Learn on PengiReveal Math, Course 3Module 10: Volume

Lesson 10-2: Volume of Cones

In this Grade 8 lesson from Reveal Math, Course 3 (Module 10: Volume), students learn how to calculate the volume of a cone using the formula V = ⅓πr²h, building on the relationship that a cone's volume is one-third that of a cylinder with the same base and height. Students practice applying the formula given a cone's radius or diameter and height, including real-world problems such as finding the volume of a cone-shaped paper cup. The lesson also challenges students to compare the volumes of cylindrical and conical containers to solve cost-based problems.

Section 1

Relationship Between Cone and Cylinder Volumes

Property

A cone has exactly one-third the volume of a cylinder with the same base and height: Vcone=13VcylinderV_{cone} = \frac{1}{3} \cdot V_{cylinder}

If cylinder volume is Vcylinder=πr2hV_{cylinder} = \pi r^2 h, then cone volume is Vcone=13πr2hV_{cone} = \frac{1}{3}\pi r^2 h

Section 2

Volume of a Cone Using Base Area

Property

The volume VV of a cone is one-third the product of its base area BB and its perpendicular height hh.

V=13BhV = \frac{1}{3}Bh

Section 3

Volume of a Cone

Property

A cone is a three-dimensional shape with a circular base and an apex. The volume of a right circular cone is one-third the product of the area of the base and the height. If the height is hh and the radius of the base is rr, then V=13πr2hV = \frac{1}{3} \pi r^2 h.

Examples

  • A party hat is a cone with a height of 8 inches and a base radius of 3 inches. Its volume is V=13π(32)(8)=24πV = \frac{1}{3} \pi (3^2)(8) = 24\pi cubic inches.
  • A cylinder has a volume of 9090 cubic cm. A cone with the same base and height would have a volume of V=13(90)=30V = \frac{1}{3} (90) = 30 cubic cm.
  • An hourglass cone holds 15π15\pi cubic inches of sand and has a base radius of 3 inches. Its height is found by solving 15π=13π(32)h15\pi = \frac{1}{3} \pi (3^2)h, which gives h=5h=5 inches.

Explanation

A cone's volume is directly related to a cylinder's. For a cone and cylinder with the same base radius and height, the cone's volume is exactly one-third of the cylinder's. You could fit three full cones of water into one cylinder.

Book overview

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Module 10: Volume

  1. Lesson 1

    Lesson 10-1: Volume of Cylinders

  2. Lesson 2Current

    Lesson 10-2: Volume of Cones

  3. Lesson 3

    Lesson 10-3: Volume of Spheres

  4. Lesson 4

    Lesson 10-4: Find Missing Dimensions

  5. Lesson 5

    Lesson 10-5: Volume of Composite Solids

Lesson overview

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Section 1

Relationship Between Cone and Cylinder Volumes

Property

A cone has exactly one-third the volume of a cylinder with the same base and height: Vcone=13VcylinderV_{cone} = \frac{1}{3} \cdot V_{cylinder}

If cylinder volume is Vcylinder=πr2hV_{cylinder} = \pi r^2 h, then cone volume is Vcone=13πr2hV_{cone} = \frac{1}{3}\pi r^2 h

Section 2

Volume of a Cone Using Base Area

Property

The volume VV of a cone is one-third the product of its base area BB and its perpendicular height hh.

V=13BhV = \frac{1}{3}Bh

Section 3

Volume of a Cone

Property

A cone is a three-dimensional shape with a circular base and an apex. The volume of a right circular cone is one-third the product of the area of the base and the height. If the height is hh and the radius of the base is rr, then V=13πr2hV = \frac{1}{3} \pi r^2 h.

Examples

  • A party hat is a cone with a height of 8 inches and a base radius of 3 inches. Its volume is V=13π(32)(8)=24πV = \frac{1}{3} \pi (3^2)(8) = 24\pi cubic inches.
  • A cylinder has a volume of 9090 cubic cm. A cone with the same base and height would have a volume of V=13(90)=30V = \frac{1}{3} (90) = 30 cubic cm.
  • An hourglass cone holds 15π15\pi cubic inches of sand and has a base radius of 3 inches. Its height is found by solving 15π=13π(32)h15\pi = \frac{1}{3} \pi (3^2)h, which gives h=5h=5 inches.

Explanation

A cone's volume is directly related to a cylinder's. For a cone and cylinder with the same base radius and height, the cone's volume is exactly one-third of the cylinder's. You could fit three full cones of water into one cylinder.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Module 10: Volume

  1. Lesson 1

    Lesson 10-1: Volume of Cylinders

  2. Lesson 2Current

    Lesson 10-2: Volume of Cones

  3. Lesson 3

    Lesson 10-3: Volume of Spheres

  4. Lesson 4

    Lesson 10-4: Find Missing Dimensions

  5. Lesson 5

    Lesson 10-5: Volume of Composite Solids