Learn on PengiReveal Math, Course 1Module 6: Equations and Inequalities

6-1 Use Substitution to Solve One-Step Equations

In Grade 6 Reveal Math (Course 1), Lesson 6-1 introduces students to equations and the concept of a solution, teaching them how to use substitution and the guess, check, and revise strategy to determine whether a given value makes a one-step equation true. Students practice testing candidate values in equations involving addition, subtraction, and multiplication with decimals and fractions. This lesson is part of Module 6: Equations and Inequalities.

Section 1

Distinguishing Between Expressions and Equations

Property

An expression is a mathematical phrase that contains numbers, variables, and operations but has no equal sign: 3x+53x + 5 or 2y72y - 7.

An equation is a mathematical sentence that shows two expressions are equal using an equal sign: 3x+5=143x + 5 = 14 or 2y7=112y - 7 = 11.

Section 2

Determining Solutions by Substitution

Property

A solution of an equation is a value of a variable that makes a true statement when substituted into the equation.
To determine whether a number is a solution to an equation:

Step 1. Substitute the number for the variable in the equation.
Step 2. Simplify the expressions on both sides of the equation.
Step 3. Determine whether the resulting equation is true.

  • If it is true, the number is a solution.
  • If it is not true, the number is not a solution.

Examples

  • Is x=5x=5 a solution to the equation 3x5=103x - 5 = 10? We substitute 3(5)5=155=103(5) - 5 = 15 - 5 = 10. Since 10=1010 = 10, it is a solution.
  • Is y=2y=-2 a solution to the equation 4y+9=2y4y + 9 = 2y? We substitute 4(2)+9=8+9=14(-2) + 9 = -8 + 9 = 1 on the left, and 2(2)=42(-2) = -4 on the right. Since 141 \neq -4, it is not a solution.
  • Is a=13a = \frac{1}{3} a solution to the equation 9a+2=59a + 2 = 5? We substitute 9(13)+2=3+2=59(\frac{1}{3}) + 2 = 3 + 2 = 5. Since 5=55=5, it is a solution.

Section 3

Guess and Check

Property

A problem-solving strategy where you make a reasonable guess, check if it fits the problem's conditions, and revise your guess if it is wrong. Repeat the process until you find the correct answer.

Examples

  • Problem: Two numbers add to 20 and their difference is 6. Guess: 10 and 10. Check: 1010=010-10=0. Revise: 13 and 7. Check: 13+7=2013+7=20 and 137=613-7=6. Correct!
  • Problem: A toy costs 45 cents. You pay with 10 coins (nickels and dimes). Guess: 5 nickels, 5 dimes = 75 cents. Revise: 7 nickels, 3 dimes = 65 cents. Revise again: 9 nickels, 1 dime = 55 cents.

Explanation

Think of yourself as a super sleuth! Make a smart guess to crack the case, check your clues, and if you're wrong, just try another angle. Every guess gets you closer to the solution, detective!

Book overview

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Module 6: Equations and Inequalities

  1. Lesson 1Current

    6-1 Use Substitution to Solve One-Step Equations

  2. Lesson 2

    6-2 One-Step Addition Equations

  3. Lesson 3

    6-3 One-Step Subtraction Equations

  4. Lesson 4

    6-4 One-Step Multiplication Equations

  5. Lesson 5

    6-5 One-Step Division Equations

  6. Lesson 6

    6-6 Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Distinguishing Between Expressions and Equations

Property

An expression is a mathematical phrase that contains numbers, variables, and operations but has no equal sign: 3x+53x + 5 or 2y72y - 7.

An equation is a mathematical sentence that shows two expressions are equal using an equal sign: 3x+5=143x + 5 = 14 or 2y7=112y - 7 = 11.

Section 2

Determining Solutions by Substitution

Property

A solution of an equation is a value of a variable that makes a true statement when substituted into the equation.
To determine whether a number is a solution to an equation:

Step 1. Substitute the number for the variable in the equation.
Step 2. Simplify the expressions on both sides of the equation.
Step 3. Determine whether the resulting equation is true.

  • If it is true, the number is a solution.
  • If it is not true, the number is not a solution.

Examples

  • Is x=5x=5 a solution to the equation 3x5=103x - 5 = 10? We substitute 3(5)5=155=103(5) - 5 = 15 - 5 = 10. Since 10=1010 = 10, it is a solution.
  • Is y=2y=-2 a solution to the equation 4y+9=2y4y + 9 = 2y? We substitute 4(2)+9=8+9=14(-2) + 9 = -8 + 9 = 1 on the left, and 2(2)=42(-2) = -4 on the right. Since 141 \neq -4, it is not a solution.
  • Is a=13a = \frac{1}{3} a solution to the equation 9a+2=59a + 2 = 5? We substitute 9(13)+2=3+2=59(\frac{1}{3}) + 2 = 3 + 2 = 5. Since 5=55=5, it is a solution.

Section 3

Guess and Check

Property

A problem-solving strategy where you make a reasonable guess, check if it fits the problem's conditions, and revise your guess if it is wrong. Repeat the process until you find the correct answer.

Examples

  • Problem: Two numbers add to 20 and their difference is 6. Guess: 10 and 10. Check: 1010=010-10=0. Revise: 13 and 7. Check: 13+7=2013+7=20 and 137=613-7=6. Correct!
  • Problem: A toy costs 45 cents. You pay with 10 coins (nickels and dimes). Guess: 5 nickels, 5 dimes = 75 cents. Revise: 7 nickels, 3 dimes = 65 cents. Revise again: 9 nickels, 1 dime = 55 cents.

Explanation

Think of yourself as a super sleuth! Make a smart guess to crack the case, check your clues, and if you're wrong, just try another angle. Every guess gets you closer to the solution, detective!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Module 6: Equations and Inequalities

  1. Lesson 1Current

    6-1 Use Substitution to Solve One-Step Equations

  2. Lesson 2

    6-2 One-Step Addition Equations

  3. Lesson 3

    6-3 One-Step Subtraction Equations

  4. Lesson 4

    6-4 One-Step Multiplication Equations

  5. Lesson 5

    6-5 One-Step Division Equations

  6. Lesson 6

    6-6 Inequalities