Learn on PengiCalifornia Reveal Math, Algebra 1Unit 10: Quadratic Functions

10-8 Modeling and Curve Fitting

In this Grade 9 lesson from California Reveal Math Algebra 1, students learn how to use first differences, second differences, and ratios of successive y-values to determine whether a data set is best modeled by a linear, quadratic, or exponential function. Students then apply curve fitting techniques to write the specific equation — in slope-intercept or standard form — that represents the data. The lesson also introduces the coefficient of determination as a measure of how well a function fits a given data set.

Section 1

Identifying Function Families from Data

Property

When analyzing a table of data where the xx-values are evenly spaced (e.g., increasing by 1), you can identify the underlying function family by analyzing the patterns in the yy-values:

  • Linear Model: The first differences (the difference between consecutive yy-values) are constant. This means the data grows by adding the same amount each time.
  • Quadratic Model: The first differences are not constant, but the second differences (the difference between consecutive first differences) are constant and non-zero.
  • Exponential Model: The differences are not constant, but the successive ratios (dividing a yy-value by the previous yy-value) are constant. This means the data grows by multiplying by the same factor each time.

Examples

  • Linear (Constant First Difference): Data (1,3),(2,7),(3,11),(4,15)(1, 3), (2, 7), (3, 11), (4, 15).

First differences: 73=47-3 = 4; 117=411-7 = 4; 1511=415-11 = 4. The constant difference is 4.

  • Quadratic (Constant Second Difference): Data (0,1),(1,4),(2,9),(3,16)(0, 1), (1, 4), (2, 9), (3, 16).

First differences: 3,5,73, 5, 7.
Second differences: 53=25-3 = 2; 75=27-5 = 2. The constant second difference is 2.

  • Exponential (Constant Ratio): Data (0,3),(1,6),(2,12),(3,24)(0, 3), (1, 6), (2, 12), (3, 24).

First differences are 3,6,123, 6, 12 (not constant).
Successive ratios: 6/3=26/3 = 2; 12/6=212/6 = 2; 24/12=224/12 = 2. The constant ratio is 2.

Explanation

Think of this process as running a diagnostic test on mysterious data. By systematically checking how the yy-values change, you reveal the data's "genetic code." Addition patterns point to lines, multiplying patterns point to exponential curves, and a constant rate of change in the rate of change points to a parabola. Always check these patterns in order: first differences, then second differences, then ratios.

Section 2

Writing Functions from Tables

Property

Once you identify the pattern in a perfect data table (where xx starts at 0 and increases by 1), you can manually calculate the parameters of the function:

  • Linear (y=mx+by = mx + b): mm is the constant first difference. bb is the yy-value when x=0x = 0.
  • Quadratic (y=ax2+bx+cy = ax^2 + bx + c): aa is EXACTLY HALF of the constant second difference (a=Δ22a = \frac{\Delta^2}{2}). cc is the yy-value when x=0x = 0. Substitute a known point to find bb.
  • Exponential (y=abxy = ab^x): bb is the constant successive ratio. aa is the yy-value when x=0x = 0.

Examples

  • Linear: Table has x=0,1,2x = 0, 1, 2 and y=5,8,11y = 5, 8, 11.

Constant first difference is 3, so m=3m = 3. At x=0x=0, y=5y=5, so b=5b=5. Model: y=3x+5y = 3x + 5.

  • Quadratic: Table has x=0,1,2,3x = 0, 1, 2, 3 and y=3,6,13,24y = 3, 6, 13, 24.

First differences: 3,7,113, 7, 11. Second differences: 4,44, 4.
So, a=4/2=2a = 4 / 2 = 2. At x=0x=0, y=3y=3, so c=3c=3.
Substitute point (1,6)(1, 6) into y=2x2+bx+36=2(1)2+b(1)+3b=1y = 2x^2 + bx + 3 \rightarrow 6 = 2(1)^2 + b(1) + 3 \rightarrow b = 1. Model: y=2x2+x+3y = 2x^2 + x + 3.

  • Exponential: Table has x=0,1,2x = 0, 1, 2 and y=4,12,36y = 4, 12, 36.

Constant ratio is 3, so base b=3b = 3. At x=0x=0, y=4y=4, so initial value a=4a = 4. Model: y=4(3)xy = 4(3)^x.

Explanation

When real-world data is mathematically perfect, you don't need a computer to find the equation. The yy-intercept (where x=0x=0) always gives you your starting parameter (bb for linear, cc for quadratic, aa for exponential). The constant pattern you found in your diagnostic test directly provides your growth parameter. For quadratic models, just remember the golden rule: the leading coefficient 'aa' is always half of the second difference!

Section 3

Shifting to Years-Since-Baseline for Modeling

Property

When modeling real-world data recorded in calendar years (e.g., 2015, 2016, 2017), you must define a shifted input variable tt so that the modeling begins at t=0t = 0:

t=Current YearBaseline Yeart = \text{Current Year} - \text{Baseline Year}

The baseline year is typically the first year in your data set. Use tt as your input variable for all calculations and regressions.

