Learn on PengienVision, Mathematics, Grade 4Chapter 6: Use Operations with Whole Numbers to Solve Problems

Lesson 2: Continue to Solve Comparison Problems

In this Grade 4 enVision Mathematics lesson from Chapter 6, students learn how to use multiplication and division as inverse operations to solve multiplicative comparison problems. They practice writing and solving equations such as 192 = 4 × m and m = 192 ÷ 4 to find an unknown quantity when one value is described as a multiple of another. The lesson builds skills in modeling with math using bar diagrams and comparison sentences to represent real-world situations.

Section 1

Relating Division to Finding a Missing Factor

Property

Solving a division problem, such as A÷B=?A \div B = ?, is the same as finding the unknown factor in the related multiplication equation, B×?=AB \times ? = A.
The quotient of the division is the unknown factor.

Examples

Section 2

Inverse Operations: Multiplication and Division

Property

Multiplication and division are inverse operations, which means they "undo" each other. For any number xx and any non-zero number aa:

xa÷a=xx \cdot a \div a = x
x÷aa=xx \div a \cdot a = x

Examples

Section 3

Solving Comparison Problems Using Division

Property

To find an unknown smaller quantity in a comparison problem, divide the larger quantity by the comparison factor.

Smaller Quantity=Larger Quantity÷Factor \text{Smaller Quantity} = {\text{Larger Quantity}}\div{\text{Factor}}

Examples

  • A book costs 18 dollars, which is 3 times as much as a magazine. To find the cost of the magazine, you calculate: 18÷3=618 \div 3 = 6. The magazine costs 6 dollars.
  • A bus traveled 120 miles. This is 4 times the distance a car traveled. To find the distance the car traveled, you calculate: 120÷4=30120 \div 4 = 30. The car traveled 30 miles.

Explanation

This skill applies the inverse relationship between multiplication and division to solve real-world problems. When a problem states that one amount is a certain number of times larger than another, it describes a multiplicative comparison. If you know the larger amount and the factor, you can use division to find the original, smaller amount. This is like working backward from a multiplication equation to find a missing factor.

Book overview

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Continue this chapter

Chapter 6: Use Operations with Whole Numbers to Solve Problems

  1. Lesson 1

    Lesson 1: Solve Comparison Problems

  2. Lesson 2Current

    Lesson 2: Continue to Solve Comparison Problems

  3. Lesson 3

    Lesson 3: Model Multi-Step Problems

  4. Lesson 4

    Lesson 4: More Model Multi-Step Problems

  5. Lesson 5

    Lesson 5: Solve Multi-Step Problems

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Relating Division to Finding a Missing Factor

Property

Solving a division problem, such as A÷B=?A \div B = ?, is the same as finding the unknown factor in the related multiplication equation, B×?=AB \times ? = A.
The quotient of the division is the unknown factor.

Examples

Section 2

Inverse Operations: Multiplication and Division

Property

Multiplication and division are inverse operations, which means they "undo" each other. For any number xx and any non-zero number aa:

xa÷a=xx \cdot a \div a = x
x÷aa=xx \div a \cdot a = x

Examples

Section 3

Solving Comparison Problems Using Division

Property

To find an unknown smaller quantity in a comparison problem, divide the larger quantity by the comparison factor.

Smaller Quantity=Larger Quantity÷Factor \text{Smaller Quantity} = {\text{Larger Quantity}}\div{\text{Factor}}

Examples

  • A book costs 18 dollars, which is 3 times as much as a magazine. To find the cost of the magazine, you calculate: 18÷3=618 \div 3 = 6. The magazine costs 6 dollars.
  • A bus traveled 120 miles. This is 4 times the distance a car traveled. To find the distance the car traveled, you calculate: 120÷4=30120 \div 4 = 30. The car traveled 30 miles.

Explanation

This skill applies the inverse relationship between multiplication and division to solve real-world problems. When a problem states that one amount is a certain number of times larger than another, it describes a multiplicative comparison. If you know the larger amount and the factor, you can use division to find the original, smaller amount. This is like working backward from a multiplication equation to find a missing factor.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Use Operations with Whole Numbers to Solve Problems

  1. Lesson 1

    Lesson 1: Solve Comparison Problems

  2. Lesson 2Current

    Lesson 2: Continue to Solve Comparison Problems

  3. Lesson 3

    Lesson 3: Model Multi-Step Problems

  4. Lesson 4

    Lesson 4: More Model Multi-Step Problems

  5. Lesson 5

    Lesson 5: Solve Multi-Step Problems