Learn on PengienVision, Algebra 1Chapter 4: Systems of Linear Equations and Inequalities

Lesson 4: Linear Inequalities in Two Variables

Property A linear inequality is an inequality that can be written in one of the following forms: $A x + B y C$ $A x + B y \geq C$ $A x + B y < C$ $A x + B y \leq C$ where $A$ and $B$ are not both zero.

Section 1

Linear Inequality

Property

A linear inequality is an inequality that can be written in one of the following forms:
Ax+By>CA x + B y > C
Ax+ByCA x + B y \geq C
Ax+By<CA x + B y < C
Ax+ByCA x + B y \leq C
where AA and BB are not both zero.

Examples

  • The statement 3xy<73x - y < 7 is a linear inequality.
  • The statement y2x+5y \geq 2x + 5 is a linear inequality.
  • The statement x<4x < 4 is a linear inequality where the coefficient of yy is 00.

Explanation

A linear inequality describes a relationship that isn't strictly equal. Instead of a single line of solutions, it represents a whole region on the coordinate plane. Think of it as a 'more than' or 'less than' zone with infinite solutions.

Section 2

Boundary Line

Property

The line with equation Ax+By=CAx + By = C is the boundary line that separates the region where Ax+By>CAx + By > C from the region where Ax+By<CAx + By < C.

For Ax+By<CAx + By < C or Ax+By>CAx + By > C, the boundary line is not included in the solution, and the line is dashed.

For Ax+ByCAx + By \leq C or Ax+ByCAx + By \geq C, the boundary line is included in the solution, and the line is solid.

Section 3

Using a Test Point to Determine Shading

Property

To find which half-plane contains the solutions (and should be shaded), use the Test Point Method:

  1. Graph the boundary line (solid or dashed).
  2. Choose a simple test point that is strictly NOT on the boundary line. The origin (0,0)(0, 0) is always the best choice, unless the line passes directly through it.
  3. Substitute the coordinates of the test point into the original inequality.
  4. If the result is a TRUE statement, shade the entire half-plane that contains the test point. If it is FALSE, shade the opposite half-plane.

Examples

  • Using (0,0)(0,0) as a test point: Graph x3y<6x - 3y < 6.

Draw the dashed line x3y=6x - 3y = 6. Test the origin (0,0)(0,0): 03(0)<60 - 3(0) < 6 simplifies to 0<60 < 6. This is a TRUE statement. Therefore, shade the side of the line that includes the point (0,0)(0,0).

  • When (0,0)(0,0) is on the line: Graph y2xy \leq 2x.

Draw the solid line y=2xy = 2x. Since this line passes exactly through the origin, we must choose a different point, like (3,1)(3, 1). Test it: 12(3)1 \leq 2(3) simplifies to 161 \leq 6. This is TRUE. Shade the side containing the point (3,1)(3, 1).

  • A False Result: Graph y>4y > 4.

Draw a dashed horizontal line at y=4y = 4. Test (0,0)(0,0): 0>40 > 4 is FALSE. Shade the side that does NOT contain (0,0)(0,0), which is the region above the line.

Explanation

Because the boundary line cuts the graph perfectly in half, all the correct answers live together on one side, and all the wrong answers live together on the other. This means you don't have to test a hundred different points! You only need to test one single point to scout out the territory. If your scout point tells the truth, its entire side is the winner. If it lies, the other side wins.

Book overview

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Chapter 4: Systems of Linear Equations and Inequalities

  1. Lesson 1

    Lesson 1: Solving Systems of Equations by Graphing

  2. Lesson 2

    Lesson 2: Solving Systems of Equations by Substitution

  3. Lesson 3

    Lesson 3: Solving Systems of Equations by Elimination

  4. Lesson 4Current

    Lesson 4: Linear Inequalities in Two Variables

  5. Lesson 5

    Lesson 5: Systems of Linear Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Linear Inequality

Property

A linear inequality is an inequality that can be written in one of the following forms:
Ax+By>CA x + B y > C
Ax+ByCA x + B y \geq C
Ax+By<CA x + B y < C
Ax+ByCA x + B y \leq C
where AA and BB are not both zero.

Examples

  • The statement 3xy<73x - y < 7 is a linear inequality.
  • The statement y2x+5y \geq 2x + 5 is a linear inequality.
  • The statement x<4x < 4 is a linear inequality where the coefficient of yy is 00.

Explanation

A linear inequality describes a relationship that isn't strictly equal. Instead of a single line of solutions, it represents a whole region on the coordinate plane. Think of it as a 'more than' or 'less than' zone with infinite solutions.

Section 2

Boundary Line

Property

The line with equation Ax+By=CAx + By = C is the boundary line that separates the region where Ax+By>CAx + By > C from the region where Ax+By<CAx + By < C.

For Ax+By<CAx + By < C or Ax+By>CAx + By > C, the boundary line is not included in the solution, and the line is dashed.

For Ax+ByCAx + By \leq C or Ax+ByCAx + By \geq C, the boundary line is included in the solution, and the line is solid.

Section 3

Using a Test Point to Determine Shading

Property

To find which half-plane contains the solutions (and should be shaded), use the Test Point Method:

  1. Graph the boundary line (solid or dashed).
  2. Choose a simple test point that is strictly NOT on the boundary line. The origin (0,0)(0, 0) is always the best choice, unless the line passes directly through it.
  3. Substitute the coordinates of the test point into the original inequality.
  4. If the result is a TRUE statement, shade the entire half-plane that contains the test point. If it is FALSE, shade the opposite half-plane.

Examples

  • Using (0,0)(0,0) as a test point: Graph x3y<6x - 3y < 6.

Draw the dashed line x3y=6x - 3y = 6. Test the origin (0,0)(0,0): 03(0)<60 - 3(0) < 6 simplifies to 0<60 < 6. This is a TRUE statement. Therefore, shade the side of the line that includes the point (0,0)(0,0).

  • When (0,0)(0,0) is on the line: Graph y2xy \leq 2x.

Draw the solid line y=2xy = 2x. Since this line passes exactly through the origin, we must choose a different point, like (3,1)(3, 1). Test it: 12(3)1 \leq 2(3) simplifies to 161 \leq 6. This is TRUE. Shade the side containing the point (3,1)(3, 1).

  • A False Result: Graph y>4y > 4.

Draw a dashed horizontal line at y=4y = 4. Test (0,0)(0,0): 0>40 > 4 is FALSE. Shade the side that does NOT contain (0,0)(0,0), which is the region above the line.

Explanation

Because the boundary line cuts the graph perfectly in half, all the correct answers live together on one side, and all the wrong answers live together on the other. This means you don't have to test a hundred different points! You only need to test one single point to scout out the territory. If your scout point tells the truth, its entire side is the winner. If it lies, the other side wins.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Systems of Linear Equations and Inequalities

  1. Lesson 1

    Lesson 1: Solving Systems of Equations by Graphing

  2. Lesson 2

    Lesson 2: Solving Systems of Equations by Substitution

  3. Lesson 3

    Lesson 3: Solving Systems of Equations by Elimination

  4. Lesson 4Current

    Lesson 4: Linear Inequalities in Two Variables

  5. Lesson 5

    Lesson 5: Systems of Linear Inequalities