Learn on PengiOpenStax Algebra and TrigonometryChapter 12: Analytic Geometry

Lesson 12.4: Rotation of Axes

New Concept The $xy$ term in a conic's equation means its graph is rotated. You'll learn to find the angle of rotation, $\theta$, to transform the equation, remove the $xy$ term, and identify the conic's true shape.

Section 1

📘 Rotation of Axes

New Concept

The xyxy term in a conic's equation means its graph is rotated. You'll learn to find the angle of rotation, θ\theta, to transform the equation, remove the xyxy term, and identify the conic's true shape.

What’s next

Next, you'll dive into interactive examples using rotation formulas. You'll then apply what you've learned on practice cards and challenge problems.

Section 2

Identifying Conics in General Form

Property

A conic section has the general form Ax2+Bxy+Cy2+Dx+Ey+F=0A x^2 + B x y + C y^2 + D x + E y + F = 0 where AA, BB, and CC are not all zero. To identify the type of conic when it has not been rotated (B=0B=0):

  1. Rewrite the equation in the general form.
  2. Identify the values of AA and CC.

a. If AA and CC are nonzero, have the same sign, and are not equal to each other (AC>0,ACAC > 0, A \neq C), the graph may be an ellipse.
b. If AA and CC are equal and nonzero (A=CA = C), the graph may be a circle.
c. If AA and CC are nonzero and have opposite signs (AC<0AC < 0), the graph may be a hyperbola.
d. If either AA or CC is zero, the graph may be a parabola.

Examples

  • For the equation 5x23y2+10x12y+7=05x^2 - 3y^2 + 10x - 12y + 7 = 0, we see that A=5A=5 and C=3C=-3. Since AA and CC have opposite signs, the graph is a hyperbola.
  • For the equation 7x2+7y214x+28y50=07x^2 + 7y^2 - 14x + 28y - 50 = 0, we see that A=7A=7 and C=7C=7. Since A=CA=C, the graph is a circle.
  • For the equation 4x2+20x3y+1=04x^2 + 20x - 3y + 1 = 0, we see that A=4A=4 and C=0C=0. Since CC is zero, the graph is a parabola.

Explanation

Think of coefficients AA and CC as clues to the conic's identity. By comparing their signs and values in the general form, you can quickly determine the shape of the conic section, as long as it has not been rotated.

Section 3

Equations of Rotation

Property

If a point (x,y)(x, y) on the Cartesian plane is represented on a new coordinate plane where the axes of rotation are formed by rotating an angle θ\theta from the positive xx-axis, then the coordinates of the point with respect to the new axes are (x,y)(x', y'). We can use the following equations of rotation to define the relationship between (x,y)(x, y) and (x,y)(x', y'):

x=xcosθysinθx = x' \cos \theta - y' \sin \theta

and

y=xsinθ+ycosθy = x' \sin \theta + y' \cos \theta

Examples

  • To find the new equation for x=5x=5 after a rotation of θ=30\theta=30^\circ, we substitute x=xcos(30)ysin(30)x = x' \cos(30^\circ) - y' \sin(30^\circ). This gives x(32)y(12)=5x'(\frac{\sqrt{3}}{2}) - y'(\frac{1}{2}) = 5, or 3xy=10\sqrt{3}x' - y' = 10.
  • Find the new representation of y=xy=x after rotating by θ=45\theta = 45^\circ. Substitute x=xy2x = \frac{x' - y'}{\sqrt{2}} and y=x+y2y = \frac{x' + y'}{\sqrt{2}}. The equation becomes x+y2=xy2\frac{x' + y'}{\sqrt{2}} = \frac{x' - y'}{\sqrt{2}}, which simplifies to y=0y'=0.
  • Find the new equation for the circle x2+y2=16x^2 + y^2 = 16 after a 6060^\circ rotation. Substituting the rotation formulas for xx and yy and simplifying gives (x)2+(y)2=16(x')^2 + (y')^2 = 16. A circle centered at the origin looks the same after any rotation.

Explanation

These formulas act as a translator between the original coordinate system and a new, rotated one. By substituting these expressions for xx and yy into an equation, we can see what the equation looks like in the rotated view.