Book overview

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Unit 10: Quadratic Functions

  1. Lesson 1

    10-1 Graphing Quadratic Functions

  2. Lesson 2

    10-2 Transformations of Quadratic Functions

  3. Lesson 3

    10-3 Solving Quadratic Equations by Graphing

  4. Lesson 4

    10-4 Solving Quadratic Equations by Factoring

  5. Lesson 5

    10-5 Solving Quadratic Equations by Completing the Square

  6. Lesson 6

    10-6 Solving Quadratic Equations by Using the Quadratic Formula

  7. Lesson 7

    10-7 Solving Systems of Linear and Quadratic Equations

  8. Lesson 8Current

    10-8 Modeling and Curve Fitting

  9. Lesson 9

    10-9 Combining Functions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Identifying Function Families from Data

Property

When analyzing a table of data where the xx-values are evenly spaced (e.g., increasing by 1), you can identify the underlying function family by analyzing the patterns in the yy-values:

  • Linear Model: The first differences (the difference between consecutive yy-values) are constant. This means the data grows by adding the same amount each time.
  • Quadratic Model: The first differences are not constant, but the second differences (the difference between consecutive first differences) are constant and non-zero.
  • Exponential Model: The differences are not constant, but the successive ratios (dividing a yy-value by the previous yy-value) are constant. This means the data grows by multiplying by the same factor each time.

Examples

  • Linear (Constant First Difference): Data (1,3),(2,7),(3,11),(4,15)(1, 3), (2, 7), (3, 11), (4, 15).

First differences: 73=47-3 = 4; 117=411-7 = 4; 1511=415-11 = 4. The constant difference is 4.

  • Quadratic (Constant Second Difference): Data (0,1),(1,4),(2,9),(3,16)(0, 1), (1, 4), (2, 9), (3, 16).

First differences: 3,5,73, 5, 7.
Second differences: 53=25-3 = 2; 75=27-5 = 2. The constant second difference is 2.

  • Exponential (Constant Ratio): Data (0,3),(1,6),(2,12),(3,24)(0, 3), (1, 6), (2, 12), (3, 24).

First differences are 3,6,123, 6, 12 (not constant).
Successive ratios: 6/3=26/3 = 2; 12/6=212/6 = 2; 24/12=224/12 = 2. The constant ratio is 2.

Explanation

Think of this process as running a diagnostic test on mysterious data. By systematically checking how the yy-values change, you reveal the data's "genetic code." Addition patterns point to lines, multiplying patterns point to exponential curves, and a constant rate of change in the rate of change points to a parabola. Always check these patterns in order: first differences, then second differences, then ratios.

Section 2

Writing Functions from Tables

Property

Once you identify the pattern in a perfect data table (where xx starts at 0 and increases by 1), you can manually calculate the parameters of the function:

  • Linear (y=mx+by = mx + b): mm is the constant first difference. bb is the yy-value when x=0x = 0.
  • Quadratic (y=ax2+bx+cy = ax^2 + bx + c): aa is EXACTLY HALF of the constant second difference (a=Δ22a = \frac{\Delta^2}{2}). cc is the yy-value when x=0x = 0. Substitute a known point to find bb.
  • Exponential (y=abxy = ab^x): bb is the constant successive ratio. aa is the yy-value when x=0x = 0.

Examples

  • Linear: Table has x=0,1,2x = 0, 1, 2 and y=5,8,11y = 5, 8, 11.

Constant first difference is 3, so m=3m = 3. At x=0x=0, y=5y=5, so b=5b=5. Model: y=3x+5y = 3x + 5.

  • Quadratic: Table has x=0,1,2,3x = 0, 1, 2, 3 and y=3,6,13,24y = 3, 6, 13, 24.

First differences: 3,7,113, 7, 11. Second differences: 4,44, 4.
So, a=4/2=2a = 4 / 2 = 2. At x=0x=0, y=3y=3, so c=3c=3.
Substitute point (1,6)(1, 6) into y=2x2+bx+36=2(1)2+b(1)+3b=1y = 2x^2 + bx + 3 \rightarrow 6 = 2(1)^2 + b(1) + 3 \rightarrow b = 1. Model: y=2x2+x+3y = 2x^2 + x + 3.

  • Exponential: Table has x=0,1,2x = 0, 1, 2 and y=4,12,36y = 4, 12, 36.

Constant ratio is 3, so base b=3b = 3. At x=0x=0, y=4y=4, so initial value a=4a = 4. Model: y=4(3)xy = 4(3)^x.

Explanation

When real-world data is mathematically perfect, you don't need a computer to find the equation. The yy-intercept (where x=0x=0) always gives you your starting parameter (bb for linear, cc for quadratic, aa for exponential). The constant pattern you found in your diagnostic test directly provides your growth parameter. For quadratic models, just remember the golden rule: the leading coefficient 'aa' is always half of the second difference!

Section 3

Shifting to Years-Since-Baseline for Modeling

Property

When modeling real-world data recorded in calendar years (e.g., 2015, 2016, 2017), you must define a shifted input variable tt so that the modeling begins at t=0t = 0:

t=Current YearBaseline Yeart = \text{Current Year} - \text{Baseline Year}

The baseline year is typically the first year in your data set. Use tt as your input variable for all calculations and regressions.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Unit 10: Quadratic Functions

  1. Lesson 1

    10-1 Graphing Quadratic Functions

  2. Lesson 2

    10-2 Transformations of Quadratic Functions

  3. Lesson 3

    10-3 Solving Quadratic Equations by Graphing

  4. Lesson 4

    10-4 Solving Quadratic Equations by Factoring

  5. Lesson 5

    10-5 Solving Quadratic Equations by Completing the Square

  6. Lesson 6

    10-6 Solving Quadratic Equations by Using the Quadratic Formula

  7. Lesson 7

    10-7 Solving Systems of Linear and Quadratic Equations

  8. Lesson 8Current

    10-8 Modeling and Curve Fitting

  9. Lesson 9

    10-9 Combining Functions