Learn on PengiOpenstax Intermediate Algebra 2EChapter 12: Sequences, Series and Binomial Theorem

Lesson 12.4: Binomial Theorem

This lesson from OpenStax Intermediate Algebra 2e covers the Binomial Theorem and its applications, teaching students how to use Pascal's Triangle to find coefficients and expand binomial expressions such as (a + b)^n for any power. Students learn to identify patterns in binomial expansions, including how exponents shift across terms and how coefficients are derived using both Pascal's Triangle and binomial coefficients. The lesson also introduces formal notation for evaluating binomial coefficients as part of a broader study of sequences and series.

Section 1

📘 Binomial Theorem

New Concept

This lesson introduces powerful tools for expanding binomials like (a+b)n(a+b)^n. You'll learn to use Pascal's Triangle and the Binomial Theorem, which uses binomial coefficients (nr)\left(\begin{array}{c} n \\ r \end{array}\right), to find these expansions efficiently.

What’s next

Soon, we'll dive into worked examples for expanding binomials. You'll master these methods through interactive practice and challenge problems.

Section 2

Pascal’s Triangle

Property

Patterns in the expansion of (a+b)n(a + b)^n

  • The number of terms is n+1n + 1.
  • The first term is ana^n and the last term is bnb^n.
  • The exponents on aa decrease by one on each term going left to right.
  • The exponents on bb increase by one on each term going left to right.
  • The sum of the exponents on any term is nn.

Pascal’s Triangle
This triangle gives the coefficients of the terms when we expand binomials. Each number in the array is the sum of the two closest numbers in the row above.

      1
     1 1
    1 2 1
   1 3 3 1
  1 4 6 4 1
 1 5 10 10 5 1

Examples

  • To expand (c+d)4(c+d)^4, we use the row from Pascal's Triangle that starts with 1, 4. The coefficients are 1, 4, 6, 4, 1. The expansion is 1c4+4c3d1+6c2d2+4c1d3+1d4=c4+4c3d+6c2d2+4cd3+d41c^4 + 4c^3d^1 + 6c^2d^2 + 4c^1d^3 + 1d^4 = c^4 + 4c^3d + 6c^2d^2 + 4cd^3 + d^4.

Section 3

Binomial Coefficient

Property

A binomial coefficient (nr)\left(\begin{array}{c} n \\ r \end{array}\right), where rr and nn are integers with 0rn0 \leq r \leq n, is defined as

(nr)=n!r!(nr)!\left(\begin{array}{c} n \\ r \end{array}\right) = \frac{n!}{r!(n - r)!}

We read (nr)\left(\begin{array}{c} n \\ r \end{array}\right) as “nn choose rr” or “nn taken rr at a time”.

Properties of Binomial Coefficients

(n1)=n(nn)=1(n0)=1\left(\begin{array}{c} n \\ 1 \end{array}\right) = n \qquad \left(\begin{array}{c} n \\ n \end{array}\right) = 1 \qquad \left(\begin{array}{c} n \\ 0 \end{array}\right) = 1

Examples

  • To evaluate (61)\left(\begin{array}{c} 6 \\ 1 \end{array}\right), we use the property (n1)=n\left(\begin{array}{c} n \\ 1 \end{array}\right) = n. So, (61)=6\left(\begin{array}{c} 6 \\ 1 \end{array}\right) = 6.

Section 4

Binomial Theorem

Property

For any real numbers aa and bb, and positive integer nn,

(a+b)n=(n0)an+(n1)an1b1+(n2)an2b2++(nr)anrbr++(nn)bn(a + b)^n = \left(\begin{array}{c} n \\ 0 \end{array}\right)a^n + \left(\begin{array}{c} n \\ 1 \end{array}\right)a^{n-1}b^1 + \left(\begin{array}{c} n \\ 2 \end{array}\right)a^{n-2}b^2 + \ldots + \left(\begin{array}{c} n \\ r \end{array}\right)a^{n-r}b^r + \ldots + \left(\begin{array}{c} n \\ n \end{array}\right)b^n

