Learn on PengiPengi Math (Grade 5)Chapter 2: Multi-Digit Multiplication and Division with Place Value

Lesson 3: Connecting Partial Products to the Standard Algorithm

In this Grade 5 Pengi Math lesson, students learn how partial products connect to the standard multiplication algorithm by using place value reasoning to understand regrouping. They explore and compare different multiplication strategies to build a deeper understanding of multi-digit multiplication. This lesson is part of Chapter 2: Multi-Digit Multiplication and Division with Place Value.

Section 1

Adding Partial Products

Property

The final product of a multiplication problem is the sum of all its partial products.

Product=Sum of all partial products \text{Product} = \text{Sum of all partial products}

Examples

Section 2

Connecting Partial Products and the Standard Algorithm

Property

The standard algorithm for multiplication is a condensed way of calculating and adding partial products. Each row in the standard algorithm corresponds to the sum of partial products involving one of the digits of the bottom multiplier.
For 24×3524 \times 35:

  • Standard Algorithm Row 1: 5×24=1205 \times 24 = 120
  • This equals the sum of two partial products: (5×4)+(5×20)=20+100=120(5 \times 4) + (5 \times 20) = 20 + 100 = 120
  • Standard Algorithm Row 2: 30×24=72030 \times 24 = 720
  • This equals the sum of the other two partial products: (30×4)+(30×20)=120+600=720(30 \times 4) + (30 \times 20) = 120 + 600 = 720

Examples

For 24×3524 \times 35:

  • Standard Algorithm Row 1: 5×24=1205 \times 24 = 120
  • This equals the sum of two partial products: (5×4)+(5×20)=20+100=120(5 \times 4) + (5 \times 20) = 20 + 100 = 120
  • Standard Algorithm Row 2: 30×24=72030 \times 24 = 720
  • This equals the sum of the other two partial products: (30×4)+(30×20)=120+600=720(30 \times 4) + (30 \times 20) = 120 + 600 = 720
  • Final Product: 120+720=840120 + 720 = 840

For 123×45123 \times 45:

  • Standard Algorithm Row 1: 5×123=6155 \times 123 = 615
  • This equals the sum of three partial products: (5×3)+(5×20)+(5×100)=15+100+500=615(5 \times 3) + (5 \times 20) + (5 \times 100) = 15 + 100 + 500 = 615
  • Standard Algorithm Row 2: 40×123=492040 \times 123 = 4920
  • This equals the sum of the other three partial products: (40×3)+(40×20)+(40×100)=120+800+4000=4920(40 \times 3) + (40 \times 20) + (40 \times 100) = 120 + 800 + 4000 = 4920
  • Final Product: 615+4920=5535615 + 4920 = 5535

Explanation

This skill connects the expanded partial products method to the compact standard algorithm. Understanding this connection shows why the standard algorithm works. Each line you write in the standard algorithm is a shortcut for adding a set of partial products together. This helps to build a deeper understanding of the multiplication process beyond just memorizing steps.

Section 3

Multiplying Multi-Digit Numbers

Property

To multiply multi-digit numbers, multiply the top number by each digit of the bottom number, one at a time, from right to left. These intermediate results are called partial products. The final product is the sum of the partial products.

Examples

  • To calculate 86×4286 \times 42:

$$

\begin{array}{r r r r}
& & & 8 & 6 \\
\times & & & 2 & 4 \\
\hline
&& 3 & 4& 4 \\

  • & 1 & 7 & 2 &0 \\

\hline
& 2 & 0 & 6& 4 \\
\end{array}

* To calculate $527 \times 35$:

\begin{array}{r r r r r}
& & & 5 & 2 & 7 \\
\times & & && 3 & 5 \\
\hline
&& 2 & 6 & 3& 5 \\

  • & 1 & 5 & 8 & 1& 0\\

\hline
& 1 & 8 & 4 & 4& 5 \\
\end{array}

* To calculate $1677\times 18$:

Book overview

Jump across lessons in the current chapter without opening the full course modal.

