Learn on PengiOpenstax Prealgebre 2EChapter 3: Integers

Lesson 2: Add Integers

In this lesson from OpenStax Prealgebra 2E, students learn how to add integers, including both positive and negative numbers, using two-color counter models and number line strategies. The lesson builds skills in simplifying expressions with integers, evaluating variable expressions, and translating word phrases into algebraic expressions. Real-world applications such as temperature, elevation, and banking help reinforce the concept of integer addition in context.

Section 1

πŸ“˜ Add Integers

New Concept

This lesson introduces adding positive and negative numbers. You'll learn the rules for adding integers with the same or different signs, then apply these skills to simplify expressions, evaluate variables, and solve real-world problems.

What’s next

First, you’ll see how to model integer addition using visual examples. Then, you'll jump into practice cards to master simplifying and evaluating expressions.

Section 2

Model addition of integers

Property

We will model addition of negatives with two color counters. We let a blue counter represent a positive and a red counter will represent a negative. If we have one positive and one negative counter, the value of the pair is zero. They form a neutral pair.

Examples

  • To model 2+(βˆ’5)2 + (-5), start with 2 blue counters and add 5 red counters. Form two neutral pairs. You are left with 3 red counters, so the answer is βˆ’3-3.
  • To model βˆ’4+(βˆ’2)-4 + (-2), start with 4 red counters and add 2 more red counters. Since there are no blue counters to cancel them out, you have a total of 6 red counters. The answer is βˆ’6-6.

Section 3

Simplify expressions with integers

Property

When the signs are the same, the counters would be all the same color, so add them. When the signs are different, some counters would make neutral pairs; subtract to see how many are left.

Examples

  • To simplify 25+(βˆ’40)25 + (-40), the signs are different. Subtract 40βˆ’25=1540 - 25 = 15. Since βˆ’40-40 has a greater absolute value, the result is negative. So, 25+(βˆ’40)=βˆ’1525 + (-40) = -15.
  • To simplify βˆ’18+(βˆ’20)-18 + (-20), the signs are the same. Add 18+20=3818 + 20 = 38. Since both numbers are negative, the result is also negative. So, βˆ’18+(βˆ’20)=βˆ’38-18 + (-20) = -38.

Section 4

Evaluate variable expressions with integers

Property

To evaluate an expression means to substitute a number for the variable in the expression. Now we can use negative numbers as well as positive numbers when evaluating expressions.

Examples

  • Evaluate a+9a + 9 when a=βˆ’12a = -12. Substitute βˆ’12-12 for aa to get βˆ’12+9-12 + 9. The result is βˆ’3-3.
  • Evaluate βˆ’x+4-x + 4 when x=βˆ’6x = -6. Substitute βˆ’6-6 for xx to get βˆ’(βˆ’6)+4-(-6) + 4. This simplifies to 6+46 + 4, which equals 1010.

Section 5

Translate word phrases to algebraic expressions

Property

All our earlier work translating word phrases to algebra also applies to expressions that include both positive and negative numbers. Remember that the phrase the sum indicates addition. The phrase increased by also indicates addition.

Examples

  • Translate and simplify "the sum of βˆ’12-12 and 77". The phrase "the sum of" indicates addition. The expression is βˆ’12+7-12 + 7, which simplifies to βˆ’5-5.
  • Translate and simplify "99 more than βˆ’3-3". The phrase "more than" means to add. The expression is βˆ’3+9-3 + 9, which simplifies to 66.

Section 6

Add integers in applications

Property

Solving applications is easy if we have a plan. First, we determine what we are looking for. Then we write a phrase that gives the information to find it. We translate the phrase into math notation and then simplify to get the answer. Finally, we write a sentence to answer the question.

Examples

  • The temperature was βˆ’8-8 degrees Fahrenheit at sunrise. By noon, it had warmed up 1515 degrees. The temperature at noon was βˆ’8+15=7-8 + 15 = 7 degrees Fahrenheit.
  • A football team lost 55 yards on one play and then gained 1111 yards on the next. The total change in position is found by calculating βˆ’5+11=6-5 + 11 = 6 yards.

