Learn on PengienVision, Mathematics, Grade 6Chapter 5: Understand and Use Ratio and Rate

Lesson 7: Solve Unit Rate Problems

In this Grade 6 lesson from enVision Mathematics Chapter 5, students learn how to use unit rates to solve real-world problems involving constant speed, unit price, and distance-rate-time relationships. Students apply the formula d = r × t and use ratio tables and equivalent rates to find unknown quantities such as distance traveled or cost per item. The lesson aligns with Common Core standard 6.RP.A.3b and builds fluency with proportional reasoning in practical contexts.

Section 1

Using Ratio Tables to Find Equivalent Rates

Property

A ratio table organizes equivalent rates.
To find a unit rate, divide both quantities by the value of the quantity you want to be 1.
To find an equivalent rate, multiply both quantities in the unit rate row by the new desired quantity.

Examples

Section 2

The Proportional Relationship Equation

Property

Proportional relationships can be represented by an equation of the form y=kxy = kx or y=rxy = rx. In this equation:

  • xx is the independent variable (input).
  • yy is the dependent variable (output).
  • rr (or kk) is the constant of proportionality (the unit rate).

This equation shows that the output is always a constant multiple of the input.

Examples

  • A machine prints 80 pages in 5 minutes. The unit rate is r=805=16r = \frac{80}{5} = 16 pages per minute. The equation is p=16mp = 16m, where pp is pages and mm is minutes.
  • The cost for apples is 2.50 dollars per pound. If CC is the total cost and pp is the number of pounds, the equation is C=2.5pC = 2.5p.
  • A graph of a proportional relationship passes through (4,32)(4, 32). The unit rate is 324=8\frac{32}{4}=8. The equation representing this graph is y=8xy = 8x.

Explanation

An equation is like a powerful calculator for a proportional relationship. Once you find the constant rate (rr), you can plug in any amount for xx to instantly find its corresponding amount yy, without having to fill out a huge table.

Section 3

Distance, Rate, and Time

Property

For an object moving at a uniform (constant) rate, the distance traveled, the elapsed time, and the rate are related by the formula:

d=rtd = rt

where dd = distance, rr = rate, and tt = time. To solve problems with this formula, first identify the knowns and unknowns, substitute the values into the formula, and then solve for the missing variable.

Examples

  • Lindsay drove for 4.5 hours at 60 miles per hour. How much distance did she travel? The distance is d=rt=604.5=270d = rt = 60 \cdot 4.5 = 270 miles.
  • Lee wants to drive 600 miles. If he drives at a steady rate of 75 miles per hour, how many hours will the trip take? The time is t=dr=60075=8t = \frac{d}{r} = \frac{600}{75} = 8 hours.
  • A train trip from Boston to Washington D.C. is 440 miles and takes 5 hours. What was the average speed of the train? The rate is r=dt=4405=88r = \frac{d}{t} = \frac{440}{5} = 88 miles per hour.

Explanation

This formula connects speed, time, and distance. Think of it this way: the distance you cover is a product of how fast you travel (rate) and for how long (time). It is a fundamental principle used to describe motion.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Understand and Use Ratio and Rate

  1. Lesson 1

    Lesson 1: Understand Ratios

  2. Lesson 2

    Lesson 2: Generate Equivalent Ratios

  3. Lesson 3

    Lesson 3: Compare Ratios

  4. Lesson 4

    Lesson 4: Represent and Graph Ratios

  5. Lesson 5

    Lesson 5: Understand Rates and Unit Rates

  6. Lesson 6

    Lesson 6: Compare Unit Rates

  7. Lesson 7Current

    Lesson 7: Solve Unit Rate Problems

  8. Lesson 8

    Lesson 8: Ratio Reasoning: Convert Customary Units

  9. Lesson 9

    Lesson 9: Ratio Reasoning: Convert Metric Units

  10. Lesson 10

    Lesson 10: Relate Customary and Metric Units

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Using Ratio Tables to Find Equivalent Rates

Property

A ratio table organizes equivalent rates.
To find a unit rate, divide both quantities by the value of the quantity you want to be 1.
To find an equivalent rate, multiply both quantities in the unit rate row by the new desired quantity.

Examples

Section 2

The Proportional Relationship Equation

Property

Proportional relationships can be represented by an equation of the form y=kxy = kx or y=rxy = rx. In this equation:

  • xx is the independent variable (input).
  • yy is the dependent variable (output).
  • rr (or kk) is the constant of proportionality (the unit rate).

This equation shows that the output is always a constant multiple of the input.

Examples

  • A machine prints 80 pages in 5 minutes. The unit rate is r=805=16r = \frac{80}{5} = 16 pages per minute. The equation is p=16mp = 16m, where pp is pages and mm is minutes.
  • The cost for apples is 2.50 dollars per pound. If CC is the total cost and pp is the number of pounds, the equation is C=2.5pC = 2.5p.
  • A graph of a proportional relationship passes through (4,32)(4, 32). The unit rate is 324=8\frac{32}{4}=8. The equation representing this graph is y=8xy = 8x.

Explanation

An equation is like a powerful calculator for a proportional relationship. Once you find the constant rate (rr), you can plug in any amount for xx to instantly find its corresponding amount yy, without having to fill out a huge table.

Section 3

Distance, Rate, and Time

Property

For an object moving at a uniform (constant) rate, the distance traveled, the elapsed time, and the rate are related by the formula:

d=rtd = rt

where dd = distance, rr = rate, and tt = time. To solve problems with this formula, first identify the knowns and unknowns, substitute the values into the formula, and then solve for the missing variable.

Examples

  • Lindsay drove for 4.5 hours at 60 miles per hour. How much distance did she travel? The distance is d=rt=604.5=270d = rt = 60 \cdot 4.5 = 270 miles.
  • Lee wants to drive 600 miles. If he drives at a steady rate of 75 miles per hour, how many hours will the trip take? The time is t=dr=60075=8t = \frac{d}{r} = \frac{600}{75} = 8 hours.
  • A train trip from Boston to Washington D.C. is 440 miles and takes 5 hours. What was the average speed of the train? The rate is r=dt=4405=88r = \frac{d}{t} = \frac{440}{5} = 88 miles per hour.

Explanation

This formula connects speed, time, and distance. Think of it this way: the distance you cover is a product of how fast you travel (rate) and for how long (time). It is a fundamental principle used to describe motion.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Understand and Use Ratio and Rate

  1. Lesson 1

    Lesson 1: Understand Ratios

  2. Lesson 2

    Lesson 2: Generate Equivalent Ratios

  3. Lesson 3

    Lesson 3: Compare Ratios

  4. Lesson 4

    Lesson 4: Represent and Graph Ratios

  5. Lesson 5

    Lesson 5: Understand Rates and Unit Rates

  6. Lesson 6

    Lesson 6: Compare Unit Rates

  7. Lesson 7Current

    Lesson 7: Solve Unit Rate Problems

  8. Lesson 8

    Lesson 8: Ratio Reasoning: Convert Customary Units

  9. Lesson 9

    Lesson 9: Ratio Reasoning: Convert Metric Units

  10. Lesson 10

    Lesson 10: Relate Customary and Metric Units