Section 4

Eliminating The xy-Term

Property

To transform the equation of a conic Ax2+Bxy+Cy2+Dx+Ey+F=0A x^2 + B x y + C y^2 + D x + E y + F = 0 into an equation in the xx' and yy' coordinate system without the xyx'y' term, we rotate the axes by a measure of θ\theta that satisfies

cot(2θ)=ACB\cot(2\theta) = \frac{A - C}{B}

If cot(2θ)>0\cot(2\theta) > 0, then 2θ2\theta is in the first quadrant, and θ\theta is between (0,45)(0^\circ, 45^\circ).
If cot(2θ)<0\cot(2\theta) < 0, then 2θ2\theta is in the second quadrant, and θ\theta is between (45,90)(45^\circ, 90^\circ).
If A=CA = C, then θ=45\theta = 45^\circ.

Examples

  • For the equation 5x28xy+11y2=155x^2 - 8xy + 11y^2 = 15, we have A=5,B=8,C=11A=5, B=-8, C=11. The angle of rotation θ\theta is found using cot(2θ)=5118=68=34\cot(2\theta) = \frac{5-11}{-8} = \frac{-6}{-8} = \frac{3}{4}.
  • For the equation 3x2+2xy+3y2=103x^2 + 2xy + 3y^2 = 10, we have A=3,B=2,C=3A=3, B=2, C=3. Since A=CA=C, the angle of rotation is θ=45\theta = 45^\circ.
  • For the equation x2+4xy2y2=9x^2 + 4xy - 2y^2 = 9, we have A=1,B=4,C=2A=1, B=4, C=-2. The angle of rotation θ\theta is found using cot(2θ)=1(2)4=34\cot(2\theta) = \frac{1 - (-2)}{4} = \frac{3}{4}.

Explanation

The xyxy term indicates a rotated conic. This formula is the key to finding the precise angle of rotation needed to align the conic with the new xx' and yy' axes, which makes the xyx'y' term disappear and simplifies the equation.

Section 5

Using The Discriminant To Identify A Conic

Property

If the equation Ax2+Bxy+Cy2+Dx+Ey+F=0A x^2 + B x y + C y^2 + D x + E y + F = 0 is transformed by rotating axes into the equation Ax2+Bxy+Cy2+Dx+Ey+F=0A' x'^2 + B' x' y' + C' y'^2 + D' x' + E' y' + F' = 0, then B24AC=B24ACB^2 - 4AC = B'^2 - 4A'C'. The equation is an ellipse, a parabola, or a hyperbola, or a degenerate case of one of these. If the discriminant, B24ACB^2 - 4AC, is

  • <0< 0, the conic section is an ellipse
  • =0= 0, the conic section is a parabola
  • >0> 0, the conic section is a hyperbola

Examples

  • For x2+3xy+5y2=10x^2 + 3xy + 5y^2 = 10, the discriminant is B24AC=(3)24(1)(5)=920=11B^2 - 4AC = (3)^2 - 4(1)(5) = 9 - 20 = -11. Since 11<0-11 < 0, the conic is an ellipse.
  • For 4x24xy+y2+2x=74x^2 - 4xy + y^2 + 2x = 7, the discriminant is B24AC=(4)24(4)(1)=1616=0B^2 - 4AC = (-4)^2 - 4(4)(1) = 16 - 16 = 0. Since the discriminant is 00, the conic is a parabola.
  • For 2x2+10xy3y2=82x^2 + 10xy - 3y^2 = 8, the discriminant is B24AC=(10)24(2)(3)=100+24=124B^2 - 4AC = (10)^2 - 4(2)(-3) = 100 + 24 = 124. Since 124>0124 > 0, the conic is a hyperbola.

Explanation

The discriminant, B24ACB^2 - 4AC, is a special value that doesn't change when a conic is rotated. This makes it a powerful shortcut to identify the conic's type without performing any rotation calculations.

