Learn on PengiOpenstax Elementary Algebra 2EChapter 2: Solving Linear Equations and Inequalities

Lesson 2.3: Solve Equations with Variables and Constants on Both Sides

In this lesson from OpenStax Elementary Algebra 2E, students learn to solve linear equations that have variables and constants on both sides by applying the Addition, Subtraction, Division, and Multiplication Properties of Equality. The core strategy involves choosing a "variable side" and a "constant side," then isolating the variable to reach the standard form ax = b. Students also practice translating real-world word problems into equations and solving them using these techniques.

Section 1

📘 Solve Equations with Variables and Constants on Both Sides

New Concept

Ready to level up your equation-solving skills? This lesson introduces a powerful strategy for equations with variables and constants on both sides. We'll learn how to organize any linear equation by isolating variables on one side and constants on the other.

What’s next

Next, you'll see this strategy in action with interactive examples. Then, you'll apply what you've learned on a series of practice cards to build your confidence.

Section 2

Solve with constants on both sides

Property

Our strategy will involve choosing one side of the equation to be the “variable side”, and the other side of the equation to be the “constant side.” Then, we will use the Subtraction and Addition Properties of Equality to get all the variable terms together on one side of the equation and the constant terms together on the other side. By doing this, we will transform the equation into the form ax=bax = b.

Examples

  • Solve 4x+5=154x + 5 = -15. First, subtract 5 from both sides to get 4x=204x = -20. Then, divide both sides by 4 to find x=5x = -5.
  • Solve 6y7=236y - 7 = 23. First, add 7 to both sides to get 6y=306y = 30. Then, divide both sides by 6 to find y=5y = 5.

Section 3

Solve with variables on both sides

Property

For equations with variables on both sides of the equation, begin as we did above—choose a “variable” side and a “constant” side, and then use the subtraction and addition properties of equality to collect all variables on one side and all constants on the other side.

Examples

  • Solve 10x=9x710x = 9x - 7. Subtract 9x9x from both sides to get all the variables on the left, which gives the solution x=7x = -7.
  • Solve 3y8=6y3y - 8 = 6y. Subtract 3y3y from both sides to gather the variables on the right, which gives 8=3y-8 = 3y. Divide by 3 to get y=83y = -\frac{8}{3}.

Section 4

Variables and constants on both sides

Property

When an equation has variables and constants on both sides, it may take several steps to solve. We need a clear and organized strategy. The strategy is to first collect the variable terms to one side of the equation, and then collect the constant terms to the other side.

Examples

  • Solve 8x+4=7x+98x + 4 = 7x + 9. First, subtract 7x7x from both sides to get x+4=9x + 4 = 9. Then, subtract 4 from both sides to find x=5x = 5.
  • Solve 10n5=3n+2110n - 5 = -3n + 21. First, add 3n3n to both sides to get 13n5=2113n - 5 = 21. Then, add 5 to both sides to get 13n=2613n = 26. Finally, divide by 13 to find n=2n = 2.

Section 5

General strategy for solving equations

Property

Step 1. Choose which side will be the “variable” side—the other side will be the “constant” side. A helpful approach is to make the “variable” side the side that has the variable with the larger coefficient.
Step 2. Collect the variable terms to the “variable” side of the equation, using the Addition or Subtraction Property of Equality.
Step 3. Collect all the constants to the other side of the equation.
Step 4. Make the coefficient of the variable equal 1.
Step 5. Check the solution by substituting it into the original equation.

Examples

  • Solve 9k1=12k+149k - 1 = 12k + 14. Choose the right side for variables since 12>912 > 9. This leads to 114=12k9k-1 - 14 = 12k - 9k, which simplifies to 15=3k-15 = 3k, so k=5k = -5.
  • Solve 32x+4=12x6\frac{3}{2}x + 4 = \frac{1}{2}x - 6. Choose the left side for variables since 32>12\frac{3}{2} > \frac{1}{2}. This leads to x+4=6x + 4 = -6, so x=10x = -10.

