Learn on PengiOpenStax Algebra and TrigonometryChapter 3: Functions

Lesson 3.3: Rates of Change and Behavior of Graphs

In this Grade 7 math lesson from OpenStax Algebra and Trigonometry, students learn how to calculate the average rate of change of a function using the formula delta-y over delta-x, or the change in output divided by the change in input. Students also use graphs to identify where a function is increasing, decreasing, or constant, and to locate local and absolute maxima and minima. The lesson is part of Chapter 3: Functions and applies these concepts to real-world contexts like gasoline price changes over time.

Section 1

πŸ“˜ Rates of Change and Behavior of Graphs

New Concept

This lesson explores how functions change. You'll calculate the average rate of change, Ξ”yΞ”x\frac{\Delta y}{\Delta x}, to understand if a function is increasing or decreasing and use its graph to pinpoint key features like maximum and minimum values (extrema).

What’s next

Get ready to master these concepts! Next, you'll tackle worked examples, practice cards, and interactive graphs to sharpen your skills.

Section 2

Average Rate of Change

Property

A rate of change describes how an output quantity changes relative to the change in the input quantity. The units on a rate of change are β€œoutput units per input units.”
The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

Ξ”yΞ”x=f(x2)βˆ’f(x1)x2βˆ’x1\frac{\Delta y}{\Delta x} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

To calculate the average rate of change between two points, find the difference in the output values (Ξ”yΞ”y) and divide it by the difference in the input values (Ξ”xΞ”x).

Examples

  • Find the average rate of change of f(x)=x2+1xf(x) = x^2 + \frac{1}{x} on the interval [1,3][1, 3]. We compute f(1)=2f(1)=2 and f(3)=283f(3)=\frac{28}{3}. The average rate of change is 283βˆ’23βˆ’1=2232=113\frac{\frac{28}{3} - 2}{3 - 1} = \frac{\frac{22}{3}}{2} = \frac{11}{3}.
  • A plant's height is recorded as 5 cm in week 1 and 25 cm in week 5. The average growth rate is the change in height divided by the change in time: 25βˆ’55βˆ’1=204=5\frac{25 - 5}{5 - 1} = \frac{20}{4} = 5 cm per week.

Section 3

Increasing and Decreasing Functions

Property

A function ff is an increasing function on an open interval if f(b)>f(a)f(b) > f(a) for any two input values aa and bb in the given interval where b>ab > a.
A function ff is a decreasing function on an open interval if f(b)<f(a)f(b) < f(a) for any two input values aa and bb in the given interval where b>ab > a. The average rate of change for an increasing function is positive, while it is negative for a decreasing function.

Examples

  • The function f(x)=x2f(x) = x^2 is decreasing on the interval (βˆ’βˆž,0)(-\infty, 0) because the graph goes down as you move from left to zero. It is increasing on (0,∞)(0, \infty) because the graph goes up after zero.
  • The function f(x)=x3f(x) = x^3 is always increasing on its entire domain, (βˆ’βˆž,∞)(-\infty, \infty), because the graph consistently rises from left to right.

Section 4

Local Maxima and Minima

Property

A function ff has a local maximum at x=bx = b if there exists an interval (a,c)(a, c) with a<b<ca < b < c such that, for any xx in the interval (a,c)(a, c), f(x)≀f(b)f(x) \leq f(b).
Likewise, ff has a local minimum at x=bx = b if there exists an interval (a,c)(a, c) with a<b<ca < b < c such that, for any xx in the interval (a,c)(a, c), f(x)β‰₯f(b)f(x) \geq f(b).
These points are called local extrema and occur where a function changes from increasing to decreasing or vice versa.

Examples

  • The function f(x)=x2f(x) = x^2 has a local minimum value of 00 at x=0x=0. This is the bottom point of the U-shaped graph.
  • The function g(x)=βˆ’(xβˆ’3)2+5g(x) = -(x-3)^2 + 5 has a local maximum value of 55 at x=3x=3. This is the peak of the inverted U-shape.

Section 5

Absolute Maxima and Minima

Property

The absolute maximum of ff at x=cx = c is f(c)f(c) where f(c)β‰₯f(x)f(c) \geq f(x) for all xx in the domain of ff.
The absolute minimum of ff at x=dx = d is f(d)f(d) where f(d)≀f(x)f(d) \leq f(x) for all xx in the domain of ff.
Not every function has an absolute maximum or minimum value.

Examples

  • The function f(x)=x2+1f(x) = x^2 + 1 has an absolute minimum of 11 at x=0x=0. It has no absolute maximum because its graph extends upward to infinity.
  • On the restricted domain [0,10][0, 10], the function g(x)=xg(x) = x has an absolute minimum of 00 (at x=0x=0) and an absolute maximum of 1010 (at x=10x=10).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Functions

  1. Lesson 1

    Lesson 3.1: Functions and Function Notation

  2. Lesson 2

    Lesson 3.2: Domain and Range

  3. Lesson 3Current

    Lesson 3.3: Rates of Change and Behavior of Graphs

  4. Lesson 4

    Lesson 3.4: Composition of Functions

  5. Lesson 5

    Lesson 3.5: Transformation of Functions

  6. Lesson 6

    Lesson 3.6: Absolute Value Functions

  7. Lesson 7

    Lesson 3.7: Inverse Functions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Rates of Change and Behavior of Graphs

New Concept

This lesson explores how functions change. You'll calculate the average rate of change, Ξ”yΞ”x\frac{\Delta y}{\Delta x}, to understand if a function is increasing or decreasing and use its graph to pinpoint key features like maximum and minimum values (extrema).

