Learn on PengiOpenstax Prealgebre 2EChapter 6: Percents

Lesson 5: Solve Proportions and their Applications

In this lesson from OpenStax Prealgebra 2E, students learn how to define and write proportions, solve for unknown values using cross products, and apply proportional reasoning to real-world rate and ratio problems. The lesson also covers how to translate percent equations into proportion form and solve percent proportions. It is designed for middle school prealgebra students building foundational skills in ratios, rates, and percent calculations.

Section 1

πŸ“˜ Solve Proportions and their Applications

New Concept

A proportion is an equation stating two ratios are equal, like ab=cd\frac{a}{b} = \frac{c}{d}. This lesson shows how to use this powerful tool to find unknown quantities in real-world scenarios and even solve percent problems.

What’s next

Next, you’ll work through examples and interactive practice problems to master solving proportions and applying them to real-world challenges.

Section 2

Definition of proportion

Property

A proportion is an equation of the form ab=cd\frac{a}{b} = \frac{c}{d}, where b≠0,d≠0b \neq 0, d \neq 0. The proportion states two ratios or rates are equal. For any proportion of this form, its cross products are equal: a⋅d=b⋅ca \cdot d = b \cdot c. Cross products can be used to test whether a proportion is true.

Examples

  • The sentence "4 is to 9 as 20 is to 45" is written as the proportion 49=2045\frac{4}{9} = \frac{20}{45}.
  • To determine if 611=3055\frac{6}{11} = \frac{30}{55} is a proportion, we check the cross products. Since 6β‹…55=3306 \cdot 55 = 330 and 11β‹…30=33011 \cdot 30 = 330, the equation is a proportion.
  • To check if 810=3040\frac{8}{10} = \frac{30}{40} is a proportion, we find the cross products. 8β‹…40=3208 \cdot 40 = 320 and 10β‹…30=30010 \cdot 30 = 300. Since the products are not equal, it is not a proportion.

Explanation

A proportion is a statement that two ratios are equal, like a balanced scale. The cross-product rule is a quick check: if the products of the numbers on the diagonal are equal, the ratios form a true proportion.

Section 3

Solving proportions

Property

To solve a proportion for a variable, you can use the property of equal cross products. For a proportion like ab=cd\frac{a}{b} = \frac{c}{d}, set the cross products equal, aβ‹…d=bβ‹…ca \cdot d = b \cdot c, and then solve the resulting equation for the unknown variable.

Examples

  • To solve x63=47\frac{x}{63} = \frac{4}{7}, set cross products equal: 7β‹…x=63β‹…47 \cdot x = 63 \cdot 4. This gives 7x=2527x = 252, so x=36x = 36.
  • To solve 144a=94\frac{144}{a} = \frac{9}{4}, set cross products equal: 144β‹…4=9β‹…a144 \cdot 4 = 9 \cdot a. This gives 576=9a576 = 9a, so a=64a = 64.
  • To solve 5291=βˆ’4y\frac{52}{91} = \frac{-4}{y}, set cross products equal: 52β‹…y=91β‹…(βˆ’4)52 \cdot y = 91 \cdot (-4). This gives 52y=βˆ’36452y = -364, so y=βˆ’7y = -7.

Explanation

When a number in a proportion is missing, we use algebra to find it. The cross-product method is the fastest way to turn the proportion into a simple equation that you can solve for the unknown value.

Section 4

Solving application problems

Property

To solve a word problem using proportions, first identify the two quantities being compared and set up two equal ratios. Let a variable represent the unknown quantity. Ensure that the units are placed consistently in the numerators and denominators of the ratios.
unitΒ AΒ quantityΒ 1unitΒ BΒ quantityΒ 1=unitΒ AΒ quantityΒ 2unitΒ BΒ quantityΒ 2\frac{\text{unit A quantity 1}}{\text{unit B quantity 1}} = \frac{\text{unit A quantity 2}}{\text{unit B quantity 2}}

