Learn on PengiAoPS: Introduction to Algebra (AMC 8 & 10)Chapter 13: Quadratic Equations - Part 2

Lesson 13.1: Squares of Binomials Revisited

In this Grade 4 AMC Math lesson from AoPS Introduction to Algebra, students revisit the perfect square identity a² + 2ab + b² = (a + b)² and learn how it leads to the technique of completing the square for solving quadratic equations. Working through Chapter 13, students practice isolating squared binomials, taking square roots to find real and imaginary solutions, and identifying when a quadratic is a perfect square trinomial. The lesson builds directly on prior factoring methods from Chapter 10 to handle quadratics that are difficult or impossible to factor.

Section 1

Complete the Square of x^2 + bx

Property

To complete the square of x2+bxx^2 + bx:

Step 1. Identify bb, the coefficient of xx.

Step 2. Find (12b)2(\frac{1}{2}b)^2, the number to complete the square.

Section 2

More Extraction of Roots

Property

We can use extraction of roots to solve quadratic equations of the form

a(xp)2=qa(x - p)^2 = q

We start by isolating the squared expression, (xp)2(x - p)^2.

Examples

  • To solve 5(x3)2=1255(x - 3)^2 = 125, first divide by 5 to get (x3)2=25(x - 3)^2 = 25. Take the square root: x3=±5x - 3 = ±5. This gives two equations: x3=5x-3=5 (so x=8x=8) and x3=5x-3=-5 (so x=2x=-2).
  • To solve 2(x+4)28=02(x+4)^2 - 8 = 0, add 8 and divide by 2 to get (x+4)2=4(x+4)^2=4. Take the square root: x+4=±2x+4 = ±2. The solutions are x=2x=-2 and x=6x=-6.
  • In 3(x+1)2=75-3(x+1)^2 = -75, divide by -3 to get (x+1)2=25(x+1)^2=25. Take the square root: x+1=±5x+1 = ±5. The solutions are x=4x=4 and x=6x=-6.

Explanation

This method extends extraction of roots to cases where an entire expression in parentheses is squared. The strategy is the same: treat the squared parenthesis as a single block, isolate it, take the square root of both sides, and then solve for xx.

Book overview

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Chapter 13: Quadratic Equations - Part 2

  1. Lesson 1Current

    Lesson 13.1: Squares of Binomials Revisited

  2. Lesson 2

    Lesson 13.2: Completing the Square

  3. Lesson 3

    Lesson 13.3: The Quadratic Formula

  4. Lesson 4

    Lesson 13.4: Applications and Extensions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Complete the Square of x^2 + bx

Property

To complete the square of x2+bxx^2 + bx:

Step 1. Identify bb, the coefficient of xx.

Step 2. Find (12b)2(\frac{1}{2}b)^2, the number to complete the square.

Section 2

More Extraction of Roots

Property

We can use extraction of roots to solve quadratic equations of the form

a(xp)2=qa(x - p)^2 = q

We start by isolating the squared expression, (xp)2(x - p)^2.

Examples

  • To solve 5(x3)2=1255(x - 3)^2 = 125, first divide by 5 to get (x3)2=25(x - 3)^2 = 25. Take the square root: x3=±5x - 3 = ±5. This gives two equations: x3=5x-3=5 (so x=8x=8) and x3=5x-3=-5 (so x=2x=-2).
  • To solve 2(x+4)28=02(x+4)^2 - 8 = 0, add 8 and divide by 2 to get (x+4)2=4(x+4)^2=4. Take the square root: x+4=±2x+4 = ±2. The solutions are x=2x=-2 and x=6x=-6.
  • In 3(x+1)2=75-3(x+1)^2 = -75, divide by -3 to get (x+1)2=25(x+1)^2=25. Take the square root: x+1=±5x+1 = ±5. The solutions are x=4x=4 and x=6x=-6.

Explanation

This method extends extraction of roots to cases where an entire expression in parentheses is squared. The strategy is the same: treat the squared parenthesis as a single block, isolate it, take the square root of both sides, and then solve for xx.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 13: Quadratic Equations - Part 2

  1. Lesson 1Current

    Lesson 13.1: Squares of Binomials Revisited

  2. Lesson 2

    Lesson 13.2: Completing the Square

  3. Lesson 3

    Lesson 13.3: The Quadratic Formula

  4. Lesson 4

    Lesson 13.4: Applications and Extensions