Learn on PengiEureka Math, Grade 5Chapter 12: Partial Quotients and Multi-Digit Whole Number Division

Lesson 1: Divide two- and three-digit dividends by multiples of 10 with single-digit quotients, and make connections to a written method.

In this Grade 5 Eureka Math lesson, students learn to divide two- and three-digit dividends by multiples of 10 to get single-digit quotients, using estimation strategies and basic multiplication facts to simplify problems like 70 ÷ 30 and 90 ÷ 40. Students practice connecting their estimated quotients to the standard long division algorithm, including identifying remainders and verifying answers. This lesson from Chapter 12 builds foundational skills for multi-digit whole number division with two-digit divisors.

Section 1

Estimate Partial Quotients Using Multiples of 10

Property

To estimate the quotient when dividing by a multiple of 10, use basic division facts. Think of the dividend and divisor in terms of tens.
For example, to solve 84÷2084 \div 20, you can think of it as 8 tens÷2 tens8 \text{ tens} \div 2 \text{ tens}, which simplifies to 8÷28 \div 2.

Examples

  • To estimate 72÷3072 \div 30, think: How many 3s are in 7? The answer is 2. So, 72÷30272 \div 30 \approx 2. (60÷30=260 \div 30 = 2)
  • To estimate 154÷50154 \div 50, think: How many 5s are in 15? The answer is 3. So, 154÷503154 \div 50 \approx 3. (150÷50=3150 \div 50 = 3)
  • To estimate 430÷60430 \div 60, think: How many 6s are in 43? The answer is 7. So, 430÷607430 \div 60 \approx 7. (420÷60=7420 \div 60 = 7)

Explanation

Estimating helps you find an answer that is close to the exact quotient before you start long division. By using basic facts, you can simplify the problem and make a reasonable guess. This strategy is useful for determining the first digit of your quotient in the standard algorithm. It also helps you check if your final answer makes sense.

Section 2

Standard Algorithm for Division by Multiples of 10

Property

To divide a dividend by a divisor using the standard algorithm, we find a quotient (qq) and a remainder (rr) such that

(Divisor×q)+r=Dividend,(\text{Divisor} \times q) + r = \text{Dividend},
where the remainder must be less than the divisor (0r<Divisor0 \leq r < \text{Divisor}).

Examples

Book overview

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Chapter 12: Partial Quotients and Multi-Digit Whole Number Division

  1. Lesson 1Current

    Lesson 1: Divide two- and three-digit dividends by multiples of 10 with single-digit quotients, and make connections to a written method.

  2. Lesson 2

    Lesson 2: Divide two- and three-digit dividends by two-digit divisors with single-digit quotients, and make connections to a written method.

  3. Lesson 3

    Lesson 3: Divide two- and three-digit dividends by two-digit divisors with single-digit quotients, and make connections to a written method.

  4. Lesson 4

    Lesson 4: Divide three- and four-digit dividends by two-digit divisors resulting in two- and three-digit quotients, reasoning about the decomposition of successive remainders in each place value.

  5. Lesson 5

    Lesson 5: Divide three- and four-digit dividends by two-digit divisors resulting in two- and three-digit quotients, reasoning about the decomposition of successive remainders in each place value.

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Estimate Partial Quotients Using Multiples of 10

Property

To estimate the quotient when dividing by a multiple of 10, use basic division facts. Think of the dividend and divisor in terms of tens.
For example, to solve 84÷2084 \div 20, you can think of it as 8 tens÷2 tens8 \text{ tens} \div 2 \text{ tens}, which simplifies to 8÷28 \div 2.

Examples

  • To estimate 72÷3072 \div 30, think: How many 3s are in 7? The answer is 2. So, 72÷30272 \div 30 \approx 2. (60÷30=260 \div 30 = 2)
  • To estimate 154÷50154 \div 50, think: How many 5s are in 15? The answer is 3. So, 154÷503154 \div 50 \approx 3. (150÷50=3150 \div 50 = 3)
  • To estimate 430÷60430 \div 60, think: How many 6s are in 43? The answer is 7. So, 430÷607430 \div 60 \approx 7. (420÷60=7420 \div 60 = 7)

Explanation

Estimating helps you find an answer that is close to the exact quotient before you start long division. By using basic facts, you can simplify the problem and make a reasonable guess. This strategy is useful for determining the first digit of your quotient in the standard algorithm. It also helps you check if your final answer makes sense.

Section 2

Standard Algorithm for Division by Multiples of 10

Property

To divide a dividend by a divisor using the standard algorithm, we find a quotient (qq) and a remainder (rr) such that

(Divisor×q)+r=Dividend,(\text{Divisor} \times q) + r = \text{Dividend},
where the remainder must be less than the divisor (0r<Divisor0 \leq r < \text{Divisor}).

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 12: Partial Quotients and Multi-Digit Whole Number Division

  1. Lesson 1Current

    Lesson 1: Divide two- and three-digit dividends by multiples of 10 with single-digit quotients, and make connections to a written method.

  2. Lesson 2

    Lesson 2: Divide two- and three-digit dividends by two-digit divisors with single-digit quotients, and make connections to a written method.

  3. Lesson 3

    Lesson 3: Divide two- and three-digit dividends by two-digit divisors with single-digit quotients, and make connections to a written method.

  4. Lesson 4

    Lesson 4: Divide three- and four-digit dividends by two-digit divisors resulting in two- and three-digit quotients, reasoning about the decomposition of successive remainders in each place value.

  5. Lesson 5

    Lesson 5: Divide three- and four-digit dividends by two-digit divisors resulting in two- and three-digit quotients, reasoning about the decomposition of successive remainders in each place value.