Learn on PengiYoshiwara Elementary AlgebraChapter 6: Quadratic Equations

Lesson 2: Some Quadratic Models

In this Grade 6 lesson from Yoshiwara Elementary Algebra (Chapter 6), students explore real-world applications of quadratic equations, including revenue models where revenue equals price per item multiplied by number of items sold. Students practice writing quadratic equations such as R = p(40 βˆ’ p), graphing parabolas to identify maximum values, and interpreting solutions in context. The lesson also introduces the Zero-Factor Principle, which states that if the product of two factors equals zero, then at least one factor must equal zero.

Section 1

πŸ“˜ Solving Quadratic Equations by Factoring

New Concept

We'll learn a powerful new method to solve quadratic equations. By rewriting the equation to equal zero and then factoring, we can use the Zero-Factor Principle to find the solutions. This breaks a tough problem into simple steps.

What’s next

Get ready to see this in action. We'll start with real-world revenue models, then master factoring and solving step-by-step with interactive practice cards.

Section 2

Revenue

Property

Revenue is the amount of money a company takes in from selling a product. To find the total revenue from the sale of a product, we multiply the price of one item by the number of items sold.

Revenue = (price per item) Β· (number of items sold)

Examples

  • A bake sale sells cookies for pp dollars each. They find that they sell 50βˆ’2p50 - 2p cookies. The revenue is R=p(50βˆ’2p)=50pβˆ’2p2R = p(50 - 2p) = 50p - 2p^2.

Section 3

The zero-factor principle

Property

If the product of two numbers is zero, then one (or both) of the numbers must be zero. Using symbols,

If AB=0AB = 0, then either A=0A = 0 or B=0B = 0.

Examples

  • To solve (xβˆ’7)(x+3)=0(x - 7)(x + 3) = 0, set each factor to zero. xβˆ’7=0x - 7 = 0 gives x=7x = 7, and x+3=0x + 3 = 0 gives x=βˆ’3x = -3.

Section 4

Factoring out a common factor

Property

Factoring is the reverse of multiplying factors together. To factor an expression with a common factor, find the largest factor that divides into each term and use the distributive law in reverse. A common factor is an expression that is a factor of each term of another expression.

Examples

  • To factor 10x2βˆ’15x10x^2 - 15x, the largest common factor is 5x5x. Dividing each term by 5x5x gives 2x2x and βˆ’3-3. The factored form is 5x(2xβˆ’3)5x(2x - 3).
  • In the expression 18y2+24y18y^2 + 24y, the largest common factor is 6y6y. Factoring this out gives 6y(3y+4)6y(3y + 4).

Section 5

Solving quadratic equations by factoring

Property

To Solve a Quadratic Equation by Factoring:

  1. Write the equation with zero isolated on the right side.
  1. Factor the left side of the equation.

Section 6

Do not divide by a variable

Property

We should never divide both sides of an equation by the variable, because we risk losing one of the solutions. This mistake happens when the variable you are dividing by could be equal to zero.

Examples

  • To solve x2=7xx^2 = 7x, dividing by xx incorrectly gives x=7x=7. The correct method is x2βˆ’7x=0x^2 - 7x = 0, so x(xβˆ’7)=0x(x-7)=0, which gives both solutions: x=0x=0 and x=7x=7.
  • In the equation 4a2=βˆ’8a4a^2 = -8a, if you divide by 4a4a, you get a=βˆ’2a = -2 and lose the a=0a=0 solution. Factoring gives 4a(a+2)=04a(a+2)=0, so a=0a=0 or a=βˆ’2a=-2.

Book overview

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Continue this chapter

Chapter 6: Quadratic Equations

  1. Lesson 1

    Lesson 1: Extracting Roots

  2. Lesson 2Current

    Lesson 2: Some Quadratic Models

  3. Lesson 3

    Lesson 3: Solving Quadratic Equations by Factoring

  4. Lesson 4

    Lesson 4: Graphing Quadratic Equations

  5. Lesson 5

    Lesson 5: The Quadratic Formula

  6. Lesson 6

    Lesson 6: Chapter Summary and Review

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Solving Quadratic Equations by Factoring

New Concept

We'll learn a powerful new method to solve quadratic equations. By rewriting the equation to equal zero and then factoring, we can use the Zero-Factor Principle to find the solutions. This breaks a tough problem into simple steps.

What’s next

Get ready to see this in action. We'll start with real-world revenue models, then master factoring and solving step-by-step with interactive practice cards.

Section 2

Revenue

Property

Revenue is the amount of money a company takes in from selling a product. To find the total revenue from the sale of a product, we multiply the price of one item by the number of items sold.

Revenue = (price per item) Β· (number of items sold)

Examples

  • A bake sale sells cookies for pp dollars each. They find that they sell 50βˆ’2p50 - 2p cookies. The revenue is R=p(50βˆ’2p)=50pβˆ’2p2R = p(50 - 2p) = 50p - 2p^2.

Section 3

The zero-factor principle

Property

If the product of two numbers is zero, then one (or both) of the numbers must be zero. Using symbols,

If AB=0AB = 0, then either A=0A = 0 or B=0B = 0.

Examples

  • To solve (xβˆ’7)(x+3)=0(x - 7)(x + 3) = 0, set each factor to zero. xβˆ’7=0x - 7 = 0 gives x=7x = 7, and x+3=0x + 3 = 0 gives x=βˆ’3x = -3.

Section 4

Factoring out a common factor

Property

Factoring is the reverse of multiplying factors together. To factor an expression with a common factor, find the largest factor that divides into each term and use the distributive law in reverse. A common factor is an expression that is a factor of each term of another expression.

Examples

  • To factor 10x2βˆ’15x10x^2 - 15x, the largest common factor is 5x5x. Dividing each term by 5x5x gives 2x2x and βˆ’3-3. The factored form is 5x(2xβˆ’3)5x(2x - 3).
  • In the expression 18y2+24y18y^2 + 24y, the largest common factor is 6y6y. Factoring this out gives 6y(3y+4)6y(3y + 4).

Section 5

Solving quadratic equations by factoring

Property

To Solve a Quadratic Equation by Factoring:

  1. Write the equation with zero isolated on the right side.
  1. Factor the left side of the equation.

Section 6

Do not divide by a variable

Property

We should never divide both sides of an equation by the variable, because we risk losing one of the solutions. This mistake happens when the variable you are dividing by could be equal to zero.

Examples

  • To solve x2=7xx^2 = 7x, dividing by xx incorrectly gives x=7x=7. The correct method is x2βˆ’7x=0x^2 - 7x = 0, so x(xβˆ’7)=0x(x-7)=0, which gives both solutions: x=0x=0 and x=7x=7.
  • In the equation 4a2=βˆ’8a4a^2 = -8a, if you divide by 4a4a, you get a=βˆ’2a = -2 and lose the a=0a=0 solution. Factoring gives 4a(a+2)=04a(a+2)=0, so a=0a=0 or a=βˆ’2a=-2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Quadratic Equations

  1. Lesson 1

    Lesson 1: Extracting Roots

  2. Lesson 2Current

    Lesson 2: Some Quadratic Models

  3. Lesson 3

    Lesson 3: Solving Quadratic Equations by Factoring

  4. Lesson 4

    Lesson 4: Graphing Quadratic Equations

  5. Lesson 5

    Lesson 5: The Quadratic Formula

  6. Lesson 6

    Lesson 6: Chapter Summary and Review