Learn on PengiOpenstax Elementary Algebra 2EChapter 9: Roots and Radicals

Lesson 9.1: Simplify and Use Square Roots

In this lesson from OpenStax Elementary Algebra 2E, students learn to simplify expressions with square roots, including identifying principal square roots, negative square roots, and recognizing when a square root is not a real number. The lesson also covers estimating and approximating square roots and simplifying variable expressions with square roots. Students work with radical sign notation and perfect squares as an introduction to Chapter 9's broader study of roots and radicals.

Section 1

πŸ“˜ Simplify and Use Square Roots

New Concept

Discover the concept of a square root, the inverse of squaring a number. This lesson will teach you how to simplify, estimate, and approximate square roots for both numbers and variable expressions.

What’s next

Next, you'll dive into worked examples and interactive practice cards to master simplifying, estimating, and approximating square roots.

Section 2

Square Root of a Number

Property

Square of a Number
If n2=mn^2 = m, then mm is the square of nn.

Square Root of a Number
If n2=mn^2 = m, then nn is a square root of mm.

Square Root Notation
m\sqrt{m} is read as β€œthe square root of mm.”
If m=n2m = n^2, then m=n\sqrt{m} = n, for nβ‰₯0n \ge 0.
The square root of mm, m\sqrt{m}, is the positive number whose square is mm. This is also called the principal square root.
To find the negative square root of a number, we place a negative in front of the radical sign.
When using the order of operations, we treat the radical as a grouping symbol.

Section 3

Estimate Square Roots

Property

To estimate a square root between two consecutive whole numbers, first locate the number between two consecutive perfect squares.
Its square root will then lie between the square roots of those perfect squares.

Examples

  • To estimate 20\sqrt{20}, we know that 16 and 25 are the closest perfect squares. Since 16<20<2516 < 20 < 25, we can say that 4<20<54 < \sqrt{20} < 5.
  • To estimate 90\sqrt{90}, we look for perfect squares near 90. Since 81<90<10081 < 90 < 100, the estimate is 9<90<109 < \sqrt{90} < 10.
  • To estimate 150\sqrt{150}, we see that 144<150<169144 < 150 < 169. Therefore, we know that 12<150<1312 < \sqrt{150} < 13.

Explanation

This method works because as numbers get bigger, their square roots also get bigger. By finding the two perfect square neighbors for your number, you can trap its square root between two whole numbers, giving you a great estimate.

Section 4

Approximate Square Roots

Property

For numbers that are not perfect squares, the square root is an irrational number.
We use a calculator to find a decimal approximation. The symbol β‰ˆ\approx means 'is approximately equal to.'

Examples

  • To approximate 23\sqrt{23} rounded to two decimal places, a calculator shows 4.7958...4.7958.... We round this to 4.804.80. So, 23β‰ˆ4.80\sqrt{23} \approx 4.80.
  • To approximate 51\sqrt{51} rounded to two decimal places, a calculator shows 7.1414...7.1414.... We round this to 7.147.14. So, 51β‰ˆ7.14\sqrt{51} \approx 7.14.
  • To approximate 2\sqrt{2} rounded to two decimal places, a calculator shows 1.4142...1.4142.... We round this to 1.411.41. So, 2β‰ˆ1.41\sqrt{2} \approx 1.41.

Explanation

The square root of a non-perfect square has a decimal that never ends or repeats. A calculator gives us a practical, rounded value to work with. This approximation is close enough for most real-world problems.

Section 5

Simplify variable square roots

Property

To find the square root of a variable expression, use the Power Property of Exponents in reverse.
Since (am)2=a2m(a^m)^2 = a^{2m}, it follows that a2m=am\sqrt{a^{2m}} = a^m.
We assume all variables represent non-negative numbers.
To simplify, take the square root of the coefficient and divide the exponent of each variable by 2.

Examples

  • To simplify z14\sqrt{z^{14}}, we divide the exponent by 2. So, z14=z14/2=z7\sqrt{z^{14}} = z^{14/2} = z^7.
  • To simplify 25x18\sqrt{25x^{18}}, we find 25=5\sqrt{25}=5 and divide the exponent of xx by 2. So, 25x18=5x9\sqrt{25x^{18}} = 5x^9.
  • To simplify 144m12n6\sqrt{144m^{12}n^6}, we find 144=12\sqrt{144}=12 and divide each exponent by 2. So, 144m12n6=12m6n3\sqrt{144m^{12}n^6} = 12m^6n^3.

Explanation

Finding the square root 'undoes' squaring. When you square a power, you multiply the exponent by 2. So, to take the square root of a variable with an even power, you do the opposite: divide the exponent by 2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Roots and Radicals

  1. Lesson 1Current

    Lesson 9.1: Simplify and Use Square Roots

  2. Lesson 2

    Lesson 9.2: Simplify Square Roots

  3. Lesson 3

    Lesson 9.3: Add and Subtract Square Roots

  4. Lesson 4

    Lesson 9.4: Multiply Square Roots

  5. Lesson 5

    Lesson 9.5: Divide Square Roots

  6. Lesson 6

    Lesson 9.6: Solve Equations with Square Roots

  7. Lesson 7

    Lesson 9.7: Higher Roots

  8. Lesson 8

    Lesson 9.8: Rational Exponents

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Simplify and Use Square Roots

New Concept

Discover the concept of a square root, the inverse of squaring a number. This lesson will teach you how to simplify, estimate, and approximate square roots for both numbers and variable expressions.