Book overview

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Continue this chapter

Chapter 12: Analytic Geometry

  1. Lesson 1

    Lesson 12.1: The Ellipse

  2. Lesson 2

    Lesson 12.2: The Hyperbola

  3. Lesson 3

    Lesson 12.3: The Parabola

  4. Lesson 4Current

    Lesson 12.4: Rotation of Axes

  5. Lesson 5

    Lesson 12.5: Conic Sections in Polar Coordinates

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Rotation of Axes

New Concept

The xyxy term in a conic's equation means its graph is rotated. You'll learn to find the angle of rotation, θ\theta, to transform the equation, remove the xyxy term, and identify the conic's true shape.

What’s next

Next, you'll dive into interactive examples using rotation formulas. You'll then apply what you've learned on practice cards and challenge problems.

Section 2

Identifying Conics in General Form

Property

A conic section has the general form Ax2+Bxy+Cy2+Dx+Ey+F=0A x^2 + B x y + C y^2 + D x + E y + F = 0 where AA, BB, and CC are not all zero. To identify the type of conic when it has not been rotated (B=0B=0):

  1. Rewrite the equation in the general form.
  2. Identify the values of AA and CC.

a. If AA and CC are nonzero, have the same sign, and are not equal to each other (AC>0,ACAC > 0, A \neq C), the graph may be an ellipse.
b. If AA and CC are equal and nonzero (A=CA = C), the graph may be a circle.
c. If AA and CC are nonzero and have opposite signs (AC<0AC < 0), the graph may be a hyperbola.
d. If either AA or CC is zero, the graph may be a parabola.

Examples

  • For the equation 5x23y2+10x12y+7=05x^2 - 3y^2 + 10x - 12y + 7 = 0, we see that A=5A=5 and C=3C=-3. Since AA and CC have opposite signs, the graph is a hyperbola.
  • For the equation 7x2+7y214x+28y50=07x^2 + 7y^2 - 14x + 28y - 50 = 0, we see that A=7A=7 and C=7C=7. Since A=CA=C, the graph is a circle.
  • For the equation 4x2+20x3y+1=04x^2 + 20x - 3y + 1 = 0, we see that A=4A=4 and C=0C=0. Since CC is zero, the graph is a parabola.

Explanation

Think of coefficients AA and CC as clues to the conic's identity. By comparing their signs and values in the general form, you can quickly determine the shape of the conic section, as long as it has not been rotated.

Section 3

Equations of Rotation

Property

If a point (x,y)(x, y) on the Cartesian plane is represented on a new coordinate plane where the axes of rotation are formed by rotating an angle θ\theta from the positive xx-axis, then the coordinates of the point with respect to the new axes are (x,y)(x', y'). We can use the following equations of rotation to define the relationship between (x,y)(x, y) and (x,y)(x', y'):

x=xcosθysinθx = x' \cos \theta - y' \sin \theta

and

y=xsinθ+ycosθy = x' \sin \theta + y' \cos \theta

Examples

  • To find the new equation for x=5x=5 after a rotation of θ=30\theta=30^\circ, we substitute x=xcos(30)ysin(30)x = x' \cos(30^\circ) - y' \sin(30^\circ). This gives x(32)y(12)=5x'(\frac{\sqrt{3}}{2}) - y'(\frac{1}{2}) = 5, or 3xy=10\sqrt{3}x' - y' = 10.
  • Find the new representation of y=xy=x after rotating by θ=45\theta = 45^\circ. Substitute x=xy2x = \frac{x' - y'}{\sqrt{2}} and y=x+y2y = \frac{x' + y'}{\sqrt{2}}. The equation becomes x+y2=xy2\frac{x' + y'}{\sqrt{2}} = \frac{x' - y'}{\sqrt{2}}, which simplifies to y=0y'=0.
  • Find the new equation for the circle x2+y2=16x^2 + y^2 = 16 after a 6060^\circ rotation. Substituting the rotation formulas for xx and yy and simplifying gives (x)2+(y)2=16(x')^2 + (y')^2 = 16. A circle centered at the origin looks the same after any rotation.

Explanation

These formulas act as a translator between the original coordinate system and a new, rotated one. By substituting these expressions for xx and yy into an equation, we can see what the equation looks like in the rotated view.

