Learn on PengiPengi Math (Grade 7)Chapter 7: 2D Geometry and Measurement

Lesson 5: Area of Circles

In this Grade 7 Pengi Math lesson from Chapter 7: 2D Geometry and Measurement, students derive and apply the formula for the area of a circle, practicing conversion between diameter and radius to find exact and approximate areas. The lesson extends to calculating the area of semicircles and quadrants before applying these skills to real-world problems involving circular area.

Section 1

Area of a circle

Property

The formula for area of a circle is:

A=πr2A = \pi r^2

Examples

  • A circular sandbox has a radius of 2.5 feet. Its area is A=πr23.14(2.5)2=3.14(6.25)=19.625A = \pi r^2 \approx 3.14(2.5)^2 = 3.14(6.25) = 19.625 square feet.
  • The lid of a paint bucket has a radius of 7 inches. Using π227\pi \approx \frac{22}{7}, the area is A227(7)2=227(49)=154A \approx \frac{22}{7}(7)^2 = \frac{22}{7}(49) = 154 square inches.

Section 2

Area of a Semicircle

Property

A semicircle is exactly half of a full circle. To find its area, calculate the area of the full circle first, and then simply divide by 2:

A=πr22A = \frac{\pi r^2}{2}

Examples

  • Find the area of a semicircle with a radius of 6 cm. Full circle area is 36π36\pi. Semicircle area is 36π/2=18π36\pi / 2 = 18\pi square cm (about 56.52 square cm).
  • A semicircular window has a diameter of 8 feet. First, find the radius (4 feet). Full circle area is 16π16\pi. Semicircle area is 16π/2=8π16\pi / 2 = 8\pi square feet.

Explanation

Don't let semicircles trick you! There is no need to memorize a completely new, complicated formula. Just pretend it is a perfectly normal, full circle, do your standard πr2\pi r^2 math, and at the very end, chop your answer in half.

Book overview

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Chapter 7: 2D Geometry and Measurement

  1. Lesson 1

    Lesson 1: Angle Relationships and Construction

  2. Lesson 2

    Lesson 2: Triangles

  3. Lesson 3

    Lesson 3: Exterior Angles and Polygons

  4. Lesson 4

    Lesson 4: Circumference of Circles

  5. Lesson 5Current

    Lesson 5: Area of Circles

  6. Lesson 6

    Lesson 6: Perimeter and Area of Composite Figures

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Area of a circle

Property

The formula for area of a circle is:

A=πr2A = \pi r^2

Examples

  • A circular sandbox has a radius of 2.5 feet. Its area is A=πr23.14(2.5)2=3.14(6.25)=19.625A = \pi r^2 \approx 3.14(2.5)^2 = 3.14(6.25) = 19.625 square feet.
  • The lid of a paint bucket has a radius of 7 inches. Using π227\pi \approx \frac{22}{7}, the area is A227(7)2=227(49)=154A \approx \frac{22}{7}(7)^2 = \frac{22}{7}(49) = 154 square inches.

Section 2

Area of a Semicircle

Property

A semicircle is exactly half of a full circle. To find its area, calculate the area of the full circle first, and then simply divide by 2:

A=πr22A = \frac{\pi r^2}{2}

Examples

  • Find the area of a semicircle with a radius of 6 cm. Full circle area is 36π36\pi. Semicircle area is 36π/2=18π36\pi / 2 = 18\pi square cm (about 56.52 square cm).
  • A semicircular window has a diameter of 8 feet. First, find the radius (4 feet). Full circle area is 16π16\pi. Semicircle area is 16π/2=8π16\pi / 2 = 8\pi square feet.

Explanation

Don't let semicircles trick you! There is no need to memorize a completely new, complicated formula. Just pretend it is a perfectly normal, full circle, do your standard πr2\pi r^2 math, and at the very end, chop your answer in half.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: 2D Geometry and Measurement

  1. Lesson 1

    Lesson 1: Angle Relationships and Construction

  2. Lesson 2

    Lesson 2: Triangles

  3. Lesson 3

    Lesson 3: Exterior Angles and Polygons

  4. Lesson 4

    Lesson 4: Circumference of Circles

  5. Lesson 5Current

    Lesson 5: Area of Circles

  6. Lesson 6

    Lesson 6: Perimeter and Area of Composite Figures