Learn on PengiIllustrative Mathematics, Grade 6Unit 1 Area and Surface Area

Lesson 2: Parallelograms

In this Grade 6 Illustrative Mathematics lesson from Unit 1: Area and Surface Area, students explore the defining properties of parallelograms — including parallel opposite sides, equal opposite side lengths, and equal opposite angles — and learn how to calculate their area. Students practice decomposing a parallelogram into a rectangle by rearranging pieces, and apply the base times height formula to find areas of parallelograms with given dimensions.

Section 1

Properties of Parallelograms

Property

A parallelogram is a quadrilateral with two pairs of opposite sides that are parallel, which gives it the following properties:

  • Opposite sides are congruent (equal in length).
  • Opposite angles are congruent (equal in measure).
  • Consecutive angles are supplementary (their sum is 180180^\circ).
  • The diagonals bisect each other (they cut each other into two equal halves).

Examples

Section 2

Visual Methods for Finding Parallelogram Area

Property

The area of a parallelogram can be determined without the formula using two visual methods:

  1. Decomposition: Decompose the parallelogram into a triangle and a trapezoid. Rearrange these pieces to form a rectangle. The area is the length times the width of this new rectangle.
  2. Enclosure: Enclose the parallelogram within a larger rectangle. The area of the parallelogram is the area of the enclosing rectangle minus the areas of the two congruent right triangles formed at either end.

Examples

  • Decomposition: A parallelogram has a base of 88 units and a height of 55 units. By cutting a right triangle from one side and moving it to the other, we form a rectangle with dimensions 8×58 \times 5. The area is 8×5=408 \times 5 = 40 square units.
  • Enclosure: A parallelogram with a base of 1010 units and a height of 66 units is enclosed in a rectangle. The rectangle has a width of 10+4=1410+4=14 units and a height of 66 units. The area of the parallelogram is the area of the rectangle minus the area of the two triangles: (14×6)2×(12×4×6)=8424=60(14 \times 6) - 2 \times (\frac{1}{2} \times 4 \times 6) = 84 - 24 = 60 square units.

Explanation

These methods demonstrate why the area formula for a parallelogram works. The decomposition method transforms the parallelogram into a rectangle with the same base, height, and area. The enclosure method calculates the area indirectly by subtracting the excess area from a larger, simpler shape. Both techniques are powerful visual strategies for understanding the concept of area conservation.

Section 3

Area of a Parallelogram

Property

A parallelogram can be rearranged into a rectangle with the same base and height. Choose any side of the parallelogram as the base (length bb), and let hh be the perpendicular distance between the base and the opposite side.
The area is given by the formula:

Area=bh\operatorname{Area} = bh

Examples

  • A parallelogram has a base of 12 cm and a height of 5 cm. Its area is 12×5=6012 \times 5 = 60 square cm.
  • A section of a patio is shaped like a parallelogram with a base of 8 feet and a height of 6 feet. The area is 8×6=488 \times 6 = 48 square feet.
  • Even if the slanted side is 9 inches, if the base is 15 inches and the height is 7 inches, the area is 15×7=10515 \times 7 = 105 square inches.

Explanation

Think of a parallelogram as a slanted rectangle. By slicing off a triangle from one end and moving it to the other, you create a perfect rectangle. This new rectangle has the same base and height, which is why the area formula works!

Book overview

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Unit 1 Area and Surface Area

  1. Lesson 1

    Lesson 1: Reasoning to Find Area

  2. Lesson 2Current

    Lesson 2: Parallelograms

  3. Lesson 3

    Lesson 3: Triangles

  4. Lesson 4

    Lesson 4: Polygons

  5. Lesson 5

    Lesson 5: Surface Area

  6. Lesson 6

    Lesson 6: Squares and Cubes

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Properties of Parallelograms

Property

A parallelogram is a quadrilateral with two pairs of opposite sides that are parallel, which gives it the following properties:

  • Opposite sides are congruent (equal in length).
  • Opposite angles are congruent (equal in measure).
  • Consecutive angles are supplementary (their sum is 180180^\circ).
  • The diagonals bisect each other (they cut each other into two equal halves).

Examples

Section 2

Visual Methods for Finding Parallelogram Area

Property

The area of a parallelogram can be determined without the formula using two visual methods:

  1. Decomposition: Decompose the parallelogram into a triangle and a trapezoid. Rearrange these pieces to form a rectangle. The area is the length times the width of this new rectangle.
  2. Enclosure: Enclose the parallelogram within a larger rectangle. The area of the parallelogram is the area of the enclosing rectangle minus the areas of the two congruent right triangles formed at either end.

Examples

  • Decomposition: A parallelogram has a base of 88 units and a height of 55 units. By cutting a right triangle from one side and moving it to the other, we form a rectangle with dimensions 8×58 \times 5. The area is 8×5=408 \times 5 = 40 square units.
  • Enclosure: A parallelogram with a base of 1010 units and a height of 66 units is enclosed in a rectangle. The rectangle has a width of 10+4=1410+4=14 units and a height of 66 units. The area of the parallelogram is the area of the rectangle minus the area of the two triangles: (14×6)2×(12×4×6)=8424=60(14 \times 6) - 2 \times (\frac{1}{2} \times 4 \times 6) = 84 - 24 = 60 square units.

Explanation

These methods demonstrate why the area formula for a parallelogram works. The decomposition method transforms the parallelogram into a rectangle with the same base, height, and area. The enclosure method calculates the area indirectly by subtracting the excess area from a larger, simpler shape. Both techniques are powerful visual strategies for understanding the concept of area conservation.

Section 3

Area of a Parallelogram

Property

A parallelogram can be rearranged into a rectangle with the same base and height. Choose any side of the parallelogram as the base (length bb), and let hh be the perpendicular distance between the base and the opposite side.
The area is given by the formula:

Area=bh\operatorname{Area} = bh

Examples

  • A parallelogram has a base of 12 cm and a height of 5 cm. Its area is 12×5=6012 \times 5 = 60 square cm.
  • A section of a patio is shaped like a parallelogram with a base of 8 feet and a height of 6 feet. The area is 8×6=488 \times 6 = 48 square feet.
  • Even if the slanted side is 9 inches, if the base is 15 inches and the height is 7 inches, the area is 15×7=10515 \times 7 = 105 square inches.

Explanation

Think of a parallelogram as a slanted rectangle. By slicing off a triangle from one end and moving it to the other, you create a perfect rectangle. This new rectangle has the same base and height, which is why the area formula works!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Unit 1 Area and Surface Area

  1. Lesson 1

    Lesson 1: Reasoning to Find Area

  2. Lesson 2Current

    Lesson 2: Parallelograms

  3. Lesson 3

    Lesson 3: Triangles

  4. Lesson 4

    Lesson 4: Polygons

  5. Lesson 5

    Lesson 5: Surface Area

  6. Lesson 6

    Lesson 6: Squares and Cubes