Book overview

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Continue this chapter

Chapter 3: Integers

  1. Lesson 1

    Lesson 1: Introduction to Integers

  2. Lesson 2Current

    Lesson 2: Add Integers

  3. Lesson 3

    Lesson 3: Subtract Integers

  4. Lesson 4

    Lesson 4: Multiply and Divide Integers

  5. Lesson 5

    Lesson 5: Solve Equations Using Integers; The Division Property of Equality

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Add Integers

New Concept

This lesson introduces adding positive and negative numbers. You'll learn the rules for adding integers with the same or different signs, then apply these skills to simplify expressions, evaluate variables, and solve real-world problems.

What’s next

First, you’ll see how to model integer addition using visual examples. Then, you'll jump into practice cards to master simplifying and evaluating expressions.

Section 2

Model addition of integers

Property

We will model addition of negatives with two color counters. We let a blue counter represent a positive and a red counter will represent a negative. If we have one positive and one negative counter, the value of the pair is zero. They form a neutral pair.

Examples

  • To model 2+(βˆ’5)2 + (-5), start with 2 blue counters and add 5 red counters. Form two neutral pairs. You are left with 3 red counters, so the answer is βˆ’3-3.
  • To model βˆ’4+(βˆ’2)-4 + (-2), start with 4 red counters and add 2 more red counters. Since there are no blue counters to cancel them out, you have a total of 6 red counters. The answer is βˆ’6-6.

Section 3

Simplify expressions with integers

Property

When the signs are the same, the counters would be all the same color, so add them. When the signs are different, some counters would make neutral pairs; subtract to see how many are left.

Examples

  • To simplify 25+(βˆ’40)25 + (-40), the signs are different. Subtract 40βˆ’25=1540 - 25 = 15. Since βˆ’40-40 has a greater absolute value, the result is negative. So, 25+(βˆ’40)=βˆ’1525 + (-40) = -15.
  • To simplify βˆ’18+(βˆ’20)-18 + (-20), the signs are the same. Add 18+20=3818 + 20 = 38. Since both numbers are negative, the result is also negative. So, βˆ’18+(βˆ’20)=βˆ’38-18 + (-20) = -38.

Section 4

Evaluate variable expressions with integers

Property

To evaluate an expression means to substitute a number for the variable in the expression. Now we can use negative numbers as well as positive numbers when evaluating expressions.

Examples

  • Evaluate a+9a + 9 when a=βˆ’12a = -12. Substitute βˆ’12-12 for aa to get βˆ’12+9-12 + 9. The result is βˆ’3-3.
  • Evaluate βˆ’x+4-x + 4 when x=βˆ’6x = -6. Substitute βˆ’6-6 for xx to get βˆ’(βˆ’6)+4-(-6) + 4. This simplifies to 6+46 + 4, which equals 1010.

Section 5

Translate word phrases to algebraic expressions

Property

All our earlier work translating word phrases to algebra also applies to expressions that include both positive and negative numbers. Remember that the phrase the sum indicates addition. The phrase increased by also indicates addition.

Examples

  • Translate and simplify "the sum of βˆ’12-12 and 77". The phrase "the sum of" indicates addition. The expression is βˆ’12+7-12 + 7, which simplifies to βˆ’5-5.
  • Translate and simplify "99 more than βˆ’3-3". The phrase "more than" means to add. The expression is βˆ’3+9-3 + 9, which simplifies to 66.

Section 6

Add integers in applications

Property

Solving applications is easy if we have a plan. First, we determine what we are looking for. Then we write a phrase that gives the information to find it. We translate the phrase into math notation and then simplify to get the answer. Finally, we write a sentence to answer the question.

Examples

  • The temperature was βˆ’8-8 degrees Fahrenheit at sunrise. By noon, it had warmed up 1515 degrees. The temperature at noon was βˆ’8+15=7-8 + 15 = 7 degrees Fahrenheit.
  • A football team lost 55 yards on one play and then gained 1111 yards on the next. The total change in position is found by calculating βˆ’5+11=6-5 + 11 = 6 yards.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Integers

  1. Lesson 1

    Lesson 1: Introduction to Integers

  2. Lesson 2Current

    Lesson 2: Add Integers

  3. Lesson 3

    Lesson 3: Subtract Integers

  4. Lesson 4

    Lesson 4: Multiply and Divide Integers

  5. Lesson 5

    Lesson 5: Solve Equations Using Integers; The Division Property of Equality