Learn on PengiBig Ideas Math, Algebra 1Chapter 1: Solving Linear Equations

Lesson 2: Solving Multi-Step Equations

Property To solve an equation with two or more operations, we must isolate the variable on one side of the equation. We undo the operations in reverse order. Typically, we undo addition or subtraction first, before undoing multiplication or division.

Section 1

Equations with Two Operations

Property

To solve an equation with two or more operations, we must isolate the variable on one side of the equation. We undo the operations in reverse order. Typically, we undo addition or subtraction first, before undoing multiplication or division.

Examples

  • To solve 4x+5=294x + 5 = 29, first subtract 5 from both sides to get 4x=244x = 24. Then, divide both sides by 4 to find x=6x = 6.
  • To solve y32=7\frac{y}{3} - 2 = 7, first add 2 to both sides to get y3=9\frac{y}{3} = 9. Then, multiply both sides by 3 to find y=27y = 27.
  • To solve 18=6+2z18 = 6 + 2z, first subtract 6 from both sides to get 12=2z12 = 2z. Then, divide both sides by 2 to find z=6z = 6.

Explanation

Think of it as reversing your morning routine. To get back to the start, you undo the last thing you did first. In equations, this means handling addition or subtraction before dealing with multiplication or division to isolate the variable.

Section 2

The Distributive Law

Property

If aa, bb, and cc are any numbers, then

a(b+c)=ab+aca(b + c) = ab + ac

Steps for Solving Linear Equations.

  1. Use the distributive law to remove any parentheses.
  2. Combine like terms on each side of the equation.
  3. By adding or subtracting the same quantity on both sides of the equation, get all the variable terms on one side and all the constant terms on the other.
  4. Divide both sides by the coefficient of the variable to obtain an equation of the form x=ax = a.

Examples

  • To simplify 5(x+3)5(x+3), you distribute the 5 to both xx and 3. This gives 5x+535 \cdot x + 5 \cdot 3, which simplifies to 5x+155x+15.
  • To simplify 6(2a4)+76(2a-4) + 7, first distribute the 6 to get 12a24+712a - 24 + 7. Then, combine the constant terms to get the final expression 12a1712a - 17.
  • To solve the equation 3(y2)=93(y-2) = 9, first distribute the 3 to get 3y6=93y - 6 = 9. Add 6 to both sides to get 3y=153y = 15, then divide by 3 to find y=5y=5.

Explanation

Think of this law as 'distributing' the term outside the parentheses to every term inside. It helps break down multiplication with a group of terms, turning one complex multiplication into several simpler ones.

Book overview

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Chapter 1: Solving Linear Equations

  1. Lesson 1

    Lesson 1: Solving Simple Equations

  2. Lesson 2Current

    Lesson 2: Solving Multi-Step Equations

  3. Lesson 3

    Lesson 3: Solving Equations with Variables on Both Sides

  4. Lesson 4

    Lesson 4: Solving Absolute Value Equations

  5. Lesson 5

    Lesson 5: Rewriting Equations and Formulas

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Equations with Two Operations

Property

To solve an equation with two or more operations, we must isolate the variable on one side of the equation. We undo the operations in reverse order. Typically, we undo addition or subtraction first, before undoing multiplication or division.

Examples

  • To solve 4x+5=294x + 5 = 29, first subtract 5 from both sides to get 4x=244x = 24. Then, divide both sides by 4 to find x=6x = 6.
  • To solve y32=7\frac{y}{3} - 2 = 7, first add 2 to both sides to get y3=9\frac{y}{3} = 9. Then, multiply both sides by 3 to find y=27y = 27.
  • To solve 18=6+2z18 = 6 + 2z, first subtract 6 from both sides to get 12=2z12 = 2z. Then, divide both sides by 2 to find z=6z = 6.

Explanation

Think of it as reversing your morning routine. To get back to the start, you undo the last thing you did first. In equations, this means handling addition or subtraction before dealing with multiplication or division to isolate the variable.

Section 2

The Distributive Law

Property

If aa, bb, and cc are any numbers, then

a(b+c)=ab+aca(b + c) = ab + ac

Steps for Solving Linear Equations.

  1. Use the distributive law to remove any parentheses.
  2. Combine like terms on each side of the equation.
  3. By adding or subtracting the same quantity on both sides of the equation, get all the variable terms on one side and all the constant terms on the other.
  4. Divide both sides by the coefficient of the variable to obtain an equation of the form x=ax = a.

Examples

  • To simplify 5(x+3)5(x+3), you distribute the 5 to both xx and 3. This gives 5x+535 \cdot x + 5 \cdot 3, which simplifies to 5x+155x+15.
  • To simplify 6(2a4)+76(2a-4) + 7, first distribute the 6 to get 12a24+712a - 24 + 7. Then, combine the constant terms to get the final expression 12a1712a - 17.
  • To solve the equation 3(y2)=93(y-2) = 9, first distribute the 3 to get 3y6=93y - 6 = 9. Add 6 to both sides to get 3y=153y = 15, then divide by 3 to find y=5y=5.

Explanation

Think of this law as 'distributing' the term outside the parentheses to every term inside. It helps break down multiplication with a group of terms, turning one complex multiplication into several simpler ones.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Solving Linear Equations

  1. Lesson 1

    Lesson 1: Solving Simple Equations

  2. Lesson 2Current

    Lesson 2: Solving Multi-Step Equations

  3. Lesson 3

    Lesson 3: Solving Equations with Variables on Both Sides

  4. Lesson 4

    Lesson 4: Solving Absolute Value Equations

  5. Lesson 5

    Lesson 5: Rewriting Equations and Formulas