Examples

  • To expand (x+y)3(x+y)^3, we use the theorem: (30)x3+(31)x2y+(32)xy2+(33)y3=1x3+3x2y+3xy2+1y3\left(\begin{array}{c} 3 \\ 0 \end{array}\right)x^3 + \left(\begin{array}{c} 3 \\ 1 \end{array}\right)x^2y + \left(\begin{array}{c} 3 \\ 2 \end{array}\right)xy^2 + \left(\begin{array}{c} 3 \\ 3 \end{array}\right)y^3 = 1x^3 + 3x^2y + 3xy^2 + 1y^3.
  • To expand (a3)4(a-3)^4, we set a=aa=a and b=3b=-3. The expansion is 1(a)4+4(a)3(3)+6(a)2(3)2+4(a)(3)3+1(3)4=a412a3+54a2108a+811(a)^4 + 4(a)^3(-3) + 6(a)^2(-3)^2 + 4(a)(-3)^3 + 1(-3)^4 = a^4 - 12a^3 + 54a^2 - 108a + 81.

Section 5

Finding a Specific Term

Property

The (r+1)(r + 1)st term in the expansion of (a+b)n(a + b)^n is

(nr)anrbr\left(\begin{array}{c} n \\ r \end{array}\right)a^{n - r}b^r

Note that for the (r+1)(r + 1)st term, the exponent of bb is rr.

Examples

  • To find the third term of (a+b)8(a+b)^8, we have n=8n=8. For the third term, r+1=3r+1=3, so r=2r=2. The term is (82)a82b2=28a6b2\left(\begin{array}{c} 8 \\ 2 \end{array}\right)a^{8-2}b^2 = 28a^6b^2.
  • To find the fifth term of (x2)6(x-2)^6, we have n=6,a=x,b=2n=6, a=x, b=-2. For the fifth term, r+1=5r+1=5, so r=4r=4. The term is (64)x64(2)4=15x2(16)=240x2\left(\begin{array}{c} 6 \\ 4 \end{array}\right)x^{6-4}(-2)^4 = 15x^2(16) = 240x^2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

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Chapter 12: Sequences, Series and Binomial Theorem

  1. Lesson 1

    Lesson 12.1: Sequences

  2. Lesson 2

    Lesson 12.2: Arithmetic Sequences

  3. Lesson 3

    Lesson 12.3: Geometric Sequences and Series

  4. Lesson 4Current

    Lesson 12.4: Binomial Theorem

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Binomial Theorem

New Concept

This lesson introduces powerful tools for expanding binomials like (a+b)n(a+b)^n. You'll learn to use Pascal's Triangle and the Binomial Theorem, which uses binomial coefficients (nr)\left(\begin{array}{c} n \\ r \end{array}\right), to find these expansions efficiently.

What’s next

Soon, we'll dive into worked examples for expanding binomials. You'll master these methods through interactive practice and challenge problems.

Section 2

Pascal’s Triangle

Property

Patterns in the expansion of (a+b)n(a + b)^n

  • The number of terms is n+1n + 1.
  • The first term is ana^n and the last term is bnb^n.
  • The exponents on aa decrease by one on each term going left to right.
  • The exponents on bb increase by one on each term going left to right.
  • The sum of the exponents on any term is nn.

Pascal’s Triangle
This triangle gives the coefficients of the terms when we expand binomials. Each number in the array is the sum of the two closest numbers in the row above.

      1
     1 1
    1 2 1
   1 3 3 1
  1 4 6 4 1
 1 5 10 10 5 1

Examples

  • To expand (c+d)4(c+d)^4, we use the row from Pascal's Triangle that starts with 1, 4. The coefficients are 1, 4, 6, 4, 1. The expansion is 1c4+4c3d1+6c2d2+4c1d3+1d4=c4+4c3d+6c2d2+4cd3+d41c^4 + 4c^3d^1 + 6c^2d^2 + 4c^1d^3 + 1d^4 = c^4 + 4c^3d + 6c^2d^2 + 4cd^3 + d^4.

