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Lesson 5: Graphing Linear Equations in Slope-Intercept Form

Property To find the slope of a line from its graph: 1. Locate two points on the graph whose coordinates are integers. 2. Starting with the point on the left, sketch a right triangle, going from the first point to the second point. 3. Count the rise and the run on the legs of the triangle. 4. Take the ratio of rise to run to find the slope, $m = \frac{\operatorname{rise}}{\operatorname{run}}$.

Section 1

Find Slope from a Graph

Property

To find the slope of a line from its graph:

  1. Locate two points on the graph whose coordinates are integers.
  2. Starting with the point on the left, sketch a right triangle, going from the first point to the second point.
  3. Count the rise and the run on the legs of the triangle.
  4. Take the ratio of rise to run to find the slope, m=riserunm = \frac{\operatorname{rise}}{\operatorname{run}}.

Examples

  • A line passes through (1,2)(1, 2) and (4,8)(4, 8). The rise is 82=68 - 2 = 6 and the run is 41=34 - 1 = 3. The slope is m=63=2m = \frac{6}{3} = 2.
  • A line passes through (0,6)(0, 6) and (2,2)(2, 2). The rise is 26=42 - 6 = -4 and the run is 20=22 - 0 = 2. The slope is m=42=2m = \frac{-4}{2} = -2.
  • A line on a graph connects points (3,1)(-3, 1) and (5,7)(5, 7). The rise is 71=67-1=6 and the run is 5(3)=85-(-3)=8. The slope is m=68=34m = \frac{6}{8} = \frac{3}{4}.

Explanation

To find slope from a graph, pick two easy-to-read points. Count the vertical distance (rise) and horizontal distance (run) to get from one point to the other. The slope is simply the rise divided by the run.

Section 2

Slope Formula

Property

The slope of the line between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. This is the slope formula. The slope is the difference in the y-coordinates divided by the difference in the x-coordinates.

Examples

  • For the points (2,5)(2, 5) and (4,11)(4, 11), the slope is m=11542=62=3m = \frac{11 - 5}{4 - 2} = \frac{6}{2} = 3.
  • For the points (3,6)(-3, 6) and (1,4)(1, 4), the slope is m=461(3)=24=12m = \frac{4 - 6}{1 - (-3)} = \frac{-2}{4} = -\frac{1}{2}.
  • For the points (5,1)(5, -1) and (2,3)(-2, 3), the slope is m=3(1)25=47=47m = \frac{3 - (-1)}{-2 - 5} = \frac{4}{-7} = -\frac{4}{7}.

Explanation

The slope formula is a tool to find a line's steepness without a graph. It calculates the rise by subtracting y-values (y2y1y_2 - y_1) and the run by subtracting x-values (x2x1x_2 - x_1), then divides them.

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Chapter 3: Graphing Linear Functions

  1. Lesson 1

    Lesson 1: Functions

  2. Lesson 2

    Lesson 2: Linear Functions

  3. Lesson 3

    Lesson 3: Function Notation

  4. Lesson 4

    Lesson 4: Graphing Linear Equations in Standard Form

  5. Lesson 5Current

    Lesson 5: Graphing Linear Equations in Slope-Intercept Form

  6. Lesson 6

    Lesson 6: Transformations of Graphs of Linear Functions

  7. Lesson 7

    Lesson 7: Graphing Absolute Value Functions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Find Slope from a Graph

Property

To find the slope of a line from its graph:

  1. Locate two points on the graph whose coordinates are integers.
  2. Starting with the point on the left, sketch a right triangle, going from the first point to the second point.
  3. Count the rise and the run on the legs of the triangle.
  4. Take the ratio of rise to run to find the slope, m=riserunm = \frac{\operatorname{rise}}{\operatorname{run}}.

Examples

  • A line passes through (1,2)(1, 2) and (4,8)(4, 8). The rise is 82=68 - 2 = 6 and the run is 41=34 - 1 = 3. The slope is m=63=2m = \frac{6}{3} = 2.
  • A line passes through (0,6)(0, 6) and (2,2)(2, 2). The rise is 26=42 - 6 = -4 and the run is 20=22 - 0 = 2. The slope is m=42=2m = \frac{-4}{2} = -2.
  • A line on a graph connects points (3,1)(-3, 1) and (5,7)(5, 7). The rise is 71=67-1=6 and the run is 5(3)=85-(-3)=8. The slope is m=68=34m = \frac{6}{8} = \frac{3}{4}.

Explanation

To find slope from a graph, pick two easy-to-read points. Count the vertical distance (rise) and horizontal distance (run) to get from one point to the other. The slope is simply the rise divided by the run.

Section 2

Slope Formula

Property

The slope of the line between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}. This is the slope formula. The slope is the difference in the y-coordinates divided by the difference in the x-coordinates.

Examples

  • For the points (2,5)(2, 5) and (4,11)(4, 11), the slope is m=11542=62=3m = \frac{11 - 5}{4 - 2} = \frac{6}{2} = 3.
  • For the points (3,6)(-3, 6) and (1,4)(1, 4), the slope is m=461(3)=24=12m = \frac{4 - 6}{1 - (-3)} = \frac{-2}{4} = -\frac{1}{2}.
  • For the points (5,1)(5, -1) and (2,3)(-2, 3), the slope is m=3(1)25=47=47m = \frac{3 - (-1)}{-2 - 5} = \frac{4}{-7} = -\frac{4}{7}.

Explanation

The slope formula is a tool to find a line's steepness without a graph. It calculates the rise by subtracting y-values (y2y1y_2 - y_1) and the run by subtracting x-values (x2x1x_2 - x_1), then divides them.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Graphing Linear Functions

  1. Lesson 1

    Lesson 1: Functions

  2. Lesson 2

    Lesson 2: Linear Functions

  3. Lesson 3

    Lesson 3: Function Notation

  4. Lesson 4

    Lesson 4: Graphing Linear Equations in Standard Form

  5. Lesson 5Current

    Lesson 5: Graphing Linear Equations in Slope-Intercept Form

  6. Lesson 6

    Lesson 6: Transformations of Graphs of Linear Functions

  7. Lesson 7

    Lesson 7: Graphing Absolute Value Functions