Learn on PengiSaxon Math, Intermediate 4Chapter 3: Lessons 21–30, Investigation 3

Lesson 24: Inverse Operations

In this Grade 4 lesson from Saxon Math Intermediate 4, students learn that addition and subtraction are inverse operations, meaning one operation undoes the other. Using related addition and subtraction facts built from the same three numbers, students practice finding missing variables in equations such as r + 36 = 54 and t − 29 = 57.

Section 1

📘 Inverse Operations

New Concept

Addition and subtraction are inverse operations. One operation undoes the other.

What’s next

Next, you'll use this concept to rewrite equations and find the missing number in addition and subtraction problems.

Section 2

Inverse Operations

Property

Addition and subtraction are inverse operations, which means one operation can undo the other. An addition or subtraction fact can be written in a family of four related equations.

Examples

  • The fact family for 8+7=158+7=15 also includes 7+8=157+8=15, 157=815-7=8, and 158=715-8=7.
  • To solve for nn in n+10=25n+10=25, you can use the inverse operation: 2510=n25-10=n.
  • If you know 30k=1230-k=12, you also know that 12+k=3012+k=30.

Explanation

Think of addition and subtraction as a team of superheroes that can reverse each other's actions! If you know one fact, like an addition problem, you can use its inverse partner, subtraction, to find a mystery number. This lets you flip equations around to make them easier to solve, like rearranging puzzle pieces to see the whole picture.

Section 3

Finding a Missing Addend

Property

To find a missing addend in an addition equation, you subtract the known addend from the sum. If a+b=ca + b = c, then ca=bc - a = b.

Examples

  • To solve for mm in 23+m=4223 + m = 42, use subtraction: m=4223m = 42 - 23, so m=19m=19.
  • Find the value of qq in q+17=45q + 17 = 45. The inverse is q=4517q = 45 - 17, which means q=28q = 28.

Explanation

When a number is hiding in an addition problem, subtraction is your detective! To find the missing piece, just take the total (the sum) and subtract the part you already know. The answer you get is the secret number you were looking for. It's the inverse operation coming to the rescue, showing you exactly how to find the missing value.

Section 4

Finding the Starting Number

Property

To find the starting number in a subtraction problem (the minuend), you add the other two numbers together. If tb=ct - b = c, then b+c=tb + c = t.

Examples

  • To solve for tt in t29=57t - 29 = 57, you can use addition: t=57+29t = 57 + 29, so t=86t=86.
  • Find the value of nn in n26=68n - 26 = 68. You can find it by adding: n=68+26n = 68 + 26, which means n=94n = 94.

Explanation

If you don't know what number you started with in a subtraction problem, don't worry! Just take the amount that was subtracted and add it to the final result. Those two parts will combine to rebuild your original, bigger number. It's like putting two puzzle pieces back together to see the full picture you started with.

Book overview

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Chapter 3: Lessons 21–30, Investigation 3

  1. Lesson 1

    Lesson 21: Triangles, Rectangles, Squares, and Circles, Activity Drawing a Circle

  2. Lesson 2

    Lesson 22: Naming Fractions, Adding Dollars and Cents, Activity Counting Money

  3. Lesson 3

    Lesson 23: Lines, Segments, Rays, and Angles, Activity Real-World Segments and Angles

  4. Lesson 4Current

    Lesson 24: Inverse Operations

  5. Lesson 5

    Lesson 25: Subtraction Word Problems

  6. Lesson 6

    Lesson 26: Drawing Pictures of Fractions

  7. Lesson 7

    Lesson 27: Multiplication as Repeated Addition, More Elapsed Time Problems, Activity Finding Time

  8. Lesson 8

    Lesson 28: Multiplication Table

  9. Lesson 9

    Lesson 29: Multiplication Facts: 0s, 1s, 2s, 5s

  10. Lesson 10

    Lesson 30: Subtracting Three-Digit Numbers with Regrouping, Activity Subtracting Money

  11. Lesson 11

    Investigation 3: Multiplication Patterns, Area, Squares and Square Roots, Activity 1 Finding Perimeter and Area, Activity 2 Estimating Perimeter and Area

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Inverse Operations

New Concept

Addition and subtraction are inverse operations. One operation undoes the other.

