r = \frac{d}{t}

gives

r=1203=40, r = \frac{120}{3} = 40,

showing that the rate is 40 miles per hour.

  • The formula P=2l+2wP = 2l + 2w represents the perimeter of a rectangle, where ll is the length and ww is the width. If the perimeter is 28 units and the length is 6 units, substituting these values into the rewritten formula
w=P2l2 w = \frac{P - 2l}{2}

gives

w=28122=8, w = \frac{28 - 12}{2} = 8,

showing that the width is 4 units.

Book overview

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Chapter 3: Solving Linear Equations

  1. Lesson 1

    Lesson 1: Simplifying and Solving One-Step & Multi-Step Equations

  2. Lesson 2

    Lesson 2: Solving Equations with Variables on Both Sides

  3. Lesson 3

    Lesson 3: Equations with Rational Coefficients (Fractions and Decimals)

  4. Lesson 4

    Lesson 4: Analyzing Number of Solutions (One, None, Infinite)

  5. Lesson 5Current

    Lesson 5: Literal Equations and Real-World Applications

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Setting up a Linear Equation

Property

To set up or model a linear equation to fit a real-world application, we must first determine the known quantities and define the unknown quantity as a variable.
Then, we begin to interpret the words as mathematical expressions using mathematical symbols.
For example, a variable cost can be written as 0.10x0.10x, while a fixed cost is a constant added or subtracted, such as in C=0.10x+50C = 0.10x + 50.

To model a linear equation:

  1. Identify known quantities.
  2. Assign a variable to represent the unknown quantity.
  3. If there is more than one unknown quantity, find a way to write the second unknown in terms of the first.
  4. Write an equation interpreting the words as mathematical operations.
  5. Solve the equation. Be sure the solution can be explained in words, including the units of measure.

Examples

  • One number is 10 more than another, and their sum is 52. Let the first number be xx. The second is x+10x+10. The equation is x+(x+10)=52x + (x+10) = 52, so 2x=422x=42, and x=21x=21. The numbers are 21 and 31.
  • A taxi charges 3 dollars plus 2 dollars per mile. The total cost CC for a ride of xx miles is modeled by the equation C=2x+3C = 2x + 3. A 5-mile ride costs C=2(5)+3=13C = 2(5) + 3 = 13 dollars.
  • Two streaming services have different plans. Plan A is 15 dollars a month. Plan B is 5 dollars a month plus 2 dollars per movie. To find when they cost the same for mm movies, set 15=5+2m15 = 5 + 2m. Solving gives 10=2m10 = 2m, so m=5m=5 movies.

Section 2

Isolating a Variable in a Formula

Property

Literal equations are formulas that use letters to represent quantities and relationships. These equations can be rewritten to express one variable in terms of others. Using inverse operations, a chosen variable can be isolated on one side of the equation, revealing how it depends on the remaining quantities. The process is the same as solving a regular linear equation, but you will be working with variables instead of just numbers.

Examples

  • The formula d=rtd = rt represents the relationship between distance, rate, and time. If the distance is 120 miles and the time is 3 hours, substituting these values into the rewritten formula
r=dt r = \frac{d}{t}

gives

r=1203=40, r = \frac{120}{3} = 40,

showing that the rate is 40 miles per hour.

  • The formula P=2l+2wP = 2l + 2w represents the perimeter of a rectangle, where ll is the length and ww is the width. If the perimeter is 28 units and the length is 6 units, substituting these values into the rewritten formula
w=P2l2 w = \frac{P - 2l}{2}

gives

w=28122=8, w = \frac{28 - 12}{2} = 8,

showing that the width is 4 units.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Solving Linear Equations

  1. Lesson 1

    Lesson 1: Simplifying and Solving One-Step & Multi-Step Equations

  2. Lesson 2

    Lesson 2: Solving Equations with Variables on Both Sides

  3. Lesson 3

    Lesson 3: Equations with Rational Coefficients (Fractions and Decimals)

  4. Lesson 4

    Lesson 4: Analyzing Number of Solutions (One, None, Infinite)

  5. Lesson 5Current

    Lesson 5: Literal Equations and Real-World Applications