Learn on PengiPengi Math (Grade 5)Chapter 8: Measurement — Volume & Unit Conversions

Lesson 7: Solve Multi-Step Word Problems Using Volume

In this Grade 5 Pengi Math lesson from Chapter 8, students solve multi-step real-world word problems involving volume by applying decomposition strategies and combining volume calculations with rates such as cost or weight per cubic unit. Students also practice checking their solutions for reasonableness using estimation.

Section 1

Real-World Applications

Property

Real-world objects often require both volume and surface area calculations. Always read carefully to decide which one you need:

  • Filling an object (water, dirt, air) = Volume.
  • Covering an object (paint, wrapping paper, tile) = Surface Area.

Examples

  • Swimming Pool (Volume): An L-shaped pool has a shallow end (10 ft by 12 ft, depth 4 ft) and a deep end (15 ft by 12 ft, depth 9 ft).

Volume of shallow end: 10 x 12 x 4 = 480 cubic ft.
Volume of deep end: 15 x 12 x 9 = 1620 cubic ft.
Total water needed: 480 + 1620 = 2100 cubic ft.

  • Skate Park Ramp (Surface Area): A wooden ramp is built from a rectangular prism and a triangular prism. To figure out how much special grip paint to buy, you must find the Surface Area. Remember to exclude the bottom faces touching the ground and the faces where the two prisms connect!

Explanation

Out in the real world, nobody hands you a perfectly simple cube! Pools, couches, houses, and skate ramps are all composite figures. By breaking these complex shapes into easy rectangular and triangular prisms, you can calculate exactly how much water fills a pool or how much paint covers a building. Just take it one block at a time!

Section 2

Solving Word Problems Using Volume

Property

Many real-world problems can be solved by first calculating the volume of an object and then using that volume to determine another quantity, such as cost, weight, or capacity.
This relationship can often be expressed with the formula:

Total Quantity=Volume×Rate \text{Total Quantity} = \text{Volume} \times \text{Rate}

where the rate is a value per unit of volume (e.g., cost/m³, weight/cm³).

Examples

Book overview

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Continue this chapter

Chapter 8: Measurement — Volume & Unit Conversions

  1. Lesson 1

    Lesson 1: Convert Measurement Units

  2. Lesson 2

    Lesson 2: Solve Measurement Word Problems with Conversions

  3. Lesson 3

    Lesson 3: Introduction to Volume and Cubic Units

  4. Lesson 4

    Lesson 4: Measure Volume with Unit Cubes, Layers, and Shape Comparisons

  5. Lesson 5

    Lesson 5: Volume Formulas and Equivalent Expressions

  6. Lesson 6

    Lesson 6: Volume of Composite Solids

  7. Lesson 7Current

    Lesson 7: Solve Multi-Step Word Problems Using Volume

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Real-World Applications

Property

Real-world objects often require both volume and surface area calculations. Always read carefully to decide which one you need:

  • Filling an object (water, dirt, air) = Volume.
  • Covering an object (paint, wrapping paper, tile) = Surface Area.

Examples

  • Swimming Pool (Volume): An L-shaped pool has a shallow end (10 ft by 12 ft, depth 4 ft) and a deep end (15 ft by 12 ft, depth 9 ft).

Volume of shallow end: 10 x 12 x 4 = 480 cubic ft.
Volume of deep end: 15 x 12 x 9 = 1620 cubic ft.
Total water needed: 480 + 1620 = 2100 cubic ft.

  • Skate Park Ramp (Surface Area): A wooden ramp is built from a rectangular prism and a triangular prism. To figure out how much special grip paint to buy, you must find the Surface Area. Remember to exclude the bottom faces touching the ground and the faces where the two prisms connect!

Explanation

Out in the real world, nobody hands you a perfectly simple cube! Pools, couches, houses, and skate ramps are all composite figures. By breaking these complex shapes into easy rectangular and triangular prisms, you can calculate exactly how much water fills a pool or how much paint covers a building. Just take it one block at a time!

Section 2

Solving Word Problems Using Volume

Property

Many real-world problems can be solved by first calculating the volume of an object and then using that volume to determine another quantity, such as cost, weight, or capacity.
This relationship can often be expressed with the formula:

Total Quantity=Volume×Rate \text{Total Quantity} = \text{Volume} \times \text{Rate}

where the rate is a value per unit of volume (e.g., cost/m³, weight/cm³).

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Measurement — Volume & Unit Conversions

  1. Lesson 1

    Lesson 1: Convert Measurement Units

  2. Lesson 2

    Lesson 2: Solve Measurement Word Problems with Conversions

  3. Lesson 3

    Lesson 3: Introduction to Volume and Cubic Units

  4. Lesson 4

    Lesson 4: Measure Volume with Unit Cubes, Layers, and Shape Comparisons

  5. Lesson 5

    Lesson 5: Volume Formulas and Equivalent Expressions

  6. Lesson 6

    Lesson 6: Volume of Composite Solids

  7. Lesson 7Current

    Lesson 7: Solve Multi-Step Word Problems Using Volume