Learn on PengiBig Ideas Math, Algebra 1Chapter 9: Solving Quadratic Equations

Lesson 2: Solving Quadratic Equations by Graphing

Property.

Section 1

Finding X-Intercepts of a Parabola

Property

To find the x-intercepts of a parabola with equation y=ax2+bx+cy = ax^2 + bx + c:

  • Set y=0y = 0 and solve the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0.
  • The number of x-intercepts is determined by the discriminant b24acb^2 - 4ac:
  • If b24ac>0b^2 - 4ac > 0: two x-intercepts
  • If b24ac=0b^2 - 4ac = 0: one x-intercept - If b24ac<0b^2 - 4ac < 0: no x-intercepts

Examples

Section 2

x-intercepts of a parabola

Property

To find the xx-intercepts of the graph of

y=ax2+bx+cy = ax^2 + bx + c

we set y=0y = 0 and solve the equation

Section 3

Zeros of Quadratic Functions and X-Intercepts

Property

Zero of a Quadratic Function

For any quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c, if f(x)=0f(x) = 0, then xx is a zero of the function.
When we find the values of xx for which f(x)=0f(x) = 0, we are finding the zeros of the quadratic function. When f(x)=0f(x) = 0, the point (x,0)(x, 0) is a point on the parabola, which is an xx-intercept.

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Chapter 9: Solving Quadratic Equations

  1. Lesson 1

    Lesson 1: Properties of Radicals

  2. Lesson 2Current

    Lesson 2: Solving Quadratic Equations by Graphing

  3. Lesson 3

    Lesson 3: Solving Quadratic Equations Using Square Roots

  4. Lesson 4

    Lesson 4: Solving Quadratic Equations by Completing the Square

  5. Lesson 5

    Lesson 5: Solving Quadratic Equations Using the Quadratic Formula

  6. Lesson 6

    Lesson 6: Solving Nonlinear Systems of Equations

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Finding X-Intercepts of a Parabola

Property

To find the x-intercepts of a parabola with equation y=ax2+bx+cy = ax^2 + bx + c:

  • Set y=0y = 0 and solve the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0.
  • The number of x-intercepts is determined by the discriminant b24acb^2 - 4ac:
  • If b24ac>0b^2 - 4ac > 0: two x-intercepts
  • If b24ac=0b^2 - 4ac = 0: one x-intercept - If b24ac<0b^2 - 4ac < 0: no x-intercepts

Examples

Section 2

x-intercepts of a parabola

Property

To find the xx-intercepts of the graph of

y=ax2+bx+cy = ax^2 + bx + c

we set y=0y = 0 and solve the equation

Section 3

Zeros of Quadratic Functions and X-Intercepts

Property

Zero of a Quadratic Function

For any quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c, if f(x)=0f(x) = 0, then xx is a zero of the function.
When we find the values of xx for which f(x)=0f(x) = 0, we are finding the zeros of the quadratic function. When f(x)=0f(x) = 0, the point (x,0)(x, 0) is a point on the parabola, which is an xx-intercept.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Solving Quadratic Equations

  1. Lesson 1

    Lesson 1: Properties of Radicals

  2. Lesson 2Current

    Lesson 2: Solving Quadratic Equations by Graphing

  3. Lesson 3

    Lesson 3: Solving Quadratic Equations Using Square Roots

  4. Lesson 4

    Lesson 4: Solving Quadratic Equations by Completing the Square

  5. Lesson 5

    Lesson 5: Solving Quadratic Equations Using the Quadratic Formula

  6. Lesson 6

    Lesson 6: Solving Nonlinear Systems of Equations