Examples

  • A doctor prescribes 5 ml of medicine for every 25 pounds of weight. For a child weighing 80 pounds, we set up 5Β ml25Β lbs=a80Β lbs\frac{5 \text{ ml}}{25 \text{ lbs}} = \frac{a}{80 \text{ lbs}}. Solving gives 25a=40025a = 400, so a=16a = 16 ml.
  • A bag of popcorn with 3.5 servings has 120 calories per serving. To find total calories, set up 120Β calories1Β serving=c3.5Β servings\frac{120 \text{ calories}}{1 \text{ serving}} = \frac{c}{3.5 \text{ servings}}. Solving gives c=120β‹…3.5=420c = 120 \cdot 3.5 = 420 calories.
  • If 1 U.S. dollar equals 12.54 Mexican pesos, to find how many pesos is 325 dollars, set up 1Β dollar12.54Β pesos=325Β dollarsp\frac{1 \text{ dollar}}{12.54 \text{ pesos}} = \frac{325 \text{ dollars}}{p}. Solving gives p=325β‹…12.54=4075.5p = 325 \cdot 12.54 = 4075.5 pesos.

Explanation

Proportions are fantastic for real-world problems like scaling a recipe or converting units. The key is to set up your ratios carefully, making sure the corresponding units are in the same position on both sides of the equation.

Section 5

Percent proportion

Property

A percent proportion is an equation where a percent is equal to an equivalent ratio. The amount is to the base as the percent is to 100.
amountbase=percent100\frac{\text{amount}}{\text{base}} = \frac{\text{percent}}{100}
We can restate this as: The amount out of the base is the same as the percent out of one hundred.

Examples

  • To solve "What number is 45% of 80?", set up the proportion n80=45100\frac{n}{80} = \frac{45}{100}. Cross-multiply to get 100n=3600100n = 3600, so n=36n=36.
  • To solve "6.5% of what number is 1.56 dollars?", set up 1.56n=6.5100\frac{1.56}{n} = \frac{6.5}{100}. Cross-multiply to get 156=6.5n156 = 6.5n, so n=24n=24.
  • To solve "What percent of 72 is 9?", set up 972=p100\frac{9}{72} = \frac{p}{100}. Cross-multiply to get 900=72p900 = 72p, so p=12.5p=12.5. The answer is 12.5%.

Explanation

This special proportion is a powerful tool for any percent problem. It turns sentences like "What is 25% of 80?" into an equation you can easily solve by finding the missing piece. Just fill in what you know!

Book overview

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Chapter 6: Percents

  1. Lesson 1

    Lesson 1: Understand Percent

  2. Lesson 2

    Lesson 2: Solve General Applications of Percent

  3. Lesson 3

    Lesson 3: Solve Sales Tax, Commission, and Discount Applications

  4. Lesson 4

    Lesson 4: Solve Simple Interest Applications

  5. Lesson 5Current

    Lesson 5: Solve Proportions and their Applications

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Solve Proportions and their Applications

New Concept

A proportion is an equation stating two ratios are equal, like ab=cd\frac{a}{b} = \frac{c}{d}. This lesson shows how to use this powerful tool to find unknown quantities in real-world scenarios and even solve percent problems.

What’s next

Next, you’ll work through examples and interactive practice problems to master solving proportions and applying them to real-world challenges.

Section 2

Definition of proportion

Property

A proportion is an equation of the form ab=cd\frac{a}{b} = \frac{c}{d}, where b≠0,d≠0b \neq 0, d \neq 0. The proportion states two ratios or rates are equal. For any proportion of this form, its cross products are equal: a⋅d=b⋅ca \cdot d = b \cdot c. Cross products can be used to test whether a proportion is true.

Examples

  • The sentence "4 is to 9 as 20 is to 45" is written as the proportion 49=2045\frac{4}{9} = \frac{20}{45}.
  • To determine if 611=3055\frac{6}{11} = \frac{30}{55} is a proportion, we check the cross products. Since 6β‹…55=3306 \cdot 55 = 330 and 11β‹…30=33011 \cdot 30 = 330, the equation is a proportion.
  • To check if 810=3040\frac{8}{10} = \frac{30}{40} is a proportion, we find the cross products. 8β‹…40=3208 \cdot 40 = 320 and 10β‹…30=30010 \cdot 30 = 300. Since the products are not equal, it is not a proportion.

Explanation

A proportion is a statement that two ratios are equal, like a balanced scale. The cross-product rule is a quick check: if the products of the numbers on the diagonal are equal, the ratios form a true proportion.

Section 3

Solving proportions

Property

To solve a proportion for a variable, you can use the property of equal cross products. For a proportion like ab=cd\frac{a}{b} = \frac{c}{d}, set the cross products equal, aβ‹…d=bβ‹…ca \cdot d = b \cdot c, and then solve the resulting equation for the unknown variable.