Section 4

Eliminating The xy-Term

Property

To transform the equation of a conic Ax2+Bxy+Cy2+Dx+Ey+F=0A x^2 + B x y + C y^2 + D x + E y + F = 0 into an equation in the xx' and yy' coordinate system without the xyx'y' term, we rotate the axes by a measure of θ\theta that satisfies

cot(2θ)=ACB\cot(2\theta) = \frac{A - C}{B}

If cot(2θ)>0\cot(2\theta) > 0, then 2θ2\theta is in the first quadrant, and θ\theta is between (0,45)(0^\circ, 45^\circ).
If cot(2θ)<0\cot(2\theta) < 0, then 2θ2\theta is in the second quadrant, and θ\theta is between (45,90)(45^\circ, 90^\circ).
If A=CA = C, then θ=45\theta = 45^\circ.

Examples

  • For the equation 5x28xy+11y2=155x^2 - 8xy + 11y^2 = 15, we have A=5,B=8,C=11A=5, B=-8, C=11. The angle of rotation θ\theta is found using cot(2θ)=5118=68=34\cot(2\theta) = \frac{5-11}{-8} = \frac{-6}{-8} = \frac{3}{4}.
  • For the equation 3x2+2xy+3y2=103x^2 + 2xy + 3y^2 = 10, we have A=3,B=2,C=3A=3, B=2, C=3. Since A=CA=C, the angle of rotation is θ=45\theta = 45^\circ.
  • For the equation x2+4xy2y2=9x^2 + 4xy - 2y^2 = 9, we have A=1,B=4,C=2A=1, B=4, C=-2. The angle of rotation θ\theta is found using cot(2θ)=1(2)4=34\cot(2\theta) = \frac{1 - (-2)}{4} = \frac{3}{4}.

Explanation

The xyxy term indicates a rotated conic. This formula is the key to finding the precise angle of rotation needed to align the conic with the new xx' and yy' axes, which makes the xyx'y' term disappear and simplifies the equation.

Section 5

Using The Discriminant To Identify A Conic

Property

If the equation Ax2+Bxy+Cy2+Dx+Ey+F=0A x^2 + B x y + C y^2 + D x + E y + F = 0 is transformed by rotating axes into the equation Ax2+Bxy+Cy2+Dx+Ey+F=0A' x'^2 + B' x' y' + C' y'^2 + D' x' + E' y' + F' = 0, then B24AC=B24ACB^2 - 4AC = B'^2 - 4A'C'. The equation is an ellipse, a parabola, or a hyperbola, or a degenerate case of one of these. If the discriminant, B24ACB^2 - 4AC, is

  • <0< 0, the conic section is an ellipse
  • =0= 0, the conic section is a parabola
  • >0> 0, the conic section is a hyperbola

Examples

  • For x2+3xy+5y2=10x^2 + 3xy + 5y^2 = 10, the discriminant is B24AC=(3)24(1)(5)=920=11B^2 - 4AC = (3)^2 - 4(1)(5) = 9 - 20 = -11. Since 11<0-11 < 0, the conic is an ellipse.
  • For 4x24xy+y2+2x=74x^2 - 4xy + y^2 + 2x = 7, the discriminant is B24AC=(4)24(4)(1)=1616=0B^2 - 4AC = (-4)^2 - 4(4)(1) = 16 - 16 = 0. Since the discriminant is 00, the conic is a parabola.
  • For 2x2+10xy3y2=82x^2 + 10xy - 3y^2 = 8, the discriminant is B24AC=(10)24(2)(3)=100+24=124B^2 - 4AC = (10)^2 - 4(2)(-3) = 100 + 24 = 124. Since 124>0124 > 0, the conic is a hyperbola.

Explanation

The discriminant, B24ACB^2 - 4AC, is a special value that doesn't change when a conic is rotated. This makes it a powerful shortcut to identify the conic's type without performing any rotation calculations.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 12: Analytic Geometry

  1. Lesson 1

    Lesson 12.1: The Ellipse

  2. Lesson 2

    Lesson 12.2: The Hyperbola

  3. Lesson 3

    Lesson 12.3: The Parabola

  4. Lesson 4Current

    Lesson 12.4: Rotation of Axes

  5. Lesson 5

    Lesson 12.5: Conic Sections in Polar Coordinates