Learn on PengiBig Ideas Math, Algebra 2Chapter 7: Rational Functions

Lesson 4: Adding and Subtracting Rational Expressions

In this Grade 8 lesson from Big Ideas Math Algebra 2, Chapter 7, students learn how to add and subtract rational expressions with both like and unlike denominators by finding least common denominators and simplifying the results. The lesson also covers rewriting rational expressions, graphing related functions, and simplifying complex fractions. Students practice identifying the domain of sums and differences of rational expressions, building directly on their prior knowledge of operations with numerical fractions.

Section 1

Add Rational Expressions with a Common Denominator

Property

If pp, qq, and rr are polynomials where r0r \neq 0, then

pr+qr=p+qr \frac{p}{r} + \frac{q}{r} = \frac{p+q}{r}

To add rational expressions with a common denominator, add the numerators and place the sum over the common denominator. Always check if the resulting fraction can be simplified.

Examples

  • Add: 5xx+2+10x+2\frac{5x}{x+2} + \frac{10}{x+2}.

This equals 5x+10x+2\frac{5x+10}{x+2}. Factoring the numerator gives 5(x+2)x+2\frac{5(x+2)}{x+2}, which simplifies to 55.

  • Add: x2x5+2x35x5\frac{x^2}{x-5} + \frac{2x-35}{x-5}.

This equals x2+2x35x5\frac{x^2+2x-35}{x-5}. Factoring the numerator gives (x+7)(x5)x5\frac{(x+7)(x-5)}{x-5}, which simplifies to x+7x+7.

Section 2

Subtract Rational Expressions with a Common Denominator

Property

If pp, qq, and rr are polynomials where r0r \neq 0, then

prqr=pqr \frac{p}{r} - \frac{q}{r} = \frac{p-q}{r}

To subtract rational expressions, subtract the numerators and place the difference over the common denominator. Be very careful to distribute the negative sign to every term in the second numerator.

Examples

  • Subtract: y2y416y4\frac{y^2}{y-4} - \frac{16}{y-4}.

This equals y216y4\frac{y^2-16}{y-4}. Factoring the numerator as a difference of squares gives (y4)(y+4)y4\frac{(y-4)(y+4)}{y-4}, which simplifies to y+4y+4.

  • Subtract: x2x+53x+10x+5\frac{x^2}{x+5} - \frac{3x+10}{x+5}.

This equals x2(3x+10)x+5=x23x10x+5\frac{x^2 - (3x+10)}{x+5} = \frac{x^2-3x-10}{x+5}. Factoring the numerator gives (x5)(x+2)x+5\frac{(x-5)(x+2)}{x+5}. This cannot be simplified further.

Book overview

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Chapter 7: Rational Functions

  1. Lesson 1

    Lesson 1: Inverse Variation

  2. Lesson 2

    Lesson 2: Graphing Rational Functions

  3. Lesson 3

    Lesson 3: Multiplying and Dividing Rational Expressions

  4. Lesson 4Current

    Lesson 4: Adding and Subtracting Rational Expressions

  5. Lesson 5

    Lesson 5: Solving Rational Equations

Lesson overview

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Section 1

Add Rational Expressions with a Common Denominator

Property

If pp, qq, and rr are polynomials where r0r \neq 0, then

pr+qr=p+qr \frac{p}{r} + \frac{q}{r} = \frac{p+q}{r}

To add rational expressions with a common denominator, add the numerators and place the sum over the common denominator. Always check if the resulting fraction can be simplified.

Examples

  • Add: 5xx+2+10x+2\frac{5x}{x+2} + \frac{10}{x+2}.

This equals 5x+10x+2\frac{5x+10}{x+2}. Factoring the numerator gives 5(x+2)x+2\frac{5(x+2)}{x+2}, which simplifies to 55.

  • Add: x2x5+2x35x5\frac{x^2}{x-5} + \frac{2x-35}{x-5}.

This equals x2+2x35x5\frac{x^2+2x-35}{x-5}. Factoring the numerator gives (x+7)(x5)x5\frac{(x+7)(x-5)}{x-5}, which simplifies to x+7x+7.

Section 2

Subtract Rational Expressions with a Common Denominator

Property

If pp, qq, and rr are polynomials where r0r \neq 0, then

prqr=pqr \frac{p}{r} - \frac{q}{r} = \frac{p-q}{r}

To subtract rational expressions, subtract the numerators and place the difference over the common denominator. Be very careful to distribute the negative sign to every term in the second numerator.

Examples

  • Subtract: y2y416y4\frac{y^2}{y-4} - \frac{16}{y-4}.

This equals y216y4\frac{y^2-16}{y-4}. Factoring the numerator as a difference of squares gives (y4)(y+4)y4\frac{(y-4)(y+4)}{y-4}, which simplifies to y+4y+4.

  • Subtract: x2x+53x+10x+5\frac{x^2}{x+5} - \frac{3x+10}{x+5}.

This equals x2(3x+10)x+5=x23x10x+5\frac{x^2 - (3x+10)}{x+5} = \frac{x^2-3x-10}{x+5}. Factoring the numerator gives (x5)(x+2)x+5\frac{(x-5)(x+2)}{x+5}. This cannot be simplified further.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Functions

  1. Lesson 1

    Lesson 1: Inverse Variation

  2. Lesson 2

    Lesson 2: Graphing Rational Functions

  3. Lesson 3

    Lesson 3: Multiplying and Dividing Rational Expressions

  4. Lesson 4Current

    Lesson 4: Adding and Subtracting Rational Expressions

  5. Lesson 5

    Lesson 5: Solving Rational Equations