What’s next

Next, you'll use this concept to rewrite equations and find the missing number in addition and subtraction problems.

Section 2

Inverse Operations

Property

Addition and subtraction are inverse operations, which means one operation can undo the other. An addition or subtraction fact can be written in a family of four related equations.

Examples

  • The fact family for 8+7=158+7=15 also includes 7+8=157+8=15, 157=815-7=8, and 158=715-8=7.
  • To solve for nn in n+10=25n+10=25, you can use the inverse operation: 2510=n25-10=n.
  • If you know 30k=1230-k=12, you also know that 12+k=3012+k=30.

Explanation

Think of addition and subtraction as a team of superheroes that can reverse each other's actions! If you know one fact, like an addition problem, you can use its inverse partner, subtraction, to find a mystery number. This lets you flip equations around to make them easier to solve, like rearranging puzzle pieces to see the whole picture.

Section 3

Finding a Missing Addend

Property

To find a missing addend in an addition equation, you subtract the known addend from the sum. If a+b=ca + b = c, then ca=bc - a = b.

Examples

  • To solve for mm in 23+m=4223 + m = 42, use subtraction: m=4223m = 42 - 23, so m=19m=19.
  • Find the value of qq in q+17=45q + 17 = 45. The inverse is q=4517q = 45 - 17, which means q=28q = 28.

Explanation

When a number is hiding in an addition problem, subtraction is your detective! To find the missing piece, just take the total (the sum) and subtract the part you already know. The answer you get is the secret number you were looking for. It's the inverse operation coming to the rescue, showing you exactly how to find the missing value.

Section 4

Finding the Starting Number

Property

To find the starting number in a subtraction problem (the minuend), you add the other two numbers together. If tb=ct - b = c, then b+c=tb + c = t.

Examples

  • To solve for tt in t29=57t - 29 = 57, you can use addition: t=57+29t = 57 + 29, so t=86t=86.
  • Find the value of nn in n26=68n - 26 = 68. You can find it by adding: n=68+26n = 68 + 26, which means n=94n = 94.

Explanation

If you don't know what number you started with in a subtraction problem, don't worry! Just take the amount that was subtracted and add it to the final result. Those two parts will combine to rebuild your original, bigger number. It's like putting two puzzle pieces back together to see the full picture you started with.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Lessons 21–30, Investigation 3

  1. Lesson 1

    Lesson 21: Triangles, Rectangles, Squares, and Circles, Activity Drawing a Circle

  2. Lesson 2

    Lesson 22: Naming Fractions, Adding Dollars and Cents, Activity Counting Money

  3. Lesson 3

    Lesson 23: Lines, Segments, Rays, and Angles, Activity Real-World Segments and Angles

  4. Lesson 4Current

    Lesson 24: Inverse Operations

  5. Lesson 5

    Lesson 25: Subtraction Word Problems

  6. Lesson 6

    Lesson 26: Drawing Pictures of Fractions

  7. Lesson 7

    Lesson 27: Multiplication as Repeated Addition, More Elapsed Time Problems, Activity Finding Time

  8. Lesson 8

    Lesson 28: Multiplication Table

  9. Lesson 9

    Lesson 29: Multiplication Facts: 0s, 1s, 2s, 5s

  10. Lesson 10

    Lesson 30: Subtracting Three-Digit Numbers with Regrouping, Activity Subtracting Money

  11. Lesson 11

    Investigation 3: Multiplication Patterns, Area, Squares and Square Roots, Activity 1 Finding Perimeter and Area, Activity 2 Estimating Perimeter and Area