Learn on PengiBig Ideas Math, Course 2Chapter 4: Inequalities

Lesson 4: Solving Two-Step Inequalities

In this Grade 7 lesson from Big Ideas Math, Course 2 (Chapter 4: Inequalities), students learn to solve two-step inequalities by applying inverse operations in sequence, including cases that require reversing the inequality symbol when multiplying or dividing by a negative number. The lesson connects algebraic procedures to real-world contexts such as calculating areas, perimeters, volumes, and weight-loss averages to model conditions using inequality symbols like greater than or equal to and at most. Students also practice graphing solution sets on number lines to represent the range of values satisfying each inequality.

Section 1

Solving Two-Step Linear Inequalities

Property

A two-step linear inequality has the form ax+b<cax + b < c, ax+bcax + b \leq c, ax+b>cax + b > c, or ax+bcax + b \geq c where a0a \neq 0. To solve a two-step inequality, use inverse operations to isolate the variable in exactly two steps, remembering to reverse the inequality sign when multiplying or dividing by a negative number.

Examples

Section 2

Solving Two-Step Inequalities with Distributive Property

Property

When solving inequalities containing parentheses, first apply the distributive property: a(b+c)=ab+aca(b + c) = ab + ac, then solve using the standard two-step process. Remember to reverse the inequality symbol when multiplying or dividing by a negative number.

Examples

Section 3

Application: Solving Real-World Problems with Multi-Step Inequalities

Property

A multi-step inequality models real-world scenarios involving a fixed cost plus a variable rate, or comparing two different plans.

  1. Define a variable (e.g., let xx be the number of items).
  2. Translate keywords: "at least" (\geq), "at most" (\leq), "more than" (>>), "fewer than" (<<).
  3. Build the inequality: Fixed Amount + (Rate * Variable).
  4. Solve and interpret the result practically (e.g., you cannot buy half a ticket).

Examples

  • Example 1 (Budget Constraint): A gym membership costs 30permonthplus30 per month plus 5 per guest pass. If you want to spend at most 55thismonth,howmanyguestpasses(55 this month, how many guest passes (g$) can you buy?

Inequality: 30+5g5530 + 5g \leq 55.
Solve: Subtract 30 to get 5g255g \leq 25, then divide by 5 to get g5g \leq 5. You can buy at most 5 guest passes.

  • Example 2 (Comparing Plans): Plan A charges a 15monthlyfeeplus15 monthly fee plus 0.10 per text. Plan B charges 0.25pertextwithnofee.Forhowmanytexts(0.25 per text with no fee. For how many texts (t$) is Plan A cheaper (costs less than Plan B)?

Inequality: 15+0.10t<0.25t15 + 0.10t < 0.25t.
Solve: Subtract 0.10t0.10t from both sides to get 15<0.15t15 < 0.15t. Divide by 0.15 to get 100<t100 < t (which is t>100t > 100). Plan A is cheaper if you send more than 100 texts.

  • Example 3 (Discrete Limits): A phone plan costs 40permonthplus40 per month plus 0.15 per text. To keep your bill strictly under 50,howmanytexts(50, how many texts (t$) can you send?

Inequality: 40+0.15t<5040 + 0.15t < 50.
Solve: 0.15t<10t<66.670.15t < 10 \rightarrow t < 66.67. Since you cannot send a fraction of a text, you can send at most 66 texts.

Explanation

Real-world math rarely requires just one step! Most scenarios involve a starting fee that happens once, plus a rate that happens repeatedly. When translating these into math, place your variable next to the rate. Multi-step inequalities are incredibly powerful for making financial decisions, like figuring out exactly when a subscription plan with an upfront fee becomes a better deal than a pay-as-you-go plan.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Inequalities

  1. Lesson 1

    Lesson 1: Writing and Graphing Inequalities

  2. Lesson 2

    Lesson 2: Solving Inequalities Using Addition or Subtraction

  3. Lesson 3

    Lesson 3: Solving Inequalities Using Multiplication or Division

  4. Lesson 4Current

    Lesson 4: Solving Two-Step Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Solving Two-Step Linear Inequalities

Property

A two-step linear inequality has the form ax+b<cax + b < c, ax+bcax + b \leq c, ax+b>cax + b > c, or ax+bcax + b \geq c where a0a \neq 0. To solve a two-step inequality, use inverse operations to isolate the variable in exactly two steps, remembering to reverse the inequality sign when multiplying or dividing by a negative number.

Examples

Section 2

Solving Two-Step Inequalities with Distributive Property

Property

When solving inequalities containing parentheses, first apply the distributive property: a(b+c)=ab+aca(b + c) = ab + ac, then solve using the standard two-step process. Remember to reverse the inequality symbol when multiplying or dividing by a negative number.

Examples

Section 3

Application: Solving Real-World Problems with Multi-Step Inequalities

Property

A multi-step inequality models real-world scenarios involving a fixed cost plus a variable rate, or comparing two different plans.

  1. Define a variable (e.g., let xx be the number of items).
  2. Translate keywords: "at least" (\geq), "at most" (\leq), "more than" (>>), "fewer than" (<<).
  3. Build the inequality: Fixed Amount + (Rate * Variable).
  4. Solve and interpret the result practically (e.g., you cannot buy half a ticket).

Examples

  • Example 1 (Budget Constraint): A gym membership costs 30permonthplus30 per month plus 5 per guest pass. If you want to spend at most 55thismonth,howmanyguestpasses(55 this month, how many guest passes (g$) can you buy?

Inequality: 30+5g5530 + 5g \leq 55.
Solve: Subtract 30 to get 5g255g \leq 25, then divide by 5 to get g5g \leq 5. You can buy at most 5 guest passes.

  • Example 2 (Comparing Plans): Plan A charges a 15monthlyfeeplus15 monthly fee plus 0.10 per text. Plan B charges 0.25pertextwithnofee.Forhowmanytexts(0.25 per text with no fee. For how many texts (t$) is Plan A cheaper (costs less than Plan B)?

Inequality: 15+0.10t<0.25t15 + 0.10t < 0.25t.
Solve: Subtract 0.10t0.10t from both sides to get 15<0.15t15 < 0.15t. Divide by 0.15 to get 100<t100 < t (which is t>100t > 100). Plan A is cheaper if you send more than 100 texts.

  • Example 3 (Discrete Limits): A phone plan costs 40permonthplus40 per month plus 0.15 per text. To keep your bill strictly under 50,howmanytexts(50, how many texts (t$) can you send?

Inequality: 40+0.15t<5040 + 0.15t < 50.
Solve: 0.15t<10t<66.670.15t < 10 \rightarrow t < 66.67. Since you cannot send a fraction of a text, you can send at most 66 texts.

Explanation

Real-world math rarely requires just one step! Most scenarios involve a starting fee that happens once, plus a rate that happens repeatedly. When translating these into math, place your variable next to the rate. Multi-step inequalities are incredibly powerful for making financial decisions, like figuring out exactly when a subscription plan with an upfront fee becomes a better deal than a pay-as-you-go plan.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Inequalities

  1. Lesson 1

    Lesson 1: Writing and Graphing Inequalities

  2. Lesson 2

    Lesson 2: Solving Inequalities Using Addition or Subtraction

  3. Lesson 3

    Lesson 3: Solving Inequalities Using Multiplication or Division

  4. Lesson 4Current

    Lesson 4: Solving Two-Step Inequalities