Examples

  • To solve x63=47\frac{x}{63} = \frac{4}{7}, set cross products equal: 7β‹…x=63β‹…47 \cdot x = 63 \cdot 4. This gives 7x=2527x = 252, so x=36x = 36.
  • To solve 144a=94\frac{144}{a} = \frac{9}{4}, set cross products equal: 144β‹…4=9β‹…a144 \cdot 4 = 9 \cdot a. This gives 576=9a576 = 9a, so a=64a = 64.
  • To solve 5291=βˆ’4y\frac{52}{91} = \frac{-4}{y}, set cross products equal: 52β‹…y=91β‹…(βˆ’4)52 \cdot y = 91 \cdot (-4). This gives 52y=βˆ’36452y = -364, so y=βˆ’7y = -7.

Explanation

When a number in a proportion is missing, we use algebra to find it. The cross-product method is the fastest way to turn the proportion into a simple equation that you can solve for the unknown value.

Section 4

Solving application problems

Property

To solve a word problem using proportions, first identify the two quantities being compared and set up two equal ratios. Let a variable represent the unknown quantity. Ensure that the units are placed consistently in the numerators and denominators of the ratios.
unitΒ AΒ quantityΒ 1unitΒ BΒ quantityΒ 1=unitΒ AΒ quantityΒ 2unitΒ BΒ quantityΒ 2\frac{\text{unit A quantity 1}}{\text{unit B quantity 1}} = \frac{\text{unit A quantity 2}}{\text{unit B quantity 2}}

Examples

  • A doctor prescribes 5 ml of medicine for every 25 pounds of weight. For a child weighing 80 pounds, we set up 5Β ml25Β lbs=a80Β lbs\frac{5 \text{ ml}}{25 \text{ lbs}} = \frac{a}{80 \text{ lbs}}. Solving gives 25a=40025a = 400, so a=16a = 16 ml.
  • A bag of popcorn with 3.5 servings has 120 calories per serving. To find total calories, set up 120Β calories1Β serving=c3.5Β servings\frac{120 \text{ calories}}{1 \text{ serving}} = \frac{c}{3.5 \text{ servings}}. Solving gives c=120β‹…3.5=420c = 120 \cdot 3.5 = 420 calories.
  • If 1 U.S. dollar equals 12.54 Mexican pesos, to find how many pesos is 325 dollars, set up 1Β dollar12.54Β pesos=325Β dollarsp\frac{1 \text{ dollar}}{12.54 \text{ pesos}} = \frac{325 \text{ dollars}}{p}. Solving gives p=325β‹…12.54=4075.5p = 325 \cdot 12.54 = 4075.5 pesos.

Explanation

Proportions are fantastic for real-world problems like scaling a recipe or converting units. The key is to set up your ratios carefully, making sure the corresponding units are in the same position on both sides of the equation.

Section 5

Percent proportion

Property

A percent proportion is an equation where a percent is equal to an equivalent ratio. The amount is to the base as the percent is to 100.
amountbase=percent100\frac{\text{amount}}{\text{base}} = \frac{\text{percent}}{100}
We can restate this as: The amount out of the base is the same as the percent out of one hundred.

Examples

  • To solve "What number is 45% of 80?", set up the proportion n80=45100\frac{n}{80} = \frac{45}{100}. Cross-multiply to get 100n=3600100n = 3600, so n=36n=36.
  • To solve "6.5% of what number is 1.56 dollars?", set up 1.56n=6.5100\frac{1.56}{n} = \frac{6.5}{100}. Cross-multiply to get 156=6.5n156 = 6.5n, so n=24n=24.
  • To solve "What percent of 72 is 9?", set up 972=p100\frac{9}{72} = \frac{p}{100}. Cross-multiply to get 900=72p900 = 72p, so p=12.5p=12.5. The answer is 12.5%.

Explanation

This special proportion is a powerful tool for any percent problem. It turns sentences like "What is 25% of 80?" into an equation you can easily solve by finding the missing piece. Just fill in what you know!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Percents

  1. Lesson 1

    Lesson 1: Understand Percent

  2. Lesson 2

    Lesson 2: Solve General Applications of Percent

  3. Lesson 3

    Lesson 3: Solve Sales Tax, Commission, and Discount Applications

  4. Lesson 4

    Lesson 4: Solve Simple Interest Applications

  5. Lesson 5Current

    Lesson 5: Solve Proportions and their Applications