Learn on PengiIllustrative Mathematics, Grade 8Chapter 5: Functions and Volume

Lesson 5: Dimensions and Spheres

In this Grade 8 Illustrative Mathematics lesson, students explore how changing a single dimension — such as the height of a cylinder or the edge length of a rectangular prism — affects volume through proportional relationships. Students write and graph equations relating volume to one variable for prisms, cylinders, and cones, then analyze how doubling or halving that dimension scales the volume by the same factor. The lesson reinforces that these volume relationships are linear functions and proportional relationships.

Section 1

Estimating Hemisphere Volume by Averaging

Property

The volume of a hemisphere can be estimated by averaging the volumes of a circumscribed cylinder and an inscribed cone. For a hemisphere of radius rr, the cylinder and cone have height h=rh=r. This estimation gives the exact volume of a hemisphere.

Vest_hemisphere=Vcylinder+Vcone2=πr3+13πr32=23πr3V_{est\_hemisphere} = \frac{V_{cylinder} + V_{cone}}{2} = \frac{\pi r^3 + \frac{1}{3}\pi r^3}{2} = \frac{2}{3}\pi r^3

Section 2

Volume of a Sphere

Property

The volume VV of a sphere with radius rr is given by the formula:

V=43πr3V = \frac{4}{3}\pi r^3

Examples

Section 3

Relationship Between Cone and Cylinder Volumes

Property

A cone has exactly one-third the volume of a cylinder with the same base and height: Vcone=13VcylinderV_{cone} = \frac{1}{3} \cdot V_{cylinder}

If cylinder volume is Vcylinder=πr2hV_{cylinder} = \pi r^2 h, then cone volume is Vcone=13πr2hV_{cone} = \frac{1}{3}\pi r^2 h

Section 4

Sphere Volume from Cylinder Relationship

Property

The volume of a sphere is 23\frac{2}{3} times the volume of a cylinder that has the same diameter as the sphere and height equal to the diameter:

Vsphere=23×Vcylinder=23×πr2hV_{sphere} = \frac{2}{3} \times V_{cylinder} = \frac{2}{3} \times \pi r^2 h

When h=2rh = 2r (diameter), this becomes:

Vsphere=23×πr2(2r)=43πr3V_{sphere} = \frac{2}{3} \times \pi r^2 (2r) = \frac{4}{3}\pi r^3

Book overview

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Chapter 5: Functions and Volume

  1. Lesson 1

    Lesson 1: Inputs and Outputs

  2. Lesson 2

    Lesson 2: Representing and Interpreting Functions

  3. Lesson 3

    Lesson 3: Linear Functions and Rates of Change

  4. Lesson 4

    Lesson 4: Cylinders and Cones

  5. Lesson 5Current

    Lesson 5: Dimensions and Spheres

Lesson overview

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Section 1

Estimating Hemisphere Volume by Averaging

Property

The volume of a hemisphere can be estimated by averaging the volumes of a circumscribed cylinder and an inscribed cone. For a hemisphere of radius rr, the cylinder and cone have height h=rh=r. This estimation gives the exact volume of a hemisphere.

Vest_hemisphere=Vcylinder+Vcone2=πr3+13πr32=23πr3V_{est\_hemisphere} = \frac{V_{cylinder} + V_{cone}}{2} = \frac{\pi r^3 + \frac{1}{3}\pi r^3}{2} = \frac{2}{3}\pi r^3

Section 2

Volume of a Sphere

Property

The volume VV of a sphere with radius rr is given by the formula:

V=43πr3V = \frac{4}{3}\pi r^3

Examples

Section 3

Relationship Between Cone and Cylinder Volumes

Property

A cone has exactly one-third the volume of a cylinder with the same base and height: Vcone=13VcylinderV_{cone} = \frac{1}{3} \cdot V_{cylinder}

If cylinder volume is Vcylinder=πr2hV_{cylinder} = \pi r^2 h, then cone volume is Vcone=13πr2hV_{cone} = \frac{1}{3}\pi r^2 h

Section 4

Sphere Volume from Cylinder Relationship

Property

The volume of a sphere is 23\frac{2}{3} times the volume of a cylinder that has the same diameter as the sphere and height equal to the diameter:

Vsphere=23×Vcylinder=23×πr2hV_{sphere} = \frac{2}{3} \times V_{cylinder} = \frac{2}{3} \times \pi r^2 h

When h=2rh = 2r (diameter), this becomes:

Vsphere=23×πr2(2r)=43πr3V_{sphere} = \frac{2}{3} \times \pi r^2 (2r) = \frac{4}{3}\pi r^3

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Functions and Volume

  1. Lesson 1

    Lesson 1: Inputs and Outputs

  2. Lesson 2

    Lesson 2: Representing and Interpreting Functions

  3. Lesson 3

    Lesson 3: Linear Functions and Rates of Change

  4. Lesson 4

    Lesson 4: Cylinders and Cones

  5. Lesson 5Current

    Lesson 5: Dimensions and Spheres