Section 3

Binomial Coefficient

Property

A binomial coefficient (nr)\left(\begin{array}{c} n \\ r \end{array}\right), where rr and nn are integers with 0rn0 \leq r \leq n, is defined as

(nr)=n!r!(nr)!\left(\begin{array}{c} n \\ r \end{array}\right) = \frac{n!}{r!(n - r)!}

We read (nr)\left(\begin{array}{c} n \\ r \end{array}\right) as “nn choose rr” or “nn taken rr at a time”.

Properties of Binomial Coefficients

(n1)=n(nn)=1(n0)=1\left(\begin{array}{c} n \\ 1 \end{array}\right) = n \qquad \left(\begin{array}{c} n \\ n \end{array}\right) = 1 \qquad \left(\begin{array}{c} n \\ 0 \end{array}\right) = 1

Examples

  • To evaluate (61)\left(\begin{array}{c} 6 \\ 1 \end{array}\right), we use the property (n1)=n\left(\begin{array}{c} n \\ 1 \end{array}\right) = n. So, (61)=6\left(\begin{array}{c} 6 \\ 1 \end{array}\right) = 6.

Section 4

Binomial Theorem

Property

For any real numbers aa and bb, and positive integer nn,

(a+b)n=(n0)an+(n1)an1b1+(n2)an2b2++(nr)anrbr++(nn)bn(a + b)^n = \left(\begin{array}{c} n \\ 0 \end{array}\right)a^n + \left(\begin{array}{c} n \\ 1 \end{array}\right)a^{n-1}b^1 + \left(\begin{array}{c} n \\ 2 \end{array}\right)a^{n-2}b^2 + \ldots + \left(\begin{array}{c} n \\ r \end{array}\right)a^{n-r}b^r + \ldots + \left(\begin{array}{c} n \\ n \end{array}\right)b^n

Examples

  • To expand (x+y)3(x+y)^3, we use the theorem: (30)x3+(31)x2y+(32)xy2+(33)y3=1x3+3x2y+3xy2+1y3\left(\begin{array}{c} 3 \\ 0 \end{array}\right)x^3 + \left(\begin{array}{c} 3 \\ 1 \end{array}\right)x^2y + \left(\begin{array}{c} 3 \\ 2 \end{array}\right)xy^2 + \left(\begin{array}{c} 3 \\ 3 \end{array}\right)y^3 = 1x^3 + 3x^2y + 3xy^2 + 1y^3.
  • To expand (a3)4(a-3)^4, we set a=aa=a and b=3b=-3. The expansion is 1(a)4+4(a)3(3)+6(a)2(3)2+4(a)(3)3+1(3)4=a412a3+54a2108a+811(a)^4 + 4(a)^3(-3) + 6(a)^2(-3)^2 + 4(a)(-3)^3 + 1(-3)^4 = a^4 - 12a^3 + 54a^2 - 108a + 81.

Section 5

Finding a Specific Term

Property

The (r+1)(r + 1)st term in the expansion of (a+b)n(a + b)^n is

(nr)anrbr\left(\begin{array}{c} n \\ r \end{array}\right)a^{n - r}b^r

Note that for the (r+1)(r + 1)st term, the exponent of bb is rr.

Examples

  • To find the third term of (a+b)8(a+b)^8, we have n=8n=8. For the third term, r+1=3r+1=3, so r=2r=2. The term is (82)a82b2=28a6b2\left(\begin{array}{c} 8 \\ 2 \end{array}\right)a^{8-2}b^2 = 28a^6b^2.
  • To find the fifth term of (x2)6(x-2)^6, we have n=6,a=x,b=2n=6, a=x, b=-2. For the fifth term, r+1=5r+1=5, so r=4r=4. The term is (64)x64(2)4=15x2(16)=240x2\left(\begin{array}{c} 6 \\ 4 \end{array}\right)x^{6-4}(-2)^4 = 15x^2(16) = 240x^2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 12: Sequences, Series and Binomial Theorem

  1. Lesson 1

    Lesson 12.1: Sequences

  2. Lesson 2

    Lesson 12.2: Arithmetic Sequences

  3. Lesson 3

    Lesson 12.3: Geometric Sequences and Series

  4. Lesson 4Current

    Lesson 12.4: Binomial Theorem