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Chapter 2: Multi-Digit Multiplication and Division with Place Value

  1. Lesson 1

    Lesson 1: Estimating Products Using Rounding and Compatible Numbers

  2. Lesson 2

    Lesson 2: Modeling Multiplication with Area Models and Partial Products

  3. Lesson 3Current

    Lesson 3: Connecting Partial Products to the Standard Algorithm

  4. Lesson 4

    Lesson 4: Understanding Division as Finding a Missing Factor

  5. Lesson 5

    Lesson 5: Dividing Multi-Digit Numbers Using Area Models and Partial Quotients

  6. Lesson 6

    Lesson 6: Applying Division Algorithms and Interpreting Remainders

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Adding Partial Products

Property

The final product of a multiplication problem is the sum of all its partial products.

Product=Sum of all partial products \text{Product} = \text{Sum of all partial products}

Examples

Section 2

Connecting Partial Products and the Standard Algorithm

Property

The standard algorithm for multiplication is a condensed way of calculating and adding partial products. Each row in the standard algorithm corresponds to the sum of partial products involving one of the digits of the bottom multiplier.
For 24×3524 \times 35:

  • Standard Algorithm Row 1: 5×24=1205 \times 24 = 120
  • This equals the sum of two partial products: (5×4)+(5×20)=20+100=120(5 \times 4) + (5 \times 20) = 20 + 100 = 120
  • Standard Algorithm Row 2: 30×24=72030 \times 24 = 720
  • This equals the sum of the other two partial products: (30×4)+(30×20)=120+600=720(30 \times 4) + (30 \times 20) = 120 + 600 = 720

Examples

For 24×3524 \times 35:

  • Standard Algorithm Row 1: 5×24=1205 \times 24 = 120
  • This equals the sum of two partial products: (5×4)+(5×20)=20+100=120(5 \times 4) + (5 \times 20) = 20 + 100 = 120
  • Standard Algorithm Row 2: 30×24=72030 \times 24 = 720
  • This equals the sum of the other two partial products: (30×4)+(30×20)=120+600=720(30 \times 4) + (30 \times 20) = 120 + 600 = 720
  • Final Product: 120+720=840120 + 720 = 840

For 123×45123 \times 45:

  • Standard Algorithm Row 1: 5×123=6155 \times 123 = 615
  • This equals the sum of three partial products: (5×3)+(5×20)+(5×100)=15+100+500=615(5 \times 3) + (5 \times 20) + (5 \times 100) = 15 + 100 + 500 = 615
  • Standard Algorithm Row 2: 40×123=492040 \times 123 = 4920
  • This equals the sum of the other three partial products: (40×3)+(40×20)+(40×100)=120+800+4000=4920(40 \times 3) + (40 \times 20) + (40 \times 100) = 120 + 800 + 4000 = 4920
  • Final Product: 615+4920=5535615 + 4920 = 5535

Explanation

This skill connects the expanded partial products method to the compact standard algorithm. Understanding this connection shows why the standard algorithm works. Each line you write in the standard algorithm is a shortcut for adding a set of partial products together. This helps to build a deeper understanding of the multiplication process beyond just memorizing steps.

Section 3

Multiplying Multi-Digit Numbers

Property

To multiply multi-digit numbers, multiply the top number by each digit of the bottom number, one at a time, from right to left. These intermediate results are called partial products. The final product is the sum of the partial products.

Examples

  • To calculate 86×4286 \times 42:

$$

\begin{array}{r r r r}
& & & 8 & 6 \\
\times & & & 2 & 4 \\
\hline
&& 3 & 4& 4 \\

  • & 1 & 7 & 2 &0 \\

\hline
& 2 & 0 & 6& 4 \\
\end{array}

* To calculate $527 \times 35$:

\begin{array}{r r r r r}
& & & 5 & 2 & 7 \\
\times & & && 3 & 5 \\
\hline
&& 2 & 6 & 3& 5 \\

  • & 1 & 5 & 8 & 1& 0\\

\hline
& 1 & 8 & 4 & 4& 5 \\
\end{array}

* To calculate $1677\times 18$:

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Multi-Digit Multiplication and Division with Place Value

  1. Lesson 1

    Lesson 1: Estimating Products Using Rounding and Compatible Numbers

  2. Lesson 2

    Lesson 2: Modeling Multiplication with Area Models and Partial Products

  3. Lesson 3Current

    Lesson 3: Connecting Partial Products to the Standard Algorithm

  4. Lesson 4

    Lesson 4: Understanding Division as Finding a Missing Factor

  5. Lesson 5

    Lesson 5: Dividing Multi-Digit Numbers Using Area Models and Partial Quotients

  6. Lesson 6

    Lesson 6: Applying Division Algorithms and Interpreting Remainders