Learn on PengienVision, Mathematics, Grade 8Chapter 5: Analyze and Solve Systems of Linear Equations

Lesson 3: Solve Systems by Substitution

In this Grade 8 lesson from enVision Mathematics Chapter 5, students learn how to solve systems of linear equations using the substitution method by isolating one variable and substituting its expression into the other equation. The lesson covers all three possible outcomes: one solution, no solution, and infinitely many solutions, helping students recognize what each algebraic result means. Real-world contexts like ticket sales and taxi fare comparisons are used to build understanding of when substitution is the most efficient solving strategy.

Section 1

The Substitution Method

Property

To solve a system by substitution, follow these steps:

  1. Solve one of the equations for either variable.
  2. Substitute the expression from Step 1 into the other equation.
  3. Solve the resulting equation.
  4. Substitute the solution in Step 3 into one of the original equations to find the other variable.
  5. Write the solution as an ordered pair and check that it is a solution to both original equations.

Examples

  • Solve the system y=x+3y = x + 3 and 3x+2y=193x + 2y = 19. Substitute x+3x+3 for yy in the second equation: 3x+2(x+3)=193x + 2(x+3) = 19. This simplifies to 5x+6=195x+6=19, so 5x=135x=13 and x=135x=\frac{13}{5}. Then y=135+3=285y = \frac{13}{5} + 3 = \frac{28}{5}. The solution is (135,285)(\frac{13}{5}, \frac{28}{5}).
  • Solve the system 2xy=82x - y = 8 and x+3y=11x + 3y = 11. From the first equation, solve for yy: y=2x8y = 2x - 8. Substitute this into the second equation: x+3(2x8)=11x + 3(2x-8) = 11. This gives 7x24=117x-24=11, so 7x=357x=35 and x=5x=5. Then y=2(5)8=2y=2(5)-8=2, making the solution (5,2)(5, 2).

Explanation

This method simplifies a two-variable system into a single-variable equation. By isolating a variable in one equation and plugging its expression into the other, you can solve for one variable and then use that value to find the second.

Section 2

Special Cases in Substitution

Property

When using substitution, the variables will sometimes completely cancel each other out. The resulting numerical statement determines the number of solutions and the geometric classification of the system:

  • Identity (True Statement): If solving results in a true statement like 0=00 = 0 or 5=55 = 5, the system has Infinitely Many Solutions. The equations are dependent (they represent the exact same coincident line).
  • Contradiction (False Statement): If solving results in a false statement like 0=100 = -10 or 2=12 = -1, the system has No Solution. The equations are inconsistent (they represent parallel lines).

Examples

  • Infinite Solutions (Identity): Solve y=2x3y = 2x - 3 and 4x2y=64x - 2y = 6.

Substitute yy: 4x2(2x3)=64x - 2(2x - 3) = 6.
Distribute: 4x4x+6=64x - 4x + 6 = 6.
Simplify: 6=66 = 6. This is a true statement, so there are infinitely many solutions.

  • No Solution (Contradiction): Solve y=5x+2y = 5x + 2 and y=5x1y = 5x - 1.

Substitute yy: 5x+2=5x15x + 2 = 5x - 1.
Subtract 5x5x from both sides: 2=12 = -1. This is a false statement, so there is no solution.

Explanation

If your variables vanish during substitution, the algebra is trying to tell you something about the geometry of the lines! A true statement like 6=66 = 6 means the two equations are actually identical twins disguised as different math problems; they overlap perfectly. A false statement like 2=12 = -1 means you have reached a mathematical dead-end because the lines are parallel and will literally never cross.

Book overview

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Continue this chapter

Chapter 5: Analyze and Solve Systems of Linear Equations

  1. Lesson 1

    Lesson 1: Estimate Solutions by Inspection

  2. Lesson 2

    Lesson 2: Solve Systems by Graphing

  3. Lesson 3Current

    Lesson 3: Solve Systems by Substitution

  4. Lesson 4

    Lesson 4: Solve Systems by Elimination

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

The Substitution Method

Property

To solve a system by substitution, follow these steps:

  1. Solve one of the equations for either variable.
  2. Substitute the expression from Step 1 into the other equation.
  3. Solve the resulting equation.
  4. Substitute the solution in Step 3 into one of the original equations to find the other variable.
  5. Write the solution as an ordered pair and check that it is a solution to both original equations.

Examples

  • Solve the system y=x+3y = x + 3 and 3x+2y=193x + 2y = 19. Substitute x+3x+3 for yy in the second equation: 3x+2(x+3)=193x + 2(x+3) = 19. This simplifies to 5x+6=195x+6=19, so 5x=135x=13 and x=135x=\frac{13}{5}. Then y=135+3=285y = \frac{13}{5} + 3 = \frac{28}{5}. The solution is (135,285)(\frac{13}{5}, \frac{28}{5}).
  • Solve the system 2xy=82x - y = 8 and x+3y=11x + 3y = 11. From the first equation, solve for yy: y=2x8y = 2x - 8. Substitute this into the second equation: x+3(2x8)=11x + 3(2x-8) = 11. This gives 7x24=117x-24=11, so 7x=357x=35 and x=5x=5. Then y=2(5)8=2y=2(5)-8=2, making the solution (5,2)(5, 2).

Explanation

This method simplifies a two-variable system into a single-variable equation. By isolating a variable in one equation and plugging its expression into the other, you can solve for one variable and then use that value to find the second.

Section 2

Special Cases in Substitution

Property

When using substitution, the variables will sometimes completely cancel each other out. The resulting numerical statement determines the number of solutions and the geometric classification of the system:

  • Identity (True Statement): If solving results in a true statement like 0=00 = 0 or 5=55 = 5, the system has Infinitely Many Solutions. The equations are dependent (they represent the exact same coincident line).
  • Contradiction (False Statement): If solving results in a false statement like 0=100 = -10 or 2=12 = -1, the system has No Solution. The equations are inconsistent (they represent parallel lines).

Examples

  • Infinite Solutions (Identity): Solve y=2x3y = 2x - 3 and 4x2y=64x - 2y = 6.

Substitute yy: 4x2(2x3)=64x - 2(2x - 3) = 6.
Distribute: 4x4x+6=64x - 4x + 6 = 6.
Simplify: 6=66 = 6. This is a true statement, so there are infinitely many solutions.

  • No Solution (Contradiction): Solve y=5x+2y = 5x + 2 and y=5x1y = 5x - 1.

Substitute yy: 5x+2=5x15x + 2 = 5x - 1.
Subtract 5x5x from both sides: 2=12 = -1. This is a false statement, so there is no solution.

Explanation

If your variables vanish during substitution, the algebra is trying to tell you something about the geometry of the lines! A true statement like 6=66 = 6 means the two equations are actually identical twins disguised as different math problems; they overlap perfectly. A false statement like 2=12 = -1 means you have reached a mathematical dead-end because the lines are parallel and will literally never cross.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Analyze and Solve Systems of Linear Equations

  1. Lesson 1

    Lesson 1: Estimate Solutions by Inspection

  2. Lesson 2

    Lesson 2: Solve Systems by Graphing

  3. Lesson 3Current

    Lesson 3: Solve Systems by Substitution

  4. Lesson 4

    Lesson 4: Solve Systems by Elimination