Learn on PengiOpenstax Prealgebre 2EChapter 5: Decimals

Lesson 7: Simplify and Use Square Roots

In this prealgebra lesson from OpenStax Prealgebra 2E, students learn to simplify expressions with square roots, identify perfect squares, and work with square roots of both positive numbers and variable expressions. The lesson covers estimating and approximating square roots and applying them to real-world problems. It is designed for middle school students building foundational skills before algebra.

Section 1

πŸ“˜ Simplify and Use Square Roots

New Concept

This lesson introduces the square root, the inverse of squaring a number. You'll learn how to find values like 25\sqrt{25}, estimate others like 60\sqrt{60}, and apply this skill to solve real-world problems.

What’s next

Now that you have the basics, you'll tackle interactive examples, practice problems, and real-world challenges to master using square roots.

Section 2

Square of a number

Property

If n2=mn^2 = m, then mm is the square of nn. A perfect square is the square of a whole number. Squaring a positive or negative number results in a positive number.

Examples

  • The square of 8 is 64, because 82=8Γ—8=648^2 = 8 \times 8 = 64.
  • The number 144 is a perfect square, as it is the square of a whole number: 122=14412^2 = 144.
  • The square of βˆ’5-5 is 25, since (βˆ’5)2=(βˆ’5)(βˆ’5)=25(-5)^2 = (-5)(-5) = 25.

Explanation

Squaring a number means multiplying it by itself. This concept is named after a geometric square, where the area is the side length multiplied by itself. Perfect squares are the result of squaring whole numbers, like 9 from 323^2.

Section 3

Square root of a number

Property

A number whose square is mm is called a square root of mm. If n2=mn^2 = m, then nn is a square root of mm. The notation m\sqrt{m} is read as 'the square root of mm' and represents the positive square root, or principal square root. For nβ‰₯0n \ge 0, if m=n2m = n^2, then m=n\sqrt{m} = n.

Examples

  • Since 52=255^2 = 25, the principal square root of 25 is 25=5\sqrt{25} = 5.
  • To indicate the negative square root of 100, we write βˆ’100-\sqrt{100}, which simplifies to βˆ’10-10.
  • Zero has only one square root. Because 02=00^2 = 0, we have 0=0\sqrt{0} = 0.

Explanation

Finding a square root is the inverse operation of squaring a number. The radical symbol m\sqrt{m} asks for the positive number that, when multiplied by itself, equals mm. Every positive number actually has two square roots: one positive and one negative.

Section 4

Square roots and operations

Property

When using the order of operations, treat the radical sign as a grouping symbol. Simplify any expressions under the radical sign before performing other operations. For any negative number, there is no real number solution for its square root.

Examples

  • To simplify 9+16\sqrt{9 + 16}, you must first add the numbers inside the radical to get 25\sqrt{25}, which equals 55.
  • To simplify 9+16\sqrt{9} + \sqrt{16}, you find each square root separately before adding: 3+4=73 + 4 = 7. Note this is different from the first example.
  • The expression βˆ’169\sqrt{-169} is not a real number because no real number multiplied by itself can result in βˆ’169-169.

Explanation

The radical sign acts like parentheses, so you must simplify the expression inside it first. You cannot take the square root of a negative number in the real number system because squaring any real number always results in a non-negative value.

Section 5

Estimate and approximate square roots

Property

To estimate a square root, locate it between two consecutive perfect squares.

Examples

  • To estimate 70\sqrt{70}, we know 82=648^2 = 64 and 92=819^2 = 81. Since 70 is between 64 and 81, we know that 8<70<98 < \sqrt{70} < 9.
  • Using a calculator to find 17\sqrt{17} and rounding to two decimal places gives the approximation 17β‰ˆ4.12\sqrt{17} \approx 4.12.
  • To estimate 172\sqrt{172}, notice it is between the perfect squares 169169 (13213^2) and 196196 (14214^2). Therefore, 13<172<1413 < \sqrt{172} < 14.

Explanation

Not all numbers have whole number square roots. For these non-perfect squares, we can estimate the root's value by identifying the two closest perfect squares. A calculator provides a more precise but still approximate decimal value.

