Property
A multi-step inequality models real-world scenarios involving a fixed cost plus a variable rate, or comparing two different plans.
- Define a variable (e.g., let x be the number of items).
- Translate keywords: "at least" (≥), "at most" (≤), "more than" (>), "fewer than" (<).
- Build the inequality: Fixed Amount + (Rate * Variable).
- Solve and interpret the result practically (e.g., you cannot buy half a ticket).
Examples
- Example 1 (Budget Constraint): A gym membership costs 30permonthplus5 per guest pass. If you want to spend at most 55thismonth,howmanyguestpasses(g$) can you buy?
Inequality: 30+5g≤55.
Solve: Subtract 30 to get 5g≤25, then divide by 5 to get g≤5. You can buy at most 5 guest passes.
- Example 2 (Comparing Plans): Plan A charges a 15monthlyfeeplus0.10 per text. Plan B charges 0.25pertextwithnofee.Forhowmanytexts(t$) is Plan A cheaper (costs less than Plan B)?
Inequality: 15+0.10t<0.25t.
Solve: Subtract 0.10t from both sides to get 15<0.15t. Divide by 0.15 to get 100<t (which is t>100). Plan A is cheaper if you send more than 100 texts.
- Example 3 (Discrete Limits): A phone plan costs 40permonthplus0.15 per text. To keep your bill strictly under 50,howmanytexts(t$) can you send?
Inequality: 40+0.15t<50.
Solve: 0.15t<10→t<66.67. Since you cannot send a fraction of a text, you can send at most 66 texts.
Explanation
Real-world math rarely requires just one step! Most scenarios involve a starting fee that happens once, plus a rate that happens repeatedly. When translating these into math, place your variable next to the rate. Multi-step inequalities are incredibly powerful for making financial decisions, like figuring out exactly when a subscription plan with an upfront fee becomes a better deal than a pay-as-you-go plan.