Learn on PengiAoPS: Introduction to Algebra (AMC 8 & 10)Chapter 9: Introduction to Inequalities

Lesson 1: The Basics

In this Grade 4 AMC math lesson from AoPS: Introduction to Algebra, students learn the fundamental rules for manipulating inequalities, including the transitive property, addition and subtraction properties, and how multiplying or dividing by a negative number reverses the inequality sign. The lesson also covers how exponents and roots apply to inequalities and introduces inequality chains. These concepts build directly on students' prior work with equations in preparation for AMC 8 and AMC 10 competition problem solving.

Section 1

Transitivity Property of Inequalities

Property

If a>ba > b and b>cb > c, then a>ca > c. This property also applies to other inequality symbols: if a<ba < b and b<cb < c, then a<ca < c; if aba \geq b and bcb \geq c, then aca \geq c; if aba \leq b and bcb \leq c, then aca \leq c.

Examples

Section 2

Addition and Subtraction Properties of Inequality

Property

Subtraction Property of Inequality
For any numbers aa, bb, and cc,
if a<ba < b, then ac<bca - c < b - c.
if a>ba > b, then ac>bca - c > b - c.

Addition Property of Inequality
For any numbers aa, bb, and cc,
if a<ba < b, then a+c<b+ca + c < b + c.
if a>ba > b, then a+c>b+ca + c > b + c.

Examples

  • To solve x+715x + 7 \leq 15, subtract 7 from both sides. This gives x8x \leq 8. The solution is all numbers less than or equal to 8, or (,8](-\infty, 8].

Section 3

Multiplication and Division Properties of Inequality

Property

For any real numbers aa, bb, cc
if a<ba < b and c>0c > 0, then ac<bc\frac{a}{c} < \frac{b}{c} and ac<bcac < bc.
if a>ba > b and c>0c > 0, then ac>bc\frac{a}{c} > \frac{b}{c} and ac>bcac > bc.
if a<ba < b and c<0c < 0, then ac>bc\frac{a}{c} > \frac{b}{c} and ac>bcac > bc.
if a>ba > b and c<0c < 0, then ac<bc\frac{a}{c} < \frac{b}{c} and ac<bcac < bc.
When we divide or multiply an inequality by a:
positive number, the inequality stays the same.
negative number, the inequality reverses.

Examples

  • To solve 6x>486x > 48, divide both sides by 6. Since 6 is positive, the inequality stays the same: x>8x > 8.
  • To solve 4y20-4y \geq 20, divide both sides by -4. Since -4 is negative, the inequality reverses: y5y \leq -5.

Book overview

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Chapter 9: Introduction to Inequalities

  1. Lesson 1Current

    Lesson 1: The Basics

  2. Lesson 2

    Lesson 2: Which is Greater?

  3. Lesson 3

    Lesson 3: Linear Inequalities

  4. Lesson 4

    Lesson 4: Graphing Inequalities

  5. Lesson 5

    Lesson 5: Optimization

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Transitivity Property of Inequalities

Property

If a>ba > b and b>cb > c, then a>ca > c. This property also applies to other inequality symbols: if a<ba < b and b<cb < c, then a<ca < c; if aba \geq b and bcb \geq c, then aca \geq c; if aba \leq b and bcb \leq c, then aca \leq c.

Examples

Section 2

Addition and Subtraction Properties of Inequality

Property

Subtraction Property of Inequality
For any numbers aa, bb, and cc,
if a<ba < b, then ac<bca - c < b - c.
if a>ba > b, then ac>bca - c > b - c.

Addition Property of Inequality
For any numbers aa, bb, and cc,
if a<ba < b, then a+c<b+ca + c < b + c.
if a>ba > b, then a+c>b+ca + c > b + c.

Examples

  • To solve x+715x + 7 \leq 15, subtract 7 from both sides. This gives x8x \leq 8. The solution is all numbers less than or equal to 8, or (,8](-\infty, 8].

Section 3

Multiplication and Division Properties of Inequality

Property

For any real numbers aa, bb, cc
if a<ba < b and c>0c > 0, then ac<bc\frac{a}{c} < \frac{b}{c} and ac<bcac < bc.
if a>ba > b and c>0c > 0, then ac>bc\frac{a}{c} > \frac{b}{c} and ac>bcac > bc.
if a<ba < b and c<0c < 0, then ac>bc\frac{a}{c} > \frac{b}{c} and ac>bcac > bc.
if a>ba > b and c<0c < 0, then ac<bc\frac{a}{c} < \frac{b}{c} and ac<bcac < bc.
When we divide or multiply an inequality by a:
positive number, the inequality stays the same.
negative number, the inequality reverses.

Examples

  • To solve 6x>486x > 48, divide both sides by 6. Since 6 is positive, the inequality stays the same: x>8x > 8.
  • To solve 4y20-4y \geq 20, divide both sides by -4. Since -4 is negative, the inequality reverses: y5y \leq -5.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Introduction to Inequalities

  1. Lesson 1Current

    Lesson 1: The Basics

  2. Lesson 2

    Lesson 2: Which is Greater?

  3. Lesson 3

    Lesson 3: Linear Inequalities

  4. Lesson 4

    Lesson 4: Graphing Inequalities

  5. Lesson 5

    Lesson 5: Optimization