Learn on PengienVision, Mathematics, Grade 6Chapter 7: Solve Area, Surface Area, and Volume Problems

Lesson 4: Find Areas of Polygons

Grade 6 students practice finding the area of irregular polygons and composite figures by decomposing them into rectangles, triangles, and trapezoids or by subtracting cutout regions from a whole shape. This lesson from Chapter 7 of enVision Mathematics Grade 6 covers applying area formulas to L-shaped rooms, octagons, picture frames, and polygons on coordinate planes. Students also determine which algebraic expressions correctly represent the area of a given polygon.

Section 1

Area of Composite Shapes

Property

The area of a composite shape can be found by adding the areas of its individual parts or by subtracting areas from a larger, simpler shape.
Addition: Atotal=A1+A2A_{total} = A_1 + A_2
Subtraction: Atotal=AlargerAsmallerA_{total} = A_{larger} - A_{smaller}

Examples

  • A shape is formed by a 5×45 \times 4 rectangle and a triangle with a base of 44 and a height of 33 attached to one side. The total area is the area of the rectangle plus the area of the triangle: A=(5×4)+12(4×3)=20+6=26A = (5 \times 4) + \frac{1}{2}(4 \times 3) = 20 + 6 = 26.
  • A large 10×1210 \times 12 rectangular garden has a 3×43 \times 4 rectangular shed inside it. The area of the garden space is the area of the large rectangle minus the area of the shed: A=(10×12)(3×4)=12012=108A = (10 \times 12) - (3 \times 4) = 120 - 12 = 108.

Explanation

Many complex shapes can be viewed as combinations of simpler shapes like rectangles and triangles. To find the area of such a shape, you can break it down into these basic, non-overlapping components and add their individual areas together. Alternatively, if a shape has a hole or a section removed, you can calculate the area of the larger outer shape and subtract the area of the removed inner shape. This addition/subtraction method is a powerful strategy for finding the area of any polygon.

Section 2

Area on the Coordinate Plane

Session 4. Area on the Coordinate Plane

Property

Once a polygon is graphed on a coordinate plane, you can use the grid to measure its base and height. Then, apply the standard area formulas you already know:

  • Rectangle:
    A=bhA = bh
  • Parallelogram:
    A=bhA = bh
  • Triangle:
    A=12bhA = \frac{1}{2}bh
  • Trapezoid:
    A=12h(b1+b2)A = \frac{1}{2}h(b_1 + b_2)

Examples

  • A rectangle has a base of 4 units and height of 7 units. Its area is 4 * 7 = 28 square units.
  • A triangle has a horizontal base on the grid that is 9 units long, and its highest point is 9 units straight up from the base. The area is 1/2 * 9 * 9 = 40.5 square units.

Book overview

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Chapter 7: Solve Area, Surface Area, and Volume Problems

  1. Lesson 1

    Lesson 1: Find Areas of Parallelograms and Rhombuses

  2. Lesson 2

    Lesson 2: Solve Triangle Area Problems

  3. Lesson 3

    Lesson 3: Find Areas of Trapezoids and Kites

  4. Lesson 4Current

    Lesson 4: Find Areas of Polygons

  5. Lesson 5

    Lesson 5: Represent Solid Figures Using Nets

  6. Lesson 6

    Lesson 6: Find Surface Areas of Prisms

  7. Lesson 7

    Lesson 7: Find Surface Areas of Pyramids

  8. Lesson 8

    Lesson 8: Find Volume with Fractional Edge Lengths

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Area of Composite Shapes

Property

The area of a composite shape can be found by adding the areas of its individual parts or by subtracting areas from a larger, simpler shape.
Addition: Atotal=A1+A2A_{total} = A_1 + A_2
Subtraction: Atotal=AlargerAsmallerA_{total} = A_{larger} - A_{smaller}

Examples

  • A shape is formed by a 5×45 \times 4 rectangle and a triangle with a base of 44 and a height of 33 attached to one side. The total area is the area of the rectangle plus the area of the triangle: A=(5×4)+12(4×3)=20+6=26A = (5 \times 4) + \frac{1}{2}(4 \times 3) = 20 + 6 = 26.
  • A large 10×1210 \times 12 rectangular garden has a 3×43 \times 4 rectangular shed inside it. The area of the garden space is the area of the large rectangle minus the area of the shed: A=(10×12)(3×4)=12012=108A = (10 \times 12) - (3 \times 4) = 120 - 12 = 108.

Explanation

Many complex shapes can be viewed as combinations of simpler shapes like rectangles and triangles. To find the area of such a shape, you can break it down into these basic, non-overlapping components and add their individual areas together. Alternatively, if a shape has a hole or a section removed, you can calculate the area of the larger outer shape and subtract the area of the removed inner shape. This addition/subtraction method is a powerful strategy for finding the area of any polygon.

Section 2

Area on the Coordinate Plane

Session 4. Area on the Coordinate Plane

Property

Once a polygon is graphed on a coordinate plane, you can use the grid to measure its base and height. Then, apply the standard area formulas you already know:

  • Rectangle:
    A=bhA = bh
  • Parallelogram:
    A=bhA = bh
  • Triangle:
    A=12bhA = \frac{1}{2}bh
  • Trapezoid:
    A=12h(b1+b2)A = \frac{1}{2}h(b_1 + b_2)

Examples

  • A rectangle has a base of 4 units and height of 7 units. Its area is 4 * 7 = 28 square units.
  • A triangle has a horizontal base on the grid that is 9 units long, and its highest point is 9 units straight up from the base. The area is 1/2 * 9 * 9 = 40.5 square units.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Solve Area, Surface Area, and Volume Problems

  1. Lesson 1

    Lesson 1: Find Areas of Parallelograms and Rhombuses

  2. Lesson 2

    Lesson 2: Solve Triangle Area Problems

  3. Lesson 3

    Lesson 3: Find Areas of Trapezoids and Kites

  4. Lesson 4Current

    Lesson 4: Find Areas of Polygons

  5. Lesson 5

    Lesson 5: Represent Solid Figures Using Nets

  6. Lesson 6

    Lesson 6: Find Surface Areas of Prisms

  7. Lesson 7

    Lesson 7: Find Surface Areas of Pyramids

  8. Lesson 8

    Lesson 8: Find Volume with Fractional Edge Lengths