Learn on PengiBig Ideas Math, Course 2Chapter 6: Percents

Lesson 4: The Percent Equation

In this Grade 7 lesson from Big Ideas Math, Course 2, students learn to use the percent equation (a = p × w) as an equivalent form of the percent proportion to solve percent problems. Students practice finding the part, the percent, and the whole by substituting known values into the equation and solving for the missing quantity. Real-life contexts, such as school election results, are used to connect the percent equation to practical applications.

Section 1

Translate basic percent equations

Property

We will solve percent equations by using the methods we used to solve equations with fractions or decimals. As a prealgebra student, you can translate word sentences into algebraic equations, and then solve the equations. To solve a basic percent problem, we translate it into a percent equation: we find the amount by multiplying the percent by the base. We must be sure to change the given percent to a decimal when we translate the words into an equation.

Examples

  • What number is 40% of 150? First, translate this into an equation: n=0.40150n = 0.40 \cdot 150. Then, multiply to find the answer: n=60n = 60.
  • 50 is 25% of what number? First, translate this into an equation: 50=0.25b50 = 0.25 \cdot b. Then, divide both sides by 0.25 to solve for bb: b=200b = 200.
  • What percent of 80 is 16? First, translate this into an equation, letting pp be the percent: p80=16p \cdot 80 = 16. Then, divide by 80 to solve for pp: p=0.20p = 0.20, which is 20%.

Explanation

Think of every percent problem as a simple sentence: Part is Percent of Whole. By identifying these three pieces and using a variable for the unknown, you can write a simple multiplication or division equation to find your answer.

Section 2

Basic Percent Equations

Property

To solve percent problems, we translate English sentences into algebraic equations and then solve them. We must be sure to change the given percent to a decimal when we put it in the equation. The three basic types of percent equations are:

  1. Finding the amount: What number is 35% of 90? translates to n=0.3590n = 0.35 \cdot 90
  2. Finding the base: 6.5% of what number is 1.17 dollars? translates to 0.065n=1.170.065 \cdot n = 1.17
  3. Finding the percent: 144 is what percent of 96? translates to 144=p96144 = p \cdot 96

Examples

  • What number is 25% of 160?

Translate the sentence into an equation: n=0.25160n = 0.25 \cdot 160. Solving this gives n=40n = 40. So, 40 is 25% of 160.

  • 4.5% of what number is 18 dollars?

Translate this as 0.045n=180.045 \cdot n = 18. To find n, divide both sides by 0.045: n=180.045=400n = \frac{18}{0.045} = 400. So, 4.5% of 400 dollars is 18 dollars.

Book overview

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Chapter 6: Percents

  1. Lesson 1

    Lesson 1: Percents and Decimals

  2. Lesson 2

    Lesson 2: Comparing and Ordering Fractions, Decimals, and Percents

  3. Lesson 3

    Lesson 3: The Percent Proportion

  4. Lesson 4Current

    Lesson 4: The Percent Equation

  5. Lesson 5

    Lesson 5: Percents of Increase and Decrease

  6. Lesson 6

    Lesson 6: Discounts and Markups

  7. Lesson 7

    Lesson 7: Simple Interest

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Translate basic percent equations

Property

We will solve percent equations by using the methods we used to solve equations with fractions or decimals. As a prealgebra student, you can translate word sentences into algebraic equations, and then solve the equations. To solve a basic percent problem, we translate it into a percent equation: we find the amount by multiplying the percent by the base. We must be sure to change the given percent to a decimal when we translate the words into an equation.

Examples

  • What number is 40% of 150? First, translate this into an equation: n=0.40150n = 0.40 \cdot 150. Then, multiply to find the answer: n=60n = 60.
  • 50 is 25% of what number? First, translate this into an equation: 50=0.25b50 = 0.25 \cdot b. Then, divide both sides by 0.25 to solve for bb: b=200b = 200.
  • What percent of 80 is 16? First, translate this into an equation, letting pp be the percent: p80=16p \cdot 80 = 16. Then, divide by 80 to solve for pp: p=0.20p = 0.20, which is 20%.

Explanation

Think of every percent problem as a simple sentence: Part is Percent of Whole. By identifying these three pieces and using a variable for the unknown, you can write a simple multiplication or division equation to find your answer.

Section 2

Basic Percent Equations

Property

To solve percent problems, we translate English sentences into algebraic equations and then solve them. We must be sure to change the given percent to a decimal when we put it in the equation. The three basic types of percent equations are:

  1. Finding the amount: What number is 35% of 90? translates to n=0.3590n = 0.35 \cdot 90
  2. Finding the base: 6.5% of what number is 1.17 dollars? translates to 0.065n=1.170.065 \cdot n = 1.17
  3. Finding the percent: 144 is what percent of 96? translates to 144=p96144 = p \cdot 96

Examples

  • What number is 25% of 160?

Translate the sentence into an equation: n=0.25160n = 0.25 \cdot 160. Solving this gives n=40n = 40. So, 40 is 25% of 160.

  • 4.5% of what number is 18 dollars?

Translate this as 0.045n=180.045 \cdot n = 18. To find n, divide both sides by 0.045: n=180.045=400n = \frac{18}{0.045} = 400. So, 4.5% of 400 dollars is 18 dollars.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Percents

  1. Lesson 1

    Lesson 1: Percents and Decimals

  2. Lesson 2

    Lesson 2: Comparing and Ordering Fractions, Decimals, and Percents

  3. Lesson 3

    Lesson 3: The Percent Proportion

  4. Lesson 4Current

    Lesson 4: The Percent Equation

  5. Lesson 5

    Lesson 5: Percents of Increase and Decrease

  6. Lesson 6

    Lesson 6: Discounts and Markups

  7. Lesson 7

    Lesson 7: Simple Interest