Learn on PengiBig Ideas Math, Course 2, AcceleratedChapter 5: Volume and Similar Solids

Lesson 1: Volumes of Cylinders

Property.

Section 1

The Height and Volume of Cylinders

Property

A cylinder is a solid figure with two parallel circular bases of the same size. For a cylinder with radius rr and height hh:

Volume: V=πr2hV = \pi r^2 h or V=BhV = Bh (where BB is the area of the base)

Section 2

Solving for a Missing Dimension

Property

To find a missing dimension of a cylinder, rearrange the volume formula V=πr2hV = \pi r^2 h.

  • To find the height (hh):
    h=Vπr2h = \frac{V}{\pi r^2}
  • To find the radius (rr):
    r=Vπhr = \sqrt{\frac{V}{\pi h}}

Examples

Section 3

Converting Volume Units

Property

To convert between units of volume, you must cube the linear unit conversion factor. If the linear conversion is 1 unit A=k unit B1 \text{ unit A} = k \text{ unit B}, then the volume conversion is:

1 unit A3=k3 unit B31 \text{ unit A}^3 = k^3 \text{ unit B}^3

Examples

Book overview

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Chapter 5: Volume and Similar Solids

  1. Lesson 1Current

    Lesson 1: Volumes of Cylinders

  2. Lesson 2

    Lesson 2: Volumes of Cones

  3. Lesson 3

    Lesson 3: Volumes of Spheres

  4. Lesson 4

    Lesson 4: Surface Areas and Volumes of Similar Solids

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

The Height and Volume of Cylinders

Property

A cylinder is a solid figure with two parallel circular bases of the same size. For a cylinder with radius rr and height hh:

Volume: V=πr2hV = \pi r^2 h or V=BhV = Bh (where BB is the area of the base)

Section 2

Solving for a Missing Dimension

Property

To find a missing dimension of a cylinder, rearrange the volume formula V=πr2hV = \pi r^2 h.

  • To find the height (hh):
    h=Vπr2h = \frac{V}{\pi r^2}
  • To find the radius (rr):
    r=Vπhr = \sqrt{\frac{V}{\pi h}}

Examples

Section 3

Converting Volume Units

Property

To convert between units of volume, you must cube the linear unit conversion factor. If the linear conversion is 1 unit A=k unit B1 \text{ unit A} = k \text{ unit B}, then the volume conversion is:

1 unit A3=k3 unit B31 \text{ unit A}^3 = k^3 \text{ unit B}^3

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Volume and Similar Solids

  1. Lesson 1Current

    Lesson 1: Volumes of Cylinders

  2. Lesson 2

    Lesson 2: Volumes of Cones

  3. Lesson 3

    Lesson 3: Volumes of Spheres

  4. Lesson 4

    Lesson 4: Surface Areas and Volumes of Similar Solids