Book overview

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Chapter 2: Solving Linear Equations and Inequalities

  1. Lesson 1

    Lesson 2.1: Solve Equations Using the Subtraction and Addition Properties of Equality

  2. Lesson 2

    Lesson 2.2: Solve Equations using the Division and Multiplication Properties of Equality

  3. Lesson 3Current

    Lesson 2.3: Solve Equations with Variables and Constants on Both Sides

  4. Lesson 4

    Lesson 2.4: Use a General Strategy to Solve Linear Equations

  5. Lesson 5

    Lesson 2.5: Solve Equations with Fractions or Decimals

  6. Lesson 6

    Lesson 2.6: Solve a Formula for a Specific Variable

  7. Lesson 7

    Lesson 2.7: Solve Linear Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Solve Equations with Variables and Constants on Both Sides

New Concept

Ready to level up your equation-solving skills? This lesson introduces a powerful strategy for equations with variables and constants on both sides. We'll learn how to organize any linear equation by isolating variables on one side and constants on the other.

What’s next

Next, you'll see this strategy in action with interactive examples. Then, you'll apply what you've learned on a series of practice cards to build your confidence.

Section 2

Solve with constants on both sides

Property

Our strategy will involve choosing one side of the equation to be the “variable side”, and the other side of the equation to be the “constant side.” Then, we will use the Subtraction and Addition Properties of Equality to get all the variable terms together on one side of the equation and the constant terms together on the other side. By doing this, we will transform the equation into the form ax=bax = b.

Examples

  • Solve 4x+5=154x + 5 = -15. First, subtract 5 from both sides to get 4x=204x = -20. Then, divide both sides by 4 to find x=5x = -5.
  • Solve 6y7=236y - 7 = 23. First, add 7 to both sides to get 6y=306y = 30. Then, divide both sides by 6 to find y=5y = 5.

Section 3

Solve with variables on both sides

Property

For equations with variables on both sides of the equation, begin as we did above—choose a “variable” side and a “constant” side, and then use the subtraction and addition properties of equality to collect all variables on one side and all constants on the other side.

Examples

  • Solve 10x=9x710x = 9x - 7. Subtract 9x9x from both sides to get all the variables on the left, which gives the solution x=7x = -7.
  • Solve 3y8=6y3y - 8 = 6y. Subtract 3y3y from both sides to gather the variables on the right, which gives 8=3y-8 = 3y. Divide by 3 to get y=83y = -\frac{8}{3}.

Section 4

Variables and constants on both sides

Property

When an equation has variables and constants on both sides, it may take several steps to solve. We need a clear and organized strategy. The strategy is to first collect the variable terms to one side of the equation, and then collect the constant terms to the other side.

Examples

  • Solve 8x+4=7x+98x + 4 = 7x + 9. First, subtract 7x7x from both sides to get x+4=9x + 4 = 9. Then, subtract 4 from both sides to find x=5x = 5.
  • Solve 10n5=3n+2110n - 5 = -3n + 21. First, add 3n3n to both sides to get 13n5=2113n - 5 = 21. Then, add 5 to both sides to get 13n=2613n = 26. Finally, divide by 13 to find n=2n = 2.

Section 5

General strategy for solving equations

Property

Step 1. Choose which side will be the “variable” side—the other side will be the “constant” side. A helpful approach is to make the “variable” side the side that has the variable with the larger coefficient.
Step 2. Collect the variable terms to the “variable” side of the equation, using the Addition or Subtraction Property of Equality.
Step 3. Collect all the constants to the other side of the equation.
Step 4. Make the coefficient of the variable equal 1.
Step 5. Check the solution by substituting it into the original equation.

Examples

  • Solve 9k1=12k+149k - 1 = 12k + 14. Choose the right side for variables since 12>912 > 9. This leads to 114=12k9k-1 - 14 = 12k - 9k, which simplifies to 15=3k-15 = 3k, so k=5k = -5.
  • Solve 32x+4=12x6\frac{3}{2}x + 4 = \frac{1}{2}x - 6. Choose the left side for variables since 32>12\frac{3}{2} > \frac{1}{2}. This leads to x+4=6x + 4 = -6, so x=10x = -10.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Solving Linear Equations and Inequalities

  1. Lesson 1

    Lesson 2.1: Solve Equations Using the Subtraction and Addition Properties of Equality

  2. Lesson 2

    Lesson 2.2: Solve Equations using the Division and Multiplication Properties of Equality

  3. Lesson 3Current

    Lesson 2.3: Solve Equations with Variables and Constants on Both Sides

  4. Lesson 4

    Lesson 2.4: Use a General Strategy to Solve Linear Equations

  5. Lesson 5

    Lesson 2.5: Solve Equations with Fractions or Decimals

  6. Lesson 6

    Lesson 2.6: Solve a Formula for a Specific Variable

  7. Lesson 7

    Lesson 2.7: Solve Linear Inequalities