Learn on PengienVision, Algebra 1Chapter 7: Polynomials and Factoring

Lesson 3: Multiplying Special Cases

In this Grade 11 enVision Algebra 1 lesson from Chapter 7, students learn to apply two special polynomial multiplication patterns: the square of a binomial, expressed as (a+b)² = a² + 2ab + b², and the difference of two squares, expressed as (a+b)(a-b) = a² - b². Students practice using these shortcuts to expand expressions like (5x-3)² and (5x+7)(5x-7), and also apply the patterns to mentally compute products of large numbers. The lesson builds conceptual understanding through visual models, numerical exploration, and a real-world pixel border application problem.

Section 1

Binomial Squares Pattern

Property

If aa and bb are real numbers,

(a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2
(ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2

This pattern is a shortcut for squaring a binomial.
To use it, you square the first term, square the last term, and then add or subtract double the product of the two terms.

Examples

  • To multiply (z+6)2(z+6)^2, we use the pattern (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. Here, a=za=z and b=6b=6. The result is (z)2+2(z)(6)+(6)2(z)^2 + 2(z)(6) + (6)^2, which simplifies to z2+12z+36z^2 + 12z + 36.
  • To multiply (3y+4)2(3y+4)^2, we identify a=3ya=3y and b=4b=4. Using the pattern, we get (3y)2+2(3y)(4)+(4)2(3y)^2 + 2(3y)(4) + (4)^2. This simplifies to 9y2+24y+169y^2 + 24y + 16.

Section 2

Product of Conjugates Pattern

Property

A conjugate pair is two binomials of the form (ab)(a-b) and (a+b)(a+b). They have the same first term and the same last term, but one is a sum and the other is a difference.

If aa and bb are real numbers, the Product of Conjugates Pattern is:

(ab)(a+b)=a2b2(a-b)(a+b) = a^2 - b^2

The product is called a difference of squares.
To multiply conjugates, square the first term, square the last term, and write the result as a difference.

Examples

  • To multiply (p10)(p+10)(p-10)(p+10), we recognize this as a product of conjugates where a=pa=p and b=10b=10. Using the pattern a2b2a^2 - b^2, we get (p)2(10)2(p)^2 - (10)^2, which simplifies to p2100p^2 - 100.

Book overview

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Chapter 7: Polynomials and Factoring

  1. Lesson 1

    Lesson 1: Adding and Subtracting Polynomials

  2. Lesson 2

    Lesson 2: Multiplying Polynomials

  3. Lesson 3Current

    Lesson 3: Multiplying Special Cases

  4. Lesson 4

    Lesson 4: Factoring Polynomials

  5. Lesson 5

    Lesson 5: Factoring x² + bx + c

  6. Lesson 6

    Lesson 6: Factoring ax² + bx + c

  7. Lesson 7

    Lesson 7: Factoring Special Cases

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Binomial Squares Pattern

Property

If aa and bb are real numbers,

(a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2
(ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2

This pattern is a shortcut for squaring a binomial.
To use it, you square the first term, square the last term, and then add or subtract double the product of the two terms.

Examples

  • To multiply (z+6)2(z+6)^2, we use the pattern (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2. Here, a=za=z and b=6b=6. The result is (z)2+2(z)(6)+(6)2(z)^2 + 2(z)(6) + (6)^2, which simplifies to z2+12z+36z^2 + 12z + 36.
  • To multiply (3y+4)2(3y+4)^2, we identify a=3ya=3y and b=4b=4. Using the pattern, we get (3y)2+2(3y)(4)+(4)2(3y)^2 + 2(3y)(4) + (4)^2. This simplifies to 9y2+24y+169y^2 + 24y + 16.

Section 2

Product of Conjugates Pattern

Property

A conjugate pair is two binomials of the form (ab)(a-b) and (a+b)(a+b). They have the same first term and the same last term, but one is a sum and the other is a difference.

If aa and bb are real numbers, the Product of Conjugates Pattern is:

(ab)(a+b)=a2b2(a-b)(a+b) = a^2 - b^2

The product is called a difference of squares.
To multiply conjugates, square the first term, square the last term, and write the result as a difference.

Examples

  • To multiply (p10)(p+10)(p-10)(p+10), we recognize this as a product of conjugates where a=pa=p and b=10b=10. Using the pattern a2b2a^2 - b^2, we get (p)2(10)2(p)^2 - (10)^2, which simplifies to p2100p^2 - 100.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Polynomials and Factoring

  1. Lesson 1

    Lesson 1: Adding and Subtracting Polynomials

  2. Lesson 2

    Lesson 2: Multiplying Polynomials

  3. Lesson 3Current

    Lesson 3: Multiplying Special Cases

  4. Lesson 4

    Lesson 4: Factoring Polynomials

  5. Lesson 5

    Lesson 5: Factoring x² + bx + c

  6. Lesson 6

    Lesson 6: Factoring ax² + bx + c

  7. Lesson 7

    Lesson 7: Factoring Special Cases