Section 6

Simplify variable expressions with square roots

Property

To simplify a square root containing a variable, find an expression that, when squared, equals the expression inside the radical. In this context, we assume all variables in a square root expression are non-negative.

Examples

  • To simplify y2\sqrt{y^2}, we recognize that (y)2=y2(y)^2 = y^2, so y2=y\sqrt{y^2} = y.
  • To simplify 49x2\sqrt{49x^2}, find the square root of 49 (which is 7) and the square root of x2x^2 (which is xx), giving a result of 7x7x.
  • To simplify βˆ’100y2-\sqrt{100y^2}, the negative sign stays outside. Since 100y2=10y\sqrt{100y^2} = 10y, the expression simplifies to βˆ’10y-10y.

Explanation

When simplifying square roots with variables, think 'what expression, when squared, gives me this?'. Assuming variables are non-negative, x2\sqrt{x^2} simplifies to xx. You can find the square root of the coefficient and the variable part separately.

Section 7

Use square roots in applications

Property

Square roots are used in various real-world formulas.

Examples

  • If a square patio has an area of 200 square feet, the length of one side is 200β‰ˆ14.1\sqrt{200} \approx 14.1 feet.
  • If a pair of sunglasses is dropped from a bridge 400 feet high, the time it takes to reach the river is 4004=100=5\sqrt{\frac{400}{4}} = \sqrt{100} = 5 seconds.
  • If a car's skid marks measure 190 feet, its speed before braking was 24β‹…190=4560β‰ˆ67.5\sqrt{24 \cdot 190} = \sqrt{4560} \approx 67.5 miles per hour.

Explanation

Square roots are essential for solving practical problems, especially when you need to reverse a squaring operation. This is common in geometry for finding lengths from areas and in physics for formulas involving time, speed, and distance.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Decimals

  1. Lesson 1

    Lesson 1: Decimals

  2. Lesson 2

    Lesson 2: Decimal Operations

  3. Lesson 3

    Lesson 3: Decimals and Fractions

  4. Lesson 4

    Lesson 4: Solve Equations with Decimals

  5. Lesson 5

    Lesson 5: Averages and Probability

  6. Lesson 6

    Lesson 6: Ratios and Rate

  7. Lesson 7Current

    Lesson 7: Simplify and Use Square Roots

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Simplify and Use Square Roots

New Concept

This lesson introduces the square root, the inverse of squaring a number. You'll learn how to find values like 25\sqrt{25}, estimate others like 60\sqrt{60}, and apply this skill to solve real-world problems.

What’s next

Now that you have the basics, you'll tackle interactive examples, practice problems, and real-world challenges to master using square roots.

Section 2

Square of a number

Property

If n2=mn^2 = m, then mm is the square of nn. A perfect square is the square of a whole number. Squaring a positive or negative number results in a positive number.

Examples

  • The square of 8 is 64, because 82=8Γ—8=648^2 = 8 \times 8 = 64.
  • The number 144 is a perfect square, as it is the square of a whole number: 122=14412^2 = 144.
  • The square of βˆ’5-5 is 25, since (βˆ’5)2=(βˆ’5)(βˆ’5)=25(-5)^2 = (-5)(-5) = 25.

Explanation

Squaring a number means multiplying it by itself. This concept is named after a geometric square, where the area is the side length multiplied by itself. Perfect squares are the result of squaring whole numbers, like 9 from 323^2.

Section 3

Square root of a number

Property

A number whose square is mm is called a square root of mm. If n2=mn^2 = m, then nn is a square root of mm. The notation m\sqrt{m} is read as 'the square root of mm' and represents the positive square root, or principal square root. For nβ‰₯0n \ge 0, if m=n2m = n^2, then m=n\sqrt{m} = n.

Examples

  • Since 52=255^2 = 25, the principal square root of 25 is 25=5\sqrt{25} = 5.
  • To indicate the negative square root of 100, we write βˆ’100-\sqrt{100}, which simplifies to βˆ’10-10.
  • Zero has only one square root. Because 02=00^2 = 0, we have 0=0\sqrt{0} = 0.

