Learn on PengiBig Ideas Math, Advanced 2Chapter 4: Graphing and Writing Linear Equations

Section 4.2: Slope of a Line

In this Grade 7 lesson from Big Ideas Math, Advanced 2 (Chapter 4), students learn how to calculate the slope of a line using the formula m = (y₂ − y₁)/(x₂ − x₁), applying the concepts of rise and run between two coordinate points. Students practice identifying positive and negative slopes from graphs, finding slope from tables, and exploring how similar triangles confirm that slope is constant between any two points on a line. The lesson builds foundational skills for graphing and writing linear equations.

Section 1

Slope

Property

The Greek letter Δ\Delta ('delta') is used in mathematics to indicate change. The slope of a line is defined by the ratio

change in y-coordinatechange in x-coordinate \frac{\text{change in } y\text{-coordinate}}{\text{change in } x\text{-coordinate}}

as we move from one point to another on the line. In symbols, the slope, denoted by mm, is:

m=ΔyΔx m = \frac{\Delta y}{\Delta x}

Examples

  • For a line passing through points (2,5)(2, 5) and (4,9)(4, 9), the change in yy is Δy=95=4\Delta y = 9 - 5 = 4 and the change in xx is Δx=42=2\Delta x = 4 - 2 = 2. The slope is m=42=2m = \frac{4}{2} = 2.
  • If we move from point A(1,3)A(1, 3) to point B(5,6)B(5, 6), the slope is m=ΔyΔx=6351=34m = \frac{\Delta y}{\Delta x} = \frac{6-3}{5-1} = \frac{3}{4}.

Section 2

Two-point formula for slope

Property

The slope of the line joining points P1(x1,y1)P_1(x_1, y_1) and P2(x2,y2)P_2(x_2, y_2) is

m=y2y1x2x1ifx2x1m = \frac{y_2 - y_1}{x_2 - x_1} \quad \text{if} \quad x_2 \neq x_1

Examples

  • To find the slope of the line through (1,2)(1, 2) and (4,8)(4, 8), we let (x1,y1)=(1,2)(x_1, y_1) = (1, 2) and (x2,y2)=(4,8)(x_2, y_2) = (4, 8). The slope is m=8241=63=2m = \frac{8 - 2}{4 - 1} = \frac{6}{3} = 2.
  • The slope of the line containing points (2,5)(-2, 5) and (3,5)(3, -5) is calculated as m=553(2)=105=2m = \frac{-5 - 5}{3 - (-2)} = \frac{-10}{5} = -2.
  • For the points (5,3)(5, -3) and (1,1)(-1, -1), the slope is m=1(3)15=26=13m = \frac{-1 - (-3)}{-1 - 5} = \frac{2}{-6} = -\frac{1}{3}. It doesn't matter which point you choose as first or second.

Explanation

This formula is a precise way to calculate 'rise over run.' It finds the vertical change (the 'rise,' y2y1y_2 - y_1) and divides it by the horizontal change (the 'run,' x2x1x_2 - x_1) between any two points on a line.

Book overview

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Chapter 4: Graphing and Writing Linear Equations

  1. Lesson 1

    Section 4.1: Graphing Linear Equations

  2. Lesson 2Current

    Section 4.2: Slope of a Line

  3. Lesson 3

    Section 4.3: Graphing Proportional Relationships

  4. Lesson 4

    Section 4.4: Graphing Linear Equations in Slope-Intercept Form

  5. Lesson 5

    Section 4.5: Graphing Linear Equations in Standard Form

  6. Lesson 6

    Section 4.6: Writing Equations in Slope-Intercept Form

  7. Lesson 7

    Section 4.7: Writing Equations in Point-Slope Form

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Slope

Property

The Greek letter Δ\Delta ('delta') is used in mathematics to indicate change. The slope of a line is defined by the ratio

change in y-coordinatechange in x-coordinate \frac{\text{change in } y\text{-coordinate}}{\text{change in } x\text{-coordinate}}

as we move from one point to another on the line. In symbols, the slope, denoted by mm, is:

m=ΔyΔx m = \frac{\Delta y}{\Delta x}

Examples

  • For a line passing through points (2,5)(2, 5) and (4,9)(4, 9), the change in yy is Δy=95=4\Delta y = 9 - 5 = 4 and the change in xx is Δx=42=2\Delta x = 4 - 2 = 2. The slope is m=42=2m = \frac{4}{2} = 2.
  • If we move from point A(1,3)A(1, 3) to point B(5,6)B(5, 6), the slope is m=ΔyΔx=6351=34m = \frac{\Delta y}{\Delta x} = \frac{6-3}{5-1} = \frac{3}{4}.

Section 2

Two-point formula for slope

Property

The slope of the line joining points P1(x1,y1)P_1(x_1, y_1) and P2(x2,y2)P_2(x_2, y_2) is

m=y2y1x2x1ifx2x1m = \frac{y_2 - y_1}{x_2 - x_1} \quad \text{if} \quad x_2 \neq x_1

Examples

  • To find the slope of the line through (1,2)(1, 2) and (4,8)(4, 8), we let (x1,y1)=(1,2)(x_1, y_1) = (1, 2) and (x2,y2)=(4,8)(x_2, y_2) = (4, 8). The slope is m=8241=63=2m = \frac{8 - 2}{4 - 1} = \frac{6}{3} = 2.
  • The slope of the line containing points (2,5)(-2, 5) and (3,5)(3, -5) is calculated as m=553(2)=105=2m = \frac{-5 - 5}{3 - (-2)} = \frac{-10}{5} = -2.
  • For the points (5,3)(5, -3) and (1,1)(-1, -1), the slope is m=1(3)15=26=13m = \frac{-1 - (-3)}{-1 - 5} = \frac{2}{-6} = -\frac{1}{3}. It doesn't matter which point you choose as first or second.

Explanation

This formula is a precise way to calculate 'rise over run.' It finds the vertical change (the 'rise,' y2y1y_2 - y_1) and divides it by the horizontal change (the 'run,' x2x1x_2 - x_1) between any two points on a line.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Graphing and Writing Linear Equations

  1. Lesson 1

    Section 4.1: Graphing Linear Equations

  2. Lesson 2Current

    Section 4.2: Slope of a Line

  3. Lesson 3

    Section 4.3: Graphing Proportional Relationships

  4. Lesson 4

    Section 4.4: Graphing Linear Equations in Slope-Intercept Form

  5. Lesson 5

    Section 4.5: Graphing Linear Equations in Standard Form

  6. Lesson 6

    Section 4.6: Writing Equations in Slope-Intercept Form

  7. Lesson 7

    Section 4.7: Writing Equations in Point-Slope Form