What’s next

Get ready to master these concepts! Next, you'll tackle worked examples, practice cards, and interactive graphs to sharpen your skills.

Section 2

Average Rate of Change

Property

A rate of change describes how an output quantity changes relative to the change in the input quantity. The units on a rate of change are β€œoutput units per input units.”
The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

Ξ”yΞ”x=f(x2)βˆ’f(x1)x2βˆ’x1\frac{\Delta y}{\Delta x} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

To calculate the average rate of change between two points, find the difference in the output values (Ξ”yΞ”y) and divide it by the difference in the input values (Ξ”xΞ”x).

Examples

  • Find the average rate of change of f(x)=x2+1xf(x) = x^2 + \frac{1}{x} on the interval [1,3][1, 3]. We compute f(1)=2f(1)=2 and f(3)=283f(3)=\frac{28}{3}. The average rate of change is 283βˆ’23βˆ’1=2232=113\frac{\frac{28}{3} - 2}{3 - 1} = \frac{\frac{22}{3}}{2} = \frac{11}{3}.
  • A plant's height is recorded as 5 cm in week 1 and 25 cm in week 5. The average growth rate is the change in height divided by the change in time: 25βˆ’55βˆ’1=204=5\frac{25 - 5}{5 - 1} = \frac{20}{4} = 5 cm per week.

Section 3

Increasing and Decreasing Functions

Property

A function ff is an increasing function on an open interval if f(b)>f(a)f(b) > f(a) for any two input values aa and bb in the given interval where b>ab > a.
A function ff is a decreasing function on an open interval if f(b)<f(a)f(b) < f(a) for any two input values aa and bb in the given interval where b>ab > a. The average rate of change for an increasing function is positive, while it is negative for a decreasing function.

Examples

  • The function f(x)=x2f(x) = x^2 is decreasing on the interval (βˆ’βˆž,0)(-\infty, 0) because the graph goes down as you move from left to zero. It is increasing on (0,∞)(0, \infty) because the graph goes up after zero.
  • The function f(x)=x3f(x) = x^3 is always increasing on its entire domain, (βˆ’βˆž,∞)(-\infty, \infty), because the graph consistently rises from left to right.

Section 4

Local Maxima and Minima

Property

A function ff has a local maximum at x=bx = b if there exists an interval (a,c)(a, c) with a<b<ca < b < c such that, for any xx in the interval (a,c)(a, c), f(x)≀f(b)f(x) \leq f(b).
Likewise, ff has a local minimum at x=bx = b if there exists an interval (a,c)(a, c) with a<b<ca < b < c such that, for any xx in the interval (a,c)(a, c), f(x)β‰₯f(b)f(x) \geq f(b).
These points are called local extrema and occur where a function changes from increasing to decreasing or vice versa.

Examples

  • The function f(x)=x2f(x) = x^2 has a local minimum value of 00 at x=0x=0. This is the bottom point of the U-shaped graph.
  • The function g(x)=βˆ’(xβˆ’3)2+5g(x) = -(x-3)^2 + 5 has a local maximum value of 55 at x=3x=3. This is the peak of the inverted U-shape.

Section 5

Absolute Maxima and Minima

Property

The absolute maximum of ff at x=cx = c is f(c)f(c) where f(c)β‰₯f(x)f(c) \geq f(x) for all xx in the domain of ff.
The absolute minimum of ff at x=dx = d is f(d)f(d) where f(d)≀f(x)f(d) \leq f(x) for all xx in the domain of ff.
Not every function has an absolute maximum or minimum value.

Examples

  • The function f(x)=x2+1f(x) = x^2 + 1 has an absolute minimum of 11 at x=0x=0. It has no absolute maximum because its graph extends upward to infinity.
  • On the restricted domain [0,10][0, 10], the function g(x)=xg(x) = x has an absolute minimum of 00 (at x=0x=0) and an absolute maximum of 1010 (at x=10x=10).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Functions

  1. Lesson 1

    Lesson 3.1: Functions and Function Notation

  2. Lesson 2

    Lesson 3.2: Domain and Range

  3. Lesson 3Current

    Lesson 3.3: Rates of Change and Behavior of Graphs

  4. Lesson 4

    Lesson 3.4: Composition of Functions

  5. Lesson 5

    Lesson 3.5: Transformation of Functions

  6. Lesson 6

    Lesson 3.6: Absolute Value Functions

  7. Lesson 7

    Lesson 3.7: Inverse Functions