What’s next

Next, you'll dive into worked examples and interactive practice cards to master simplifying, estimating, and approximating square roots.

Section 2

Square Root of a Number

Property

Square of a Number
If n2=mn^2 = m, then mm is the square of nn.

Square Root of a Number
If n2=mn^2 = m, then nn is a square root of mm.

Square Root Notation
m\sqrt{m} is read as β€œthe square root of mm.”
If m=n2m = n^2, then m=n\sqrt{m} = n, for nβ‰₯0n \ge 0.
The square root of mm, m\sqrt{m}, is the positive number whose square is mm. This is also called the principal square root.
To find the negative square root of a number, we place a negative in front of the radical sign.
When using the order of operations, we treat the radical as a grouping symbol.

Section 3

Estimate Square Roots

Property

To estimate a square root between two consecutive whole numbers, first locate the number between two consecutive perfect squares.
Its square root will then lie between the square roots of those perfect squares.

Examples

  • To estimate 20\sqrt{20}, we know that 16 and 25 are the closest perfect squares. Since 16<20<2516 < 20 < 25, we can say that 4<20<54 < \sqrt{20} < 5.
  • To estimate 90\sqrt{90}, we look for perfect squares near 90. Since 81<90<10081 < 90 < 100, the estimate is 9<90<109 < \sqrt{90} < 10.
  • To estimate 150\sqrt{150}, we see that 144<150<169144 < 150 < 169. Therefore, we know that 12<150<1312 < \sqrt{150} < 13.

Explanation

This method works because as numbers get bigger, their square roots also get bigger. By finding the two perfect square neighbors for your number, you can trap its square root between two whole numbers, giving you a great estimate.

Section 4

Approximate Square Roots

Property

For numbers that are not perfect squares, the square root is an irrational number.
We use a calculator to find a decimal approximation. The symbol β‰ˆ\approx means 'is approximately equal to.'

Examples

  • To approximate 23\sqrt{23} rounded to two decimal places, a calculator shows 4.7958...4.7958.... We round this to 4.804.80. So, 23β‰ˆ4.80\sqrt{23} \approx 4.80.
  • To approximate 51\sqrt{51} rounded to two decimal places, a calculator shows 7.1414...7.1414.... We round this to 7.147.14. So, 51β‰ˆ7.14\sqrt{51} \approx 7.14.
  • To approximate 2\sqrt{2} rounded to two decimal places, a calculator shows 1.4142...1.4142.... We round this to 1.411.41. So, 2β‰ˆ1.41\sqrt{2} \approx 1.41.

Explanation

The square root of a non-perfect square has a decimal that never ends or repeats. A calculator gives us a practical, rounded value to work with. This approximation is close enough for most real-world problems.

Section 5

Simplify variable square roots

Property

To find the square root of a variable expression, use the Power Property of Exponents in reverse.
Since (am)2=a2m(a^m)^2 = a^{2m}, it follows that a2m=am\sqrt{a^{2m}} = a^m.
We assume all variables represent non-negative numbers.
To simplify, take the square root of the coefficient and divide the exponent of each variable by 2.

Examples

  • To simplify z14\sqrt{z^{14}}, we divide the exponent by 2. So, z14=z14/2=z7\sqrt{z^{14}} = z^{14/2} = z^7.
  • To simplify 25x18\sqrt{25x^{18}}, we find 25=5\sqrt{25}=5 and divide the exponent of xx by 2. So, 25x18=5x9\sqrt{25x^{18}} = 5x^9.
  • To simplify 144m12n6\sqrt{144m^{12}n^6}, we find 144=12\sqrt{144}=12 and divide each exponent by 2. So, 144m12n6=12m6n3\sqrt{144m^{12}n^6} = 12m^6n^3.

Explanation

Finding the square root 'undoes' squaring. When you square a power, you multiply the exponent by 2. So, to take the square root of a variable with an even power, you do the opposite: divide the exponent by 2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Roots and Radicals

  1. Lesson 1Current

    Lesson 9.1: Simplify and Use Square Roots

  2. Lesson 2

    Lesson 9.2: Simplify Square Roots

  3. Lesson 3

    Lesson 9.3: Add and Subtract Square Roots

  4. Lesson 4

    Lesson 9.4: Multiply Square Roots

  5. Lesson 5

    Lesson 9.5: Divide Square Roots

  6. Lesson 6

    Lesson 9.6: Solve Equations with Square Roots

  7. Lesson 7

    Lesson 9.7: Higher Roots

  8. Lesson 8

    Lesson 9.8: Rational Exponents