Learn on PengiOpenstax Prealgebre 2EChapter 9: Math Models and Geometry

Lesson 3: Use Properties of Angles, Triangles, and the Pythagorean Theorem

Students learn to identify and solve problems involving supplementary and complementary angles, properties of triangles, and the Pythagorean Theorem in this lesson from Chapter 9 of OpenStax Prealgebra 2e. The lesson introduces key angle concepts such as vertex, degrees, and angle measurement, then applies a structured problem-solving strategy to geometry applications. These foundational geometry skills build on prior algebra techniques to prepare students for real-world math modeling.

Section 1

πŸ“˜ Use Properties of Angles, Triangles, and the Pythagorean Theorem

New Concept

This lesson introduces fundamental geometric rules. You'll learn how to use properties of angles, triangles, and the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) to find unknown lengths and angles, setting the stage for solving geometry problems.

What’s next

Now, let's apply these rules. You'll tackle interactive examples and practice problems to master finding missing angles and side lengths.

Section 2

Supplementary and complementary angles

Property

If the sum of the measures of two angles is 180∘180^\circ, then the angles are supplementary.

If ∠A\angle A and ∠B\angle B are supplementary, then m∠A+m∠B=180∘m\angle A + m\angle B = 180^\circ.

If the sum of the measures of two angles is 90∘90^\circ, then the angles are complementary.

Section 3

Sum of the measures of the angles of a triangle

Property

For any β–³ABC\triangle ABC, the sum of the measures of the angles is 180∘180^\circ.

m∠A+m∠B+m∠C=180∘m\angle A + m\angle B + m\angle C = 180^\circ

Examples

  • The measures of two angles of a triangle are 60∘60^\circ and 85∘85^\circ. The third angle, xx, is found by solving 60∘+85∘+x=180∘60^\circ + 85^\circ + x = 180^\circ, which gives 145∘+x=180∘145^\circ + x = 180^\circ, so x=35∘x = 35^\circ.

Section 4

Properties of similar triangles

Property

If two triangles are similar, then their corresponding angle measures are equal and their corresponding side lengths are in the same ratio.

Examples

  • β–³ABC\triangle ABC is similar to β–³XYZ\triangle XYZ. If side AB=6AB=6 and corresponding side XY=2XY=2, the ratio is 62=3\frac{6}{2}=3. If side BC=9BC=9, then corresponding side YZYZ must be 93=3\frac{9}{3}=3.
  • A man who is 6 feet tall casts a 4-foot shadow. A nearby tree casts a 20-foot shadow. Let hh be the tree's height. The ratio is h6=204\frac{h}{6} = \frac{20}{4}, so 4h=1204h = 120, and h=30h=30 feet.

Section 5

The Pythagorean theorem

Property

In any right triangle β–³ABC\triangle ABC,

a2+b2=c2a^2 + b^2 = c^2

where cc is the length of the hypotenuse (the side opposite the right angle) and aa and bb are the lengths of the legs.

Book overview

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Chapter 9: Math Models and Geometry

  1. Lesson 1

    Lesson 1: Use a Problem Solving Strategy

  2. Lesson 2

    Lesson 2: Solve Money Applications

  3. Lesson 3Current

    Lesson 3: Use Properties of Angles, Triangles, and the Pythagorean Theorem

  4. Lesson 4

    Lesson 4: Use Properties of Rectangles, Triangles, and Trapezoids

  5. Lesson 5

    Lesson 5: Solve Geometry Applications: Circles and Irregular Figures

  6. Lesson 6

    Lesson 6: Solve Geometry Applications: Volume and Surface Area

  7. Lesson 7

    Lesson 7: Solve a Formula for a Specific Variable

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Use Properties of Angles, Triangles, and the Pythagorean Theorem

New Concept

This lesson introduces fundamental geometric rules. You'll learn how to use properties of angles, triangles, and the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) to find unknown lengths and angles, setting the stage for solving geometry problems.

What’s next

Now, let's apply these rules. You'll tackle interactive examples and practice problems to master finding missing angles and side lengths.

Section 2

Supplementary and complementary angles

Property

If the sum of the measures of two angles is 180∘180^\circ, then the angles are supplementary.

If ∠A\angle A and ∠B\angle B are supplementary, then m∠A+m∠B=180∘m\angle A + m\angle B = 180^\circ.

If the sum of the measures of two angles is 90∘90^\circ, then the angles are complementary.

Section 3

Sum of the measures of the angles of a triangle

Property

For any β–³ABC\triangle ABC, the sum of the measures of the angles is 180∘180^\circ.

m∠A+m∠B+m∠C=180∘m\angle A + m\angle B + m\angle C = 180^\circ

Examples

  • The measures of two angles of a triangle are 60∘60^\circ and 85∘85^\circ. The third angle, xx, is found by solving 60∘+85∘+x=180∘60^\circ + 85^\circ + x = 180^\circ, which gives 145∘+x=180∘145^\circ + x = 180^\circ, so x=35∘x = 35^\circ.

Section 4

Properties of similar triangles

Property

If two triangles are similar, then their corresponding angle measures are equal and their corresponding side lengths are in the same ratio.

Examples

  • β–³ABC\triangle ABC is similar to β–³XYZ\triangle XYZ. If side AB=6AB=6 and corresponding side XY=2XY=2, the ratio is 62=3\frac{6}{2}=3. If side BC=9BC=9, then corresponding side YZYZ must be 93=3\frac{9}{3}=3.
  • A man who is 6 feet tall casts a 4-foot shadow. A nearby tree casts a 20-foot shadow. Let hh be the tree's height. The ratio is h6=204\frac{h}{6} = \frac{20}{4}, so 4h=1204h = 120, and h=30h=30 feet.

Section 5

The Pythagorean theorem

Property

In any right triangle β–³ABC\triangle ABC,

a2+b2=c2a^2 + b^2 = c^2

where cc is the length of the hypotenuse (the side opposite the right angle) and aa and bb are the lengths of the legs.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Math Models and Geometry

  1. Lesson 1

    Lesson 1: Use a Problem Solving Strategy

  2. Lesson 2

    Lesson 2: Solve Money Applications

  3. Lesson 3Current

    Lesson 3: Use Properties of Angles, Triangles, and the Pythagorean Theorem

  4. Lesson 4

    Lesson 4: Use Properties of Rectangles, Triangles, and Trapezoids

  5. Lesson 5

    Lesson 5: Solve Geometry Applications: Circles and Irregular Figures

  6. Lesson 6

    Lesson 6: Solve Geometry Applications: Volume and Surface Area

  7. Lesson 7

    Lesson 7: Solve a Formula for a Specific Variable