Learn on PengiYoshiwara Intermediate AlgebraChapter 1: Linear Models

Lesson 3: Intercepts

In this Grade 7 math lesson from Yoshiwara Intermediate Algebra, Chapter 1, students learn how to identify and calculate the x-intercept and y-intercept of a linear equation by setting each variable equal to zero and solving. The lesson also introduces the general form of a linear equation (Ax + By = C) and emphasizes how intercepts carry real-world meaning, such as how far a car can travel before running out of gas.

Section 1

📘 Intercepts

New Concept

Intercepts are the specific points where a graph crosses the axes. We find the yy-intercept by setting x=0x=0 and the xx-intercept by setting y=0y=0. These points reveal key starting values or endpoints in real-world scenarios.

What’s next

Soon, you'll work through interactive examples of finding intercepts. Then, you'll apply this skill to graph lines and solve challenge problems.

Section 2

Intercepts of a graph

Property

The points at which a graph crosses the axes are called the intercepts of the graph.

To find the intercepts of a graph:

  1. To find the xx-intercept, we set y=0y = 0 and solve for xx.
  2. To find the yy-intercept, we set x=0x = 0 and solve for yy.

Examples

  • To find the intercepts of 3x+2y=123x + 2y = 12, first set y=0y=0 to get 3x=123x = 12, so the xx-intercept is (4,0)(4, 0). Then set x=0x=0 to get 2y=122y=12, so the yy-intercept is (0,6)(0, 6).

Section 3

General form for a linear equation

Property

The graphs of the equations we have seen so far are all portions of straight lines. For this reason such equations are called linear equations.

The general form for a linear equation is

Ax+By=CAx + By = C

(where AA and BB cannot both be 0).

Examples

  • A bakery sells muffins for 3 dollars and croissants for 4 dollars. To make 600 dollars in revenue, the equation is 3x+4y=6003x + 4y = 600, where xx is muffins and yy is croissants.

Section 4

Intercept method of graphing

Property

To Graph a Linear Equation by the Intercept Method:
a. Find the horizontal and vertical intercepts.
b. Plot the intercepts, and draw the line through the two points.

Examples

  • To graph 4x+3y=244x + 3y = 24, find the intercepts. Set y=0y=0 to get the xx-intercept (6,0)(6, 0). Set x=0x=0 to get the yy-intercept (0,8)(0, 8). Plot these two points and draw a line through them.
  • Let's graph x−2y=4x - 2y = 4. The xx-intercept is (4,0)(4, 0) and the yy-intercept is (0,−2)(0, -2). Plot these two points on the coordinate plane and draw the line that connects them.

Section 5

Two forms for linear equations

Property

We have now seen two forms for linear equations: the general linear form,

Ax+By=CAx + By = C

and the form for a linear model,

y=(starting value)+(rate)×ty = \text{(starting value)} + \text{(rate)} \times t

Caution: Do not confuse solving for yy in terms of xx with finding the yy-intercept.

Examples

  • To convert 8x−2y=148x - 2y = 14 into the linear model form, we solve for yy. This gives −2y=−8x+14-2y = -8x + 14, which simplifies to y=4x−7y = 4x - 7.
  • To convert y=−14x+2y = -\frac{1}{4}x + 2 to general form, first multiply by 4 to clear the fraction: 4y=−x+84y = -x + 8. Then, add xx to both sides to get x+4y=8x + 4y = 8.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Linear Models

  1. Lesson 1

    Lesson 1: Linear Models

  2. Lesson 2

    Lesson 2: Graphs and Equations

  3. Lesson 3Current

    Lesson 3: Intercepts

  4. Lesson 4

    Lesson 4: Slope

  5. Lesson 5

    Lesson 5: Equations of Lines

  6. Lesson 6

    Lesson 6: Chapter Summary and Review

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Intercepts

New Concept

Intercepts are the specific points where a graph crosses the axes. We find the yy-intercept by setting x=0x=0 and the xx-intercept by setting y=0y=0. These points reveal key starting values or endpoints in real-world scenarios.

What’s next

Soon, you'll work through interactive examples of finding intercepts. Then, you'll apply this skill to graph lines and solve challenge problems.

Section 2

Intercepts of a graph

Property

The points at which a graph crosses the axes are called the intercepts of the graph.

To find the intercepts of a graph:

  1. To find the xx-intercept, we set y=0y = 0 and solve for xx.
  2. To find the yy-intercept, we set x=0x = 0 and solve for yy.

Examples

  • To find the intercepts of 3x+2y=123x + 2y = 12, first set y=0y=0 to get 3x=123x = 12, so the xx-intercept is (4,0)(4, 0). Then set x=0x=0 to get 2y=122y=12, so the yy-intercept is (0,6)(0, 6).

Section 3

General form for a linear equation

Property

The graphs of the equations we have seen so far are all portions of straight lines. For this reason such equations are called linear equations.

The general form for a linear equation is

Ax+By=CAx + By = C

(where AA and BB cannot both be 0).

Examples

  • A bakery sells muffins for 3 dollars and croissants for 4 dollars. To make 600 dollars in revenue, the equation is 3x+4y=6003x + 4y = 600, where xx is muffins and yy is croissants.

Section 4

Intercept method of graphing

Property

To Graph a Linear Equation by the Intercept Method:
a. Find the horizontal and vertical intercepts.
b. Plot the intercepts, and draw the line through the two points.

Examples

  • To graph 4x+3y=244x + 3y = 24, find the intercepts. Set y=0y=0 to get the xx-intercept (6,0)(6, 0). Set x=0x=0 to get the yy-intercept (0,8)(0, 8). Plot these two points and draw a line through them.
  • Let's graph x−2y=4x - 2y = 4. The xx-intercept is (4,0)(4, 0) and the yy-intercept is (0,−2)(0, -2). Plot these two points on the coordinate plane and draw the line that connects them.

Section 5

Two forms for linear equations

Property

We have now seen two forms for linear equations: the general linear form,

Ax+By=CAx + By = C

and the form for a linear model,

y=(starting value)+(rate)×ty = \text{(starting value)} + \text{(rate)} \times t

Caution: Do not confuse solving for yy in terms of xx with finding the yy-intercept.

Examples

  • To convert 8x−2y=148x - 2y = 14 into the linear model form, we solve for yy. This gives −2y=−8x+14-2y = -8x + 14, which simplifies to y=4x−7y = 4x - 7.
  • To convert y=−14x+2y = -\frac{1}{4}x + 2 to general form, first multiply by 4 to clear the fraction: 4y=−x+84y = -x + 8. Then, add xx to both sides to get x+4y=8x + 4y = 8.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Linear Models

  1. Lesson 1

    Lesson 1: Linear Models

  2. Lesson 2

    Lesson 2: Graphs and Equations

  3. Lesson 3Current

    Lesson 3: Intercepts

  4. Lesson 4

    Lesson 4: Slope

  5. Lesson 5

    Lesson 5: Equations of Lines

  6. Lesson 6

    Lesson 6: Chapter Summary and Review