Learn on PengiBig Ideas Math, Course 3Chapter 8: Volume and Similar Solids

Lesson 2: Volumes of Cones

In this Grade 8 lesson from Big Ideas Math Course 3, students learn how to calculate the volume of a cone using the formula V = ⅓Bh, discovering that a cone holds exactly one-third the volume of a cylinder with the same base and height. Students apply the formula to find both the volume and the height of right and oblique cones, including real-life problem solving. The lesson aligns with Common Core standard 8.G.9 and builds on prior knowledge of cylinder and pyramid volume formulas.

Section 1

Volume of a Cone Using Base Area

Property

The volume VV of a cone is one-third the product of its base area BB and its perpendicular height hh.

V=13BhV = \frac{1}{3}Bh

Section 2

Volume of a Cone

Property

A cone is a three-dimensional shape with a circular base and an apex. The volume of a right circular cone is one-third the product of the area of the base and the height. If the height is hh and the radius of the base is rr, then V=13πr2hV = \frac{1}{3} \pi r^2 h.

Examples

  • A party hat is a cone with a height of 8 inches and a base radius of 3 inches. Its volume is V=13π(32)(8)=24πV = \frac{1}{3} \pi (3^2)(8) = 24\pi cubic inches.
  • A cylinder has a volume of 9090 cubic cm. A cone with the same base and height would have a volume of V=13(90)=30V = \frac{1}{3} (90) = 30 cubic cm.
  • An hourglass cone holds 15π15\pi cubic inches of sand and has a base radius of 3 inches. Its height is found by solving 15π=13π(32)h15\pi = \frac{1}{3} \pi (3^2)h, which gives h=5h=5 inches.

Explanation

A cone's volume is directly related to a cylinder's. For a cone and cylinder with the same base radius and height, the cone's volume is exactly one-third of the cylinder's. You could fit three full cones of water into one cylinder.

Book overview

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Chapter 8: Volume and Similar Solids

  1. Lesson 1

    Lesson 1: Volumes of Cylinders

  2. Lesson 2Current

    Lesson 2: Volumes of Cones

  3. Lesson 3

    Lesson 3: Volumes of Spheres

  4. Lesson 4

    Lesson 4: Surface Areas and Volumes of Similar Solids

Lesson overview

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Section 1

Volume of a Cone Using Base Area

Property

The volume VV of a cone is one-third the product of its base area BB and its perpendicular height hh.

V=13BhV = \frac{1}{3}Bh

Section 2

Volume of a Cone

Property

A cone is a three-dimensional shape with a circular base and an apex. The volume of a right circular cone is one-third the product of the area of the base and the height. If the height is hh and the radius of the base is rr, then V=13πr2hV = \frac{1}{3} \pi r^2 h.

Examples

  • A party hat is a cone with a height of 8 inches and a base radius of 3 inches. Its volume is V=13π(32)(8)=24πV = \frac{1}{3} \pi (3^2)(8) = 24\pi cubic inches.
  • A cylinder has a volume of 9090 cubic cm. A cone with the same base and height would have a volume of V=13(90)=30V = \frac{1}{3} (90) = 30 cubic cm.
  • An hourglass cone holds 15π15\pi cubic inches of sand and has a base radius of 3 inches. Its height is found by solving 15π=13π(32)h15\pi = \frac{1}{3} \pi (3^2)h, which gives h=5h=5 inches.

Explanation

A cone's volume is directly related to a cylinder's. For a cone and cylinder with the same base radius and height, the cone's volume is exactly one-third of the cylinder's. You could fit three full cones of water into one cylinder.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Volume and Similar Solids

  1. Lesson 1

    Lesson 1: Volumes of Cylinders

  2. Lesson 2Current

    Lesson 2: Volumes of Cones

  3. Lesson 3

    Lesson 3: Volumes of Spheres

  4. Lesson 4

    Lesson 4: Surface Areas and Volumes of Similar Solids