Learn on PengienVision, Mathematics, Grade 7Chapter 3: Analyze and Solve Percent Problems

Lesson 5: Solve Markup and Markdown Problems

In this Grade 7 lesson from enVision Mathematics Chapter 3, students learn how to solve percent markup and markdown problems using the percent equation. They calculate the percent markup by finding the difference between selling price and cost, then dividing by the original cost, and apply the same approach in reverse to find marked-down sale prices and final costs including sales tax. The lesson builds directly on students' understanding of percent increase and decrease within real-world retail and shopping contexts.

Section 1

Mark-Up

Property

The formulas for calculating a mark-up are:

amount of mark-up=mark-up rate×original cost\text{amount of mark-up} = \text{mark-up rate} \times \text{original cost}
list price=original cost+amount of mark up\text{list price} = \text{original cost} + \text{amount of mark up}

Keep in mind that the list price should always be more than the original cost.

Examples

  • An art gallery buys a sculpture for 400 dollars and marks the price up by 60%. What is the amount of mark-up and the list price?

The amount of mark-up is 0.60×400=2400.60 \times 400 = 240 dollars. The list price is 400+240=640400 + 240 = 640 dollars.

  • A music store buys a guitar for 1,500 dollars and sells it for 2,100 dollars. What is the amount of mark-up and the mark-up rate?

The amount of mark-up is 21001500=6002100 - 1500 = 600 dollars. To find the rate, solve 600=r1500600 = r \cdot 1500, which gives r=0.4r = 0.4, or a 40% mark-up rate.

Section 2

Discount

Property

An amount of discount is a percent off the original price.

amount of discount=discount rateoriginal price\text{amount of discount} = \text{discount rate} \cdot \text{original price}
sale price=original priceamount of discount\text{sale price} = \text{original price} - \text{amount of discount}

Section 3

Markup in Retail

Property

Markup in the retail industry means the percentage of cost for an item that is added to set the sale price of the item. If the markup is m%m\%, then the sale price for an item costing CC dollars will be:

C+m100CC + \frac{m}{100}C

Examples

  • A bookstore buys a novel for 10 dollars and applies a 40% markup. The sale price is 10+40100(10)=10+4=1410 + \frac{40}{100}(10) = 10 + 4 = 14 dollars.
  • A toy store's cost for a doll is 25 dollars. With a 20% markup, the customer price is 25+20100(25)=25+5=3025 + \frac{20}{100}(25) = 25 + 5 = 30 dollars.
  • An electronics store uses a 15% markup on headphones that cost 80 dollars. The sale price becomes 80+15100(80)=80+12=9280 + \frac{15}{100}(80) = 80 + 12 = 92 dollars.

Explanation

Markup is how stores make a profit. They buy an item at a cost price and add a percentage on top to get the selling price. This extra amount covers their expenses and earnings.

Book overview

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Chapter 3: Analyze and Solve Percent Problems

  1. Lesson 1

    Lesson 1: Analyze Percents of Numbers

  2. Lesson 2

    Lesson 2: Connect Percent and Proportion

  3. Lesson 3

    Lesson 3: Represent and Use the Percent Equation

  4. Lesson 4

    Lesson 4: Solve Percent Change and Percent Error Problems

  5. Lesson 5Current

    Lesson 5: Solve Markup and Markdown Problems

  6. Lesson 6

    Lesson 6: Solve Simple Interest Problems

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Mark-Up

Property

The formulas for calculating a mark-up are:

amount of mark-up=mark-up rate×original cost\text{amount of mark-up} = \text{mark-up rate} \times \text{original cost}
list price=original cost+amount of mark up\text{list price} = \text{original cost} + \text{amount of mark up}

Keep in mind that the list price should always be more than the original cost.

Examples

  • An art gallery buys a sculpture for 400 dollars and marks the price up by 60%. What is the amount of mark-up and the list price?

The amount of mark-up is 0.60×400=2400.60 \times 400 = 240 dollars. The list price is 400+240=640400 + 240 = 640 dollars.

  • A music store buys a guitar for 1,500 dollars and sells it for 2,100 dollars. What is the amount of mark-up and the mark-up rate?

The amount of mark-up is 21001500=6002100 - 1500 = 600 dollars. To find the rate, solve 600=r1500600 = r \cdot 1500, which gives r=0.4r = 0.4, or a 40% mark-up rate.

Section 2

Discount

Property

An amount of discount is a percent off the original price.

amount of discount=discount rateoriginal price\text{amount of discount} = \text{discount rate} \cdot \text{original price}
sale price=original priceamount of discount\text{sale price} = \text{original price} - \text{amount of discount}

Section 3

Markup in Retail

Property

Markup in the retail industry means the percentage of cost for an item that is added to set the sale price of the item. If the markup is m%m\%, then the sale price for an item costing CC dollars will be:

C+m100CC + \frac{m}{100}C

Examples

  • A bookstore buys a novel for 10 dollars and applies a 40% markup. The sale price is 10+40100(10)=10+4=1410 + \frac{40}{100}(10) = 10 + 4 = 14 dollars.
  • A toy store's cost for a doll is 25 dollars. With a 20% markup, the customer price is 25+20100(25)=25+5=3025 + \frac{20}{100}(25) = 25 + 5 = 30 dollars.
  • An electronics store uses a 15% markup on headphones that cost 80 dollars. The sale price becomes 80+15100(80)=80+12=9280 + \frac{15}{100}(80) = 80 + 12 = 92 dollars.

Explanation

Markup is how stores make a profit. They buy an item at a cost price and add a percentage on top to get the selling price. This extra amount covers their expenses and earnings.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Analyze and Solve Percent Problems

  1. Lesson 1

    Lesson 1: Analyze Percents of Numbers

  2. Lesson 2

    Lesson 2: Connect Percent and Proportion

  3. Lesson 3

    Lesson 3: Represent and Use the Percent Equation

  4. Lesson 4

    Lesson 4: Solve Percent Change and Percent Error Problems

  5. Lesson 5Current

    Lesson 5: Solve Markup and Markdown Problems

  6. Lesson 6

    Lesson 6: Solve Simple Interest Problems