Explanation

Finding a square root is the inverse operation of squaring a number. The radical symbol m\sqrt{m} asks for the positive number that, when multiplied by itself, equals mm. Every positive number actually has two square roots: one positive and one negative.

Section 4

Square roots and operations

Property

When using the order of operations, treat the radical sign as a grouping symbol. Simplify any expressions under the radical sign before performing other operations. For any negative number, there is no real number solution for its square root.

Examples

  • To simplify 9+16\sqrt{9 + 16}, you must first add the numbers inside the radical to get 25\sqrt{25}, which equals 55.
  • To simplify 9+16\sqrt{9} + \sqrt{16}, you find each square root separately before adding: 3+4=73 + 4 = 7. Note this is different from the first example.
  • The expression βˆ’169\sqrt{-169} is not a real number because no real number multiplied by itself can result in βˆ’169-169.

Explanation

The radical sign acts like parentheses, so you must simplify the expression inside it first. You cannot take the square root of a negative number in the real number system because squaring any real number always results in a non-negative value.

Section 5

Estimate and approximate square roots

Property

To estimate a square root, locate it between two consecutive perfect squares.

Examples

  • To estimate 70\sqrt{70}, we know 82=648^2 = 64 and 92=819^2 = 81. Since 70 is between 64 and 81, we know that 8<70<98 < \sqrt{70} < 9.
  • Using a calculator to find 17\sqrt{17} and rounding to two decimal places gives the approximation 17β‰ˆ4.12\sqrt{17} \approx 4.12.
  • To estimate 172\sqrt{172}, notice it is between the perfect squares 169169 (13213^2) and 196196 (14214^2). Therefore, 13<172<1413 < \sqrt{172} < 14.

Explanation

Not all numbers have whole number square roots. For these non-perfect squares, we can estimate the root's value by identifying the two closest perfect squares. A calculator provides a more precise but still approximate decimal value.

Section 6

Simplify variable expressions with square roots

Property

To simplify a square root containing a variable, find an expression that, when squared, equals the expression inside the radical. In this context, we assume all variables in a square root expression are non-negative.

Examples

  • To simplify y2\sqrt{y^2}, we recognize that (y)2=y2(y)^2 = y^2, so y2=y\sqrt{y^2} = y.
  • To simplify 49x2\sqrt{49x^2}, find the square root of 49 (which is 7) and the square root of x2x^2 (which is xx), giving a result of 7x7x.
  • To simplify βˆ’100y2-\sqrt{100y^2}, the negative sign stays outside. Since 100y2=10y\sqrt{100y^2} = 10y, the expression simplifies to βˆ’10y-10y.

Explanation

When simplifying square roots with variables, think 'what expression, when squared, gives me this?'. Assuming variables are non-negative, x2\sqrt{x^2} simplifies to xx. You can find the square root of the coefficient and the variable part separately.

Section 7

Use square roots in applications

Property

Square roots are used in various real-world formulas.

Examples

  • If a square patio has an area of 200 square feet, the length of one side is 200β‰ˆ14.1\sqrt{200} \approx 14.1 feet.
  • If a pair of sunglasses is dropped from a bridge 400 feet high, the time it takes to reach the river is 4004=100=5\sqrt{\frac{400}{4}} = \sqrt{100} = 5 seconds.
  • If a car's skid marks measure 190 feet, its speed before braking was 24β‹…190=4560β‰ˆ67.5\sqrt{24 \cdot 190} = \sqrt{4560} \approx 67.5 miles per hour.

Explanation

Square roots are essential for solving practical problems, especially when you need to reverse a squaring operation. This is common in geometry for finding lengths from areas and in physics for formulas involving time, speed, and distance.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Decimals

  1. Lesson 1

    Lesson 1: Decimals

  2. Lesson 2

    Lesson 2: Decimal Operations

  3. Lesson 3

    Lesson 3: Decimals and Fractions

  4. Lesson 4

    Lesson 4: Solve Equations with Decimals

  5. Lesson 5

    Lesson 5: Averages and Probability

  6. Lesson 6

    Lesson 6: Ratios and Rate

  7. Lesson 7Current

    Lesson 7: Simplify and Use Square Roots