Learn on PengienVision, Algebra 2Chapter 6: Exponential and Logarithmic Functions

Lesson 2: Exponential Models

In this Grade 11 enVision Algebra 2 lesson, students learn to write and rewrite exponential models to solve real-world problems, including converting annual growth rates to monthly or quarterly rates using the Power of a Power rule. The lesson introduces the compound interest formula A = P(1 + r/n)^nt and the continuously compounded interest formula using the natural base e, showing how compounding frequency affects investment growth. Students apply these models to population growth and financial scenarios drawn from Chapter 6 on Exponential and Logarithmic Functions.

Section 1

Rewriting Exponential Functions for Different Time Periods

Property

To reveal growth rates for different time periods, rewrite y=abxy = a \cdot b^x by multiplying the exponent by nn\frac{n}{n}:

y=abx=a(b1n)nxy = a \cdot b^x = a \cdot (b^{\frac{1}{n}})^{nx}

This shows the growth factor for 1n\frac{1}{n} of the original time unit.

Section 2

Compound Interest as Exponential Model

Property

Compound interest follows an exponential model where the amount AA after tt time periods is given by

A=P(1+r)tA = P(1 + r)^t

where PP is the principal (initial amount), rr is the interest rate per period, and tt is the number of time periods. This is a specific case of the general exponential model y=abxy = ab^x where a=Pa = P and b=(1+r)b = (1 + r).

Examples

Section 3

Continuous Compounding

Property

When interest is compounded continuously, the amount A(t)A(t) in an account after tt years is given by the function

A(t)=PertA(t) = Pe^{rt}
where PP is the principal invested and rr is the annual interest rate expressed as a decimal.

Examples

  • If you invest 2000 dollars at 4% interest compounded continuously, the value of your account after tt years is A(t)=2000e0.04tA(t) = 2000e^{0.04t}.
  • To find how long it takes for a 1000 dollar investment to double to 2000 dollars at 6% interest compounded continuously, you solve the equation 2000=1000e0.06t2000 = 1000e^{0.06t}.
  • The value of a 5000 dollar investment after 8 years at 3.5% interest compounded continuously is A(8)=5000e0.035(8)6615.65A(8) = 5000e^{0.035(8)} \approx 6615.65 dollars.

Explanation

Continuous compounding is the theoretical limit of earning interest. It's as if interest is being calculated and added to your balance at every single moment. This formula gives the maximum amount of money an investment can earn at a given rate.

Book overview

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Chapter 6: Exponential and Logarithmic Functions

  1. Lesson 1

    Lesson 1: Key Features of Exponential Functions

  2. Lesson 2Current

    Lesson 2: Exponential Models

  3. Lesson 3

    Lesson 3: Logarithms

  4. Lesson 4

    Lesson 4: Logarithmic Functions

  5. Lesson 5

    Lesson 5: Properties of Logarithms

  6. Lesson 6

    Lesson 6: Exponential and Logarithmic Equations

  7. Lesson 7

    Lesson 7: Geometric Sequences and Series

Lesson overview

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Section 1

Rewriting Exponential Functions for Different Time Periods

Property

To reveal growth rates for different time periods, rewrite y=abxy = a \cdot b^x by multiplying the exponent by nn\frac{n}{n}:

y=abx=a(b1n)nxy = a \cdot b^x = a \cdot (b^{\frac{1}{n}})^{nx}

This shows the growth factor for 1n\frac{1}{n} of the original time unit.

Section 2

Compound Interest as Exponential Model

Property

Compound interest follows an exponential model where the amount AA after tt time periods is given by

A=P(1+r)tA = P(1 + r)^t

where PP is the principal (initial amount), rr is the interest rate per period, and tt is the number of time periods. This is a specific case of the general exponential model y=abxy = ab^x where a=Pa = P and b=(1+r)b = (1 + r).

Examples

Section 3

Continuous Compounding

Property

When interest is compounded continuously, the amount A(t)A(t) in an account after tt years is given by the function

A(t)=PertA(t) = Pe^{rt}
where PP is the principal invested and rr is the annual interest rate expressed as a decimal.

Examples

  • If you invest 2000 dollars at 4% interest compounded continuously, the value of your account after tt years is A(t)=2000e0.04tA(t) = 2000e^{0.04t}.
  • To find how long it takes for a 1000 dollar investment to double to 2000 dollars at 6% interest compounded continuously, you solve the equation 2000=1000e0.06t2000 = 1000e^{0.06t}.
  • The value of a 5000 dollar investment after 8 years at 3.5% interest compounded continuously is A(8)=5000e0.035(8)6615.65A(8) = 5000e^{0.035(8)} \approx 6615.65 dollars.

Explanation

Continuous compounding is the theoretical limit of earning interest. It's as if interest is being calculated and added to your balance at every single moment. This formula gives the maximum amount of money an investment can earn at a given rate.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Exponential and Logarithmic Functions

  1. Lesson 1

    Lesson 1: Key Features of Exponential Functions

  2. Lesson 2Current

    Lesson 2: Exponential Models

  3. Lesson 3

    Lesson 3: Logarithms

  4. Lesson 4

    Lesson 4: Logarithmic Functions

  5. Lesson 5

    Lesson 5: Properties of Logarithms

  6. Lesson 6

    Lesson 6: Exponential and Logarithmic Equations

  7. Lesson 7

    Lesson 7: Geometric Sequences and Series