Learn on PengiBig Ideas Math, Advanced 2Chapter 13: Circles and Area

Section 13.3: Areas of Circles

In this Grade 7 lesson from Big Ideas Math, Advanced 2 (Chapter 13: Circles and Area), students learn how to calculate the area of a circle using the formula A = πr². The lesson covers applying the formula with both 3.14 and 22/7 as approximations for π, finding areas when given either the radius or diameter, and extending the concept to find the area of semicircles. Students also explore how the formula is derived by rearranging circle sectors into a parallelogram shape.

Section 1

Circle Definitions: Radius, Diameter, and Center

Property

A circle is defined as all points that are the same distance from a center point. The radius (rr) is any line segment from the center of the circle to a point on the circle. The diameter (dd) is any line segment that passes through the center and connects two points on the circle, where d=2rd = 2r.

Examples

  • When you drop a pebble in a pond, the ripples form circles. Every point on a single ripple is the same distance from where the pebble hit the water (the center).
  • A pizza has a circular shape. If the pizza has a radius of r=6r = 6 inches, then its diameter is d=2×6=12d = 2 \times 6 = 12 inches.
  • A bicycle wheel is circular. The distance from the center hub to the edge of the tire is the radius, while the distance across the entire wheel through the center is the diameter.

Explanation

Understanding the radius and diameter of a circle is essential for calculating its area. The radius is the key measurement we use in the area formula, while the diameter helps us find the radius when needed. These definitions form the foundation for working with circle area problems.

Section 2

Area of a Circle

Property

The ratio of the area of a circle and the square of its radius is a constant, and that constant is the area of a circle of radius 1 unit, and is designated by the Greek letter π\pi. Thus we get this formula for the area AA of a circle in terms of its radius rr:

A=πr2A = \pi r^2

Examples

  • A circle has a radius of 55 cm. Its area is A=π(52)=25πA = \pi (5^2) = 25\pi cm2^2.
  • A pizza has an area of 100π100\pi square inches. To find its radius, we solve 100π=πr2100\pi = \pi r^2, which gives r2=100r^2 = 100, so the radius is 1010 inches.
  • A circular garden has a diameter of 1212 meters. The radius is half the diameter, so r=6r = 6 m. The area is A=π(62)=36πA = \pi (6^2) = 36\pi m2^2.

Explanation

The area of a circle grows with the square of its radius. This means if you double the radius, the area doesn't just double, it becomes four times larger! The special number π\pi is the constant that links them.

Section 3

Alternative Area Derivation Using Triangle Visualization

Property

By imagining a circle's area as being rearranged into a triangle, we can derive the area formula in a visual way.
The triangle's base would be the distance around the circle and its height would be the radius (rr).
This gives us the formula for the area of the circle:

A=12×(distance around)×rA = \frac{1}{2} \times \text{(distance around)} \times r

Since the distance around a circle is 2πr2\pi r, this becomes:

A=12(2πr)(r)=πr2A = \frac{1}{2}(2\pi r)(r) = \pi r^2

Book overview

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Chapter 13: Circles and Area

  1. Lesson 1

    Section 13.1: Circles and Circumference

  2. Lesson 2

    Section 13.2: Perimeters of Composite Figures

  3. Lesson 3Current

    Section 13.3: Areas of Circles

  4. Lesson 4

    Section 13.4: Areas of Composite Figures

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Circle Definitions: Radius, Diameter, and Center

Property

A circle is defined as all points that are the same distance from a center point. The radius (rr) is any line segment from the center of the circle to a point on the circle. The diameter (dd) is any line segment that passes through the center and connects two points on the circle, where d=2rd = 2r.

Examples

  • When you drop a pebble in a pond, the ripples form circles. Every point on a single ripple is the same distance from where the pebble hit the water (the center).
  • A pizza has a circular shape. If the pizza has a radius of r=6r = 6 inches, then its diameter is d=2×6=12d = 2 \times 6 = 12 inches.
  • A bicycle wheel is circular. The distance from the center hub to the edge of the tire is the radius, while the distance across the entire wheel through the center is the diameter.

Explanation

Understanding the radius and diameter of a circle is essential for calculating its area. The radius is the key measurement we use in the area formula, while the diameter helps us find the radius when needed. These definitions form the foundation for working with circle area problems.

Section 2

Area of a Circle

Property

The ratio of the area of a circle and the square of its radius is a constant, and that constant is the area of a circle of radius 1 unit, and is designated by the Greek letter π\pi. Thus we get this formula for the area AA of a circle in terms of its radius rr:

A=πr2A = \pi r^2

Examples

  • A circle has a radius of 55 cm. Its area is A=π(52)=25πA = \pi (5^2) = 25\pi cm2^2.
  • A pizza has an area of 100π100\pi square inches. To find its radius, we solve 100π=πr2100\pi = \pi r^2, which gives r2=100r^2 = 100, so the radius is 1010 inches.
  • A circular garden has a diameter of 1212 meters. The radius is half the diameter, so r=6r = 6 m. The area is A=π(62)=36πA = \pi (6^2) = 36\pi m2^2.

Explanation

The area of a circle grows with the square of its radius. This means if you double the radius, the area doesn't just double, it becomes four times larger! The special number π\pi is the constant that links them.

Section 3

Alternative Area Derivation Using Triangle Visualization

Property

By imagining a circle's area as being rearranged into a triangle, we can derive the area formula in a visual way.
The triangle's base would be the distance around the circle and its height would be the radius (rr).
This gives us the formula for the area of the circle:

A=12×(distance around)×rA = \frac{1}{2} \times \text{(distance around)} \times r

Since the distance around a circle is 2πr2\pi r, this becomes:

A=12(2πr)(r)=πr2A = \frac{1}{2}(2\pi r)(r) = \pi r^2

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 13: Circles and Area

  1. Lesson 1

    Section 13.1: Circles and Circumference

  2. Lesson 2

    Section 13.2: Perimeters of Composite Figures

  3. Lesson 3Current

    Section 13.3: Areas of Circles

  4. Lesson 4

    Section 13.4: Areas of Composite Figures