Learn on PengienVision, Algebra 1Chapter 8: Quadratic Functions

Lesson 4: Modeling with Quadratic Functions

In this Grade 11 enVision Algebra 1 lesson from Chapter 8, students learn to model real-world situations using quadratic functions, applying the vertical motion model h(t) = -16t² + v₀t + h₀ to problems involving falling objects and projectile motion. Students also write quadratic functions to represent area relationships and evaluate how well a quadratic model fits data by calculating residuals. The lesson introduces quadratic regression as a tool for finding best-fit functions from real-world data sets.

Section 1

Problem-Solving Strategy for Quadratic Modeling

Property

Use a systematic problem-solving strategy for quadratic modeling applications:
Step 1. Read the problem to understand the context and relationships.
Step 2. Identify what you are looking for (maximum, minimum, dimensions, etc.).
Step 3. Define variables for unknown quantities.
Step 4. Translate the problem into a quadratic equation or function.
Step 5. Solve the equation or analyze the function as needed.
Step 6. Check if the answer makes sense in the problem context.
Step 7. Answer the question with a complete sentence including appropriate units.

Examples

Section 2

Area of a rectangle

Property

For a rectangle with length, LL, and width, WW, the area, AA, is given by the formula:

A=LWA = LW

In application problems, one dimension is often expressed in terms of the other (e.g., L=3W1L = 3W-1).
Substituting this into the area formula creates a quadratic equation.
If the equation cannot be factored, use the Quadratic Formula to find the solution and round as needed.

Examples

  • A rectangular garden has an area of 100 square feet. Its length is 15 feet more than its width. Find the dimensions. Let the width be WW. The equation is 100=W(W+15)100 = W(W+15), or W2+15W100=0W^2 + 15W - 100 = 0. Factoring gives (W+20)(W5)=0(W+20)(W-5)=0. The width is 5 feet and the length is 20 feet.
  • The length of a rectangular patio is 1 foot less than twice its width. The area is 105 square feet. Find the length and width. Let the width be WW. The equation is 105=W(2W1)105 = W(2W-1), or 2W2W105=02W^2 - W - 105 = 0. Factoring gives (2W+15)(W7)=0(2W+15)(W-7)=0. The width is 7 feet and the length is 13 feet.

Section 3

Complete Vertical Motion Model

Property

The height in feet, hh, of an object shot upwards into the air with initial velocity, v0v_0, from an initial height h0h_0, after tt seconds is given by the formula:

h=16t2+v0t+h0h = -16t^2 + v_0t + h_0

Examples

Book overview

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Chapter 8: Quadratic Functions

  1. Lesson 1

    Lesson 1: Key Features of Graphs of a Quadratic Function

  2. Lesson 2

    Lesson 2: Quadratic Functions in Vertex Form

  3. Lesson 3

    Lesson 3: Quadratic Functions in Standard Form

  4. Lesson 4Current

    Lesson 4: Modeling with Quadratic Functions

  5. Lesson 5

    Lesson 5: Comparing Linear, Exponential, and Quadratic Models

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Problem-Solving Strategy for Quadratic Modeling

Property

Use a systematic problem-solving strategy for quadratic modeling applications:
Step 1. Read the problem to understand the context and relationships.
Step 2. Identify what you are looking for (maximum, minimum, dimensions, etc.).
Step 3. Define variables for unknown quantities.
Step 4. Translate the problem into a quadratic equation or function.
Step 5. Solve the equation or analyze the function as needed.
Step 6. Check if the answer makes sense in the problem context.
Step 7. Answer the question with a complete sentence including appropriate units.

Examples

Section 2

Area of a rectangle

Property

For a rectangle with length, LL, and width, WW, the area, AA, is given by the formula:

A=LWA = LW

In application problems, one dimension is often expressed in terms of the other (e.g., L=3W1L = 3W-1).
Substituting this into the area formula creates a quadratic equation.
If the equation cannot be factored, use the Quadratic Formula to find the solution and round as needed.

Examples

  • A rectangular garden has an area of 100 square feet. Its length is 15 feet more than its width. Find the dimensions. Let the width be WW. The equation is 100=W(W+15)100 = W(W+15), or W2+15W100=0W^2 + 15W - 100 = 0. Factoring gives (W+20)(W5)=0(W+20)(W-5)=0. The width is 5 feet and the length is 20 feet.
  • The length of a rectangular patio is 1 foot less than twice its width. The area is 105 square feet. Find the length and width. Let the width be WW. The equation is 105=W(2W1)105 = W(2W-1), or 2W2W105=02W^2 - W - 105 = 0. Factoring gives (2W+15)(W7)=0(2W+15)(W-7)=0. The width is 7 feet and the length is 13 feet.

Section 3

Complete Vertical Motion Model

Property

The height in feet, hh, of an object shot upwards into the air with initial velocity, v0v_0, from an initial height h0h_0, after tt seconds is given by the formula:

h=16t2+v0t+h0h = -16t^2 + v_0t + h_0

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Quadratic Functions

  1. Lesson 1

    Lesson 1: Key Features of Graphs of a Quadratic Function

  2. Lesson 2

    Lesson 2: Quadratic Functions in Vertex Form

  3. Lesson 3

    Lesson 3: Quadratic Functions in Standard Form

  4. Lesson 4Current

    Lesson 4: Modeling with Quadratic Functions

  5. Lesson 5

    Lesson 5: Comparing Linear, Exponential, and Quadratic Models