Learn on PengiAoPS: Introduction to Algebra (AMC 8 & 10)Chapter 11: Special Factorizations

Lesson 3: Sum and Difference of Cubes

In this Grade 4 AoPS Introduction to Algebra lesson from Chapter 11, students learn how to factor the sum and difference of cubes using the identities x³ − y³ = (x − y)(x² + xy + y²) and x³ + y³ = (x + y)(x² − xy + y²). The lesson guides students through deriving these factorizations by recognizing patterns in expanded products, then applying logical reasoning to construct the correct quadratic factors. Special attention is given to understanding why each identity works rather than simply memorizing the formulas, helping students avoid common errors when applying these special factorizations.

Section 1

Sum and Difference of Cubes Patterns

Property

  • Sum of Cubes: a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)
  • Difference of Cubes: a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a-b)(a^2 + ab + b^2)

Examples

Section 2

Factor Sums and Differences of Cubes

Property

The patterns for factoring the sum and difference of cubes are:

a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)
a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a-b)(a^2 + ab + b^2)
To factor, confirm the binomial is a sum or difference of perfect cubes. Write the terms as cubes (a3a^3 and b3b^3), then apply the corresponding pattern. The sign of the binomial factor matches the original binomial, while the middle sign of the trinomial factor is the opposite. The resulting trinomial factor is prime.

Examples

  • To factor y3+27y^3 + 27, recognize it as a sum of cubes, y3+33y^3 + 3^3. Applying the sum of cubes pattern gives (y+3)(y23y+9)(y+3)(y^2 - 3y + 9).
  • To factor 8x318x^3 - 1, see it as a difference of cubes, (2x)313(2x)^3 - 1^3. The pattern gives (2x1)((2x)2+(2x)(1)+12)(2x-1)((2x)^2 + (2x)(1) + 1^2), which simplifies to (2x1)(4x2+2x+1)(2x-1)(4x^2 + 2x + 1).

Section 3

Common Errors in Cube Factorization

Property

Common cube factorization errors to avoid:

  • Confusing signs: x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2) vs x3y3=(xy)(x2+xy+y2)x^3 - y^3 = (x - y)(x^2 + xy + y^2)
  • Incorrect quadratic factors: (x+y)(x2+xy+y2)(x + y)(x^2 + xy + y^2) is wrong for sum of cubes
  • Missing the middle term xyxy in the quadratic factor

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 11: Special Factorizations

  1. Lesson 1

    Lesson 1: Squares of Binomials

  2. Lesson 2

    Lesson 2: Difference of Squares

  3. Lesson 3Current

    Lesson 3: Sum and Difference of Cubes

  4. Lesson 4

    Lesson 4: Rationalizing Denominators

  5. Lesson 5

    Lesson 5: Simon's Favorite Factoring Trick

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Sum and Difference of Cubes Patterns

Property

  • Sum of Cubes: a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)
  • Difference of Cubes: a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a-b)(a^2 + ab + b^2)

Examples

Section 2

Factor Sums and Differences of Cubes

Property

The patterns for factoring the sum and difference of cubes are:

a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)
a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a-b)(a^2 + ab + b^2)
To factor, confirm the binomial is a sum or difference of perfect cubes. Write the terms as cubes (a3a^3 and b3b^3), then apply the corresponding pattern. The sign of the binomial factor matches the original binomial, while the middle sign of the trinomial factor is the opposite. The resulting trinomial factor is prime.

Examples

  • To factor y3+27y^3 + 27, recognize it as a sum of cubes, y3+33y^3 + 3^3. Applying the sum of cubes pattern gives (y+3)(y23y+9)(y+3)(y^2 - 3y + 9).
  • To factor 8x318x^3 - 1, see it as a difference of cubes, (2x)313(2x)^3 - 1^3. The pattern gives (2x1)((2x)2+(2x)(1)+12)(2x-1)((2x)^2 + (2x)(1) + 1^2), which simplifies to (2x1)(4x2+2x+1)(2x-1)(4x^2 + 2x + 1).

Section 3

Common Errors in Cube Factorization

Property

Common cube factorization errors to avoid:

  • Confusing signs: x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2) vs x3y3=(xy)(x2+xy+y2)x^3 - y^3 = (x - y)(x^2 + xy + y^2)
  • Incorrect quadratic factors: (x+y)(x2+xy+y2)(x + y)(x^2 + xy + y^2) is wrong for sum of cubes
  • Missing the middle term xyxy in the quadratic factor

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 11: Special Factorizations

  1. Lesson 1

    Lesson 1: Squares of Binomials

  2. Lesson 2

    Lesson 2: Difference of Squares

  3. Lesson 3Current

    Lesson 3: Sum and Difference of Cubes

  4. Lesson 4

    Lesson 4: Rationalizing Denominators

  5. Lesson 5

    Lesson 5: Simon's Favorite Factoring Trick