Learn on PengiBig Ideas Math, Algebra 2Chapter 7: Rational Functions

Lesson 1: Inverse Variation

In this Grade 8 lesson from Big Ideas Math Algebra 2, Chapter 7, students learn to classify direct variation and inverse variation by examining equations and data tables, using the defining relationship y = a/x and the constant of variation. Students practice identifying inverse variation by checking whether the products xy are constant and distinguishing it from direct variation, where the ratios y/x are constant. The lesson also covers writing inverse variation equations from real-world contexts, including applications like Hooke's Law and rectangle dimensions.

Section 1

Solving Problems with Proportional Equations

Property

For any two variables xx and yy, yy varies directly with xx if

y=kx, where k0y = kx, \text{ where } k \neq 0

The constant kk is called the constant of variation. When two quantities are related by a proportion, we say they are proportional to each other.

To solve direct variation problems:

  1. Write the formula for direct variation: y=kxy = kx.
  2. Substitute the given values for the variables.
  3. Solve for the constant of variation, kk.
  4. Write the equation that relates xx and yy using the value of kk.

Examples

  • If yy varies directly with xx, and y=45y=45 when x=9x=9, find the equation. We use y=kxy=kx, so 45=k(9)45=k(9), which gives k=5k=5. The equation is y=5xy=5x.
  • The cost of juice, CC, varies directly with the number of bottles, nn. If 4 bottles cost 12 dollars, how much would 7 bottles cost? The relation is C=knC=kn. We find kk from 12=k(4)12=k(4), so k=3k=3. The equation is C=3nC=3n. For 7 bottles, the cost is C=3(7)=21C=3(7)=21 dollars.
  • The distance, dd, an ant crawls varies directly with time, tt. If it crawls 120 cm in 3 minutes, how far can it crawl in 10 minutes? The formula is d=ktd=kt. Substituting gives 120=k(3)120=k(3), so k=40k=40. The equation is d=40td=40t. In 10 minutes, it crawls d=40(10)=400d=40(10)=400 cm.

Section 2

Definition of Inverse Proportion

Property

yy varies inversely with xx if

y=kx,x0y = \frac{k}{x}, x \neq 0

where kk is a positive constant. This relationship implies that the product of the variables is constant: xy=kxy = k.

Book overview

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Chapter 7: Rational Functions

  1. Lesson 1Current

    Lesson 1: Inverse Variation

  2. Lesson 2

    Lesson 2: Graphing Rational Functions

  3. Lesson 3

    Lesson 3: Multiplying and Dividing Rational Expressions

  4. Lesson 4

    Lesson 4: Adding and Subtracting Rational Expressions

  5. Lesson 5

    Lesson 5: Solving Rational Equations

Lesson overview

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Section 1

Solving Problems with Proportional Equations

Property

For any two variables xx and yy, yy varies directly with xx if

y=kx, where k0y = kx, \text{ where } k \neq 0

The constant kk is called the constant of variation. When two quantities are related by a proportion, we say they are proportional to each other.

To solve direct variation problems:

  1. Write the formula for direct variation: y=kxy = kx.
  2. Substitute the given values for the variables.
  3. Solve for the constant of variation, kk.
  4. Write the equation that relates xx and yy using the value of kk.

Examples

  • If yy varies directly with xx, and y=45y=45 when x=9x=9, find the equation. We use y=kxy=kx, so 45=k(9)45=k(9), which gives k=5k=5. The equation is y=5xy=5x.
  • The cost of juice, CC, varies directly with the number of bottles, nn. If 4 bottles cost 12 dollars, how much would 7 bottles cost? The relation is C=knC=kn. We find kk from 12=k(4)12=k(4), so k=3k=3. The equation is C=3nC=3n. For 7 bottles, the cost is C=3(7)=21C=3(7)=21 dollars.
  • The distance, dd, an ant crawls varies directly with time, tt. If it crawls 120 cm in 3 minutes, how far can it crawl in 10 minutes? The formula is d=ktd=kt. Substituting gives 120=k(3)120=k(3), so k=40k=40. The equation is d=40td=40t. In 10 minutes, it crawls d=40(10)=400d=40(10)=400 cm.

Section 2

Definition of Inverse Proportion

Property

yy varies inversely with xx if

y=kx,x0y = \frac{k}{x}, x \neq 0

where kk is a positive constant. This relationship implies that the product of the variables is constant: xy=kxy = k.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Functions

  1. Lesson 1Current

    Lesson 1: Inverse Variation

  2. Lesson 2

    Lesson 2: Graphing Rational Functions

  3. Lesson 3

    Lesson 3: Multiplying and Dividing Rational Expressions

  4. Lesson 4

    Lesson 4: Adding and Subtracting Rational Expressions

  5. Lesson 5

    Lesson 5: Solving Rational Equations