Learn on PengiThe Art of Problem Solving: Prealgebra (AMC 8)Chapter 9: Square Roots

Lesson 2: Square Roots of Non-square Integers

In this Grade 4 lesson from The Art of Problem Solving: Prealgebra (AMC 8), students explore square roots of non-perfect-square integers and learn why numbers like the square root of 2 are classified as irrational numbers. Students practice approximating irrational square roots to the nearest tenth by repeatedly squaring decimal values and using the rule that larger numbers have larger square roots. The lesson also covers locating square roots between consecutive integers and counting integers within a given square root range.

Section 1

Irrational number

Property

An irrational number is a number that cannot be written as the ratio of two integers. Its decimal form does not stop and does not repeat.
Famous examples include π\pi and the square roots of numbers that are not perfect squares.

Examples

  • The number π\pi is a famous irrational number, beginning with 3.14159...3.14159... and continuing infinitely without repetition.
  • The square root of 3, 3\sqrt{3}, is irrational because 3 is not a perfect square. Its decimal form is 1.7320508...1.7320508....
  • A decimal that continues without a pattern, such as 67.121231234...67.121231234..., is an irrational number.

Explanation

Irrational numbers cannot be written as a simple fraction. Their decimal representations are infinite and non-repeating, meaning they go on forever without any predictable pattern. Think of them as the 'wild' numbers on the number line.

Section 2

Estimate Square Roots

Property

To estimate a square root between two consecutive whole numbers, first locate the number between two consecutive perfect squares.
Its square root will then lie between the square roots of those perfect squares.

Examples

  • To estimate 20\sqrt{20}, we know that 16 and 25 are the closest perfect squares. Since 16<20<2516 < 20 < 25, we can say that 4<20<54 < \sqrt{20} < 5.
  • To estimate 90\sqrt{90}, we look for perfect squares near 90. Since 81<90<10081 < 90 < 100, the estimate is 9<90<109 < \sqrt{90} < 10.
  • To estimate 150\sqrt{150}, we see that 144<150<169144 < 150 < 169. Therefore, we know that 12<150<1312 < \sqrt{150} < 13.

Explanation

This method works because as numbers get bigger, their square roots also get bigger. By finding the two perfect square neighbors for your number, you can trap its square root between two whole numbers, giving you a great estimate.

Book overview

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Chapter 9: Square Roots

  1. Lesson 1

    Lesson 1: From Squares to Square Roots

  2. Lesson 2Current

    Lesson 2: Square Roots of Non-square Integers

  3. Lesson 3

    Lesson 3: Arithmetic with Square Roots

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Irrational number

Property

An irrational number is a number that cannot be written as the ratio of two integers. Its decimal form does not stop and does not repeat.
Famous examples include π\pi and the square roots of numbers that are not perfect squares.

Examples

  • The number π\pi is a famous irrational number, beginning with 3.14159...3.14159... and continuing infinitely without repetition.
  • The square root of 3, 3\sqrt{3}, is irrational because 3 is not a perfect square. Its decimal form is 1.7320508...1.7320508....
  • A decimal that continues without a pattern, such as 67.121231234...67.121231234..., is an irrational number.

Explanation

Irrational numbers cannot be written as a simple fraction. Their decimal representations are infinite and non-repeating, meaning they go on forever without any predictable pattern. Think of them as the 'wild' numbers on the number line.

Section 2

Estimate Square Roots

Property

To estimate a square root between two consecutive whole numbers, first locate the number between two consecutive perfect squares.
Its square root will then lie between the square roots of those perfect squares.

Examples

  • To estimate 20\sqrt{20}, we know that 16 and 25 are the closest perfect squares. Since 16<20<2516 < 20 < 25, we can say that 4<20<54 < \sqrt{20} < 5.
  • To estimate 90\sqrt{90}, we look for perfect squares near 90. Since 81<90<10081 < 90 < 100, the estimate is 9<90<109 < \sqrt{90} < 10.
  • To estimate 150\sqrt{150}, we see that 144<150<169144 < 150 < 169. Therefore, we know that 12<150<1312 < \sqrt{150} < 13.

Explanation

This method works because as numbers get bigger, their square roots also get bigger. By finding the two perfect square neighbors for your number, you can trap its square root between two whole numbers, giving you a great estimate.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Square Roots

  1. Lesson 1

    Lesson 1: From Squares to Square Roots

  2. Lesson 2Current

    Lesson 2: Square Roots of Non-square Integers

  3. Lesson 3

    Lesson 3